Basic Chemistry (5th Edition)
Basic Chemistry (5th Edition)
5th Edition
ISBN: 9780134138046
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 10.3, Problem 10.13QAP
Interpretation Introduction

(a)

Interpretation:

Interpret the shape of the molecule consists of central atom having 4 electron group and 4 bonded atom.

Concept Introduction:

The shape of a molecule can be determined with the help of VSEPR model in which lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.

The shape of molecule is decided by counting the lone pair of electron along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:

    Bond pair Lone pair Geometry of molecule
    2 0 Linear
    3 0 Trigonal planar
    2 1 Bent
    4 0 Tetrahedral
    3 1 Trigonal pyramidal
    2 2 Bent
    5 0 Trigonal bipyramidal
    4 1 See saw
    3 2 T shaped
    2 3 Linear
    6 0 Octahedral
    4 2 Square planar

Interpretation Introduction

(b)

Interpretation:

Interpret the shape of the molecule consists of central atom having 4 electron group and 3 bonded atom.

Concept Introduction:

The shape of a molecule can be determined with the help of VSEPR model in which lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.

The shape of molecule is decided by counting the lone pair of electron along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:

    Bond pair Lone pair Geometry of molecule
    2 0 Linear
    3 0 Trigonal planar
    2 1 Bent
    4 0 Tetrahedral
    3 1 Trigonal pyramidal
    2 2 Bent
    5 0 Trigonal bipyramidal
    4 1 See saw
    3 2 T shaped
    2 3 Linear
    6 0 Octahedral
    4 2 Square planar

Interpretation Introduction

(c)

Interpretation:

Interpret the shape of the molecule consists of central atom having 3 electron group and 3 bonded atom.

Concept Introduction:

The shape of a molecule can be determined with the help of VSEPR model in which lewis structure of the molecule is drawn which shows the arrangement of surrounding atoms around the central atom.

The shape of molecule is decided by counting the lone pair of electron along with bond pair and thus the shape of molecule is decided. Shape of molecule can be decided as:

    Bond pair Lone pair Geometry of molecule
    2 0 Linear
    3 0 Trigonal planar
    2 1 Bent
    4 0 Tetrahedral
    3 1 Trigonal pyramidal
    2 2 Bent
    5 0 Trigonal bipyramidal
    4 1 See saw
    3 2 T shaped
    2 3 Linear
    6 0 Octahedral
    4 2 Square planar

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Chapter 10 Solutions

Basic Chemistry (5th Edition)

Ch. 10.2 - Draw resonance structures for each of the...Ch. 10.2 - Prob. 10.12QAPCh. 10.3 - Prob. 10.13QAPCh. 10.3 - 10.14 Choose the shape (1 to 6) that matches each...Ch. 10.3 - Prob. 10.15QAPCh. 10.3 - Prob. 10.16QAPCh. 10.3 - Prob. 10.17QAPCh. 10.3 - Prob. 10.18QAPCh. 10.3 - Use VSEPR theory to predict the shape of each of...Ch. 10.3 - Prob. 10.20QAPCh. 10.3 - Prob. 10.21QAPCh. 10.3 - Draw the Lewis structure and predict the shape for...Ch. 10.4 - Describe the trend in electronegativity as...Ch. 10.4 - Prob. 10.24QAPCh. 10.4 - Prob. 10.25QAPCh. 10.4 - Prob. 10.26QAPCh. 10.4 - Prob. 10.27QAPCh. 10.4 - Prob. 10.28QAPCh. 10.4 - Prob. 10.29QAPCh. 10.4 - Prob. 10.30QAPCh. 10.4 - Prob. 10.31QAPCh. 10.4 - Prob. 10.32QAPCh. 10.5 - Prob. 10.33QAPCh. 10.5 - Prob. 10.34QAPCh. 10.5 - Prob. 10.35QAPCh. 10.5 - Prob. 10.36QAPCh. 10.5 - Prob. 10.37QAPCh. 10.5 - Prob. 10.38QAPCh. 10.6 - Prob. 10.39QAPCh. 10.6 - Prob. 10.40QAPCh. 10.6 - Prob. 10.41QAPCh. 10.6 - Prob. 10.42QAPCh. 10.6 - Prob. 10.43QAPCh. 10.6 - Prob. 10.44QAPCh. 10.7 - 10.45 Using Figure 10.6, calculate the heat change...Ch. 10.7 - 10.46 Using Figure 10.6, calculate the heat change...Ch. 10.7 - 10.47 Using Figure 10.6. calculate the heat change...Ch. 10.7 - 10.48 Using Figure 10.6. calculate the heat change...Ch. 10.7 - 10.49 Using Figure 10.6 and the specific heat of...Ch. 10.7 - 10.50 Using Figure 10.6 and the specific heal of...Ch. 10.7 - 10.51 An ice bag containing 275 g of ice at 0°C...Ch. 10.7 - Prob. 10.52QAPCh. 10 - Prob. 10.53FUCh. 10 - Prob. 10.54FUCh. 10 - Prob. 10.55FUCh. 10 - Prob. 10.56FUCh. 10 - Prob. 10.57FUCh. 10 - Prob. 10.58FUCh. 10 - Prob. 10.59UTCCh. 10 - Prob. 10.60UTCCh. 10 - Prob. 10.61UTCCh. 10 - Prob. 10.62UTCCh. 10 - Prob. 10.63UTCCh. 10 - Prob. 10.64UTCCh. 10 - Prob. 10.65UTCCh. 10 - Prob. 10.66UTCCh. 10 - 10.67 Use your knowledge of changes of state to...Ch. 10 - Prob. 10.68UTCCh. 10 - Prob. 10.69UTCCh. 10 - Prob. 10.70UTCCh. 10 - Prob. 10.71UTCCh. 10 - Prob. 10.72UTCCh. 10 - Prob. 10.73AQAPCh. 10 - Prob. 10.74AQAPCh. 10 - Prob. 10.75AQAPCh. 10 - Prob. 10.76AQAPCh. 10 - Prob. 10.77AQAPCh. 10 - Prob. 10.78AQAPCh. 10 - Prob. 10.79AQAPCh. 10 - Prob. 10.80AQAPCh. 10 - Prob. 10.81AQAPCh. 10 - Prob. 10.82AQAPCh. 10 - Prob. 10.83AQAPCh. 10 - Prob. 10.84AQAPCh. 10 - Prob. 10.85AQAPCh. 10 - Prob. 10.86AQAPCh. 10 - Prob. 10.87AQAPCh. 10 - Prob. 10.88AQAPCh. 10 - Prob. 10.89AQAPCh. 10 - Prob. 10.90AQAPCh. 10 - Prob. 10.91AQAPCh. 10 - Prob. 10.92AQAPCh. 10 - Prob. 10.93AQAPCh. 10 - Prob. 10.94AQAPCh. 10 - Indicate the major type of intermolecular...Ch. 10 - Prob. 10.96AQAPCh. 10 - Prob. 10.97AQAPCh. 10 - Prob. 10.98AQAPCh. 10 - Prob. 10.99AQAPCh. 10 - Prob. 10.100AQAPCh. 10 - Prob. 10.101AQAPCh. 10 - Prob. 10.102AQAPCh. 10 - Prob. 10.103CQCh. 10 - Prob. 10.104CQCh. 10 - Prob. 10.105CQCh. 10 - Prob. 10.106CQCh. 10 - Prob. 10.107CQCh. 10 - Prob. 10.108CQCh. 10 - Prob. 10.109CQCh. 10 - Prob. 10.110CQCh. 10 - Prob. 10.111CQCh. 10 - Prob. 10.112CQCh. 10 - Prob. 13CICh. 10 - Prob. 14CICh. 10 - Prob. 15CICh. 10 - Prob. 16CI
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