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Concept explainers
(a)
Interpretation:
Interpret the shape of the molecule consists of central atom having 4 electron group and 2 bonded atoms.
Concept Introduction:
The shape of a molecule can be determined with the help of VSEPR model in which Lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.
The shape of molecule is decided by counting the lone pair of electrons along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:
Bond pair | Lone pair | Geometry of molecule |
2 | 0 | Linear |
3 | 0 | Trigonal planar |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
3 | 1 | Trigonal pyramidal |
2 | 2 | Bent |
5 | 0 | Trigonal bipyramidal |
4 | 1 | See saw |
3 | 2 | T shaped |
2 | 3 | Linear |
6 | 0 | Octahedral |
4 | 2 | Square planar |
(b)
Interpretation:
Interpret the shape of the molecule consists of central atom having 4 electron group and 2 bonded atoms.
Concept Introduction:
The shape of a molecule can be determined with the help of VSEPR model in which Lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.
The shape of molecule is decided by counting the lone pair of electrons along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:
Bond pair | Lone pair | Geometry of molecule |
2 | 0 | Linear |
3 | 0 | Trigonal planar |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
3 | 1 | Trigonal pyramidal |
2 | 2 | Bent |
5 | 0 | Trigonal bipyramidal |
4 | 1 | See saw |
3 | 2 | T shaped |
2 | 3 | Linear |
6 | 0 | Octahedral |
4 | 2 | Square planar |
(c)
Interpretation:
Interpret the shape of the molecule consists of central atom having 4 electron group and 2 bonded atoms.
Concept Introduction:
The shape of a molecule can be determined with the help of VSEPR model in which Lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.
The shape of molecule is decided by counting the lone pair of electrons along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:
Bond pair | Lone pair | Geometry of molecule |
2 | 0 | Linear |
3 | 0 | Trigonal planar |
2 | 1 | Bent |
4 | 0 | Tetrahedral |
3 | 1 | Trigonal pyramidal |
2 | 2 | Bent |
5 | 0 | Trigonal bipyramidal |
4 | 1 | See saw |
3 | 2 | T shaped |
2 | 3 | Linear |
6 | 0 | Octahedral |
4 | 2 | Square planar |
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Chapter 10 Solutions
Basic Chemistry (5th Edition)
- Step 1: add a curved arrow. Select Draw Templates More / " C H Br 0 Br : :o: Erase H H H H Q2Q Step 2: Draw the intermediates and a curved arrow. Select Draw Templates More MacBook Air / " C H Br 0 9 Q Erase 2Qarrow_forwardO Macmillan Learning Question 23 of 26 > Stacked Step 7: Check your work. Does your synthesis strategy give a substitution reaction with the expected regiochemistry and stereochemistry? Draw the expected product of the forward reaction. - - CN DMF MacBook Air Clearly show stereochemistry. Questionarrow_forwardNH2 1. CH3–MgCl 2. H3O+ ? As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new C - C bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new C - C bond. Х ☐: Carrow_forward
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