Pearson eText for College Algebra and Trigonometry -- Instant Access (Pearson+)
4th Edition
ISBN: 9780137399048
Author: J. S. Ratti, Marcus McWaters
Publisher: PEARSON+
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 10.2, Problem 71E
Solar heating. A parabolic reflector mirror is to be used for the solar heating of water. The mirror is 18 feet across and 6 feet deep. Where should the heating element be placed to heat the water most rapidly?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
I want a mathematical relationship with all the details, not explanations and definitions
4 sinx cos2x+4 cos x sin2x-1=0
For the matrix A, find (if possible) a nonsingular matrix P such that P-1AP is diagonal. (If not possible, enter IMPOSSIBLE.)
6 -2
-[47]
A =
-3 1
P =
Verify that P-1AP is a diagonal matrix with the eigenvalues on the main diagonal.
P-1AP =
Chapter 10 Solutions
Pearson eText for College Algebra and Trigonometry -- Instant Access (Pearson+)
Ch. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10E
Ch. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.2 - Prob. 35ECh. 10.2 - Prob. 36ECh. 10.2 - Prob. 37ECh. 10.2 - Prob. 38ECh. 10.2 - Prob. 39ECh. 10.2 - Prob. 40ECh. 10.2 - Prob. 41ECh. 10.2 - Prob. 42ECh. 10.2 - Prob. 43ECh. 10.2 - Prob. 44ECh. 10.2 - Prob. 45ECh. 10.2 - Prob. 46ECh. 10.2 - Prob. 47ECh. 10.2 - Prob. 48ECh. 10.2 - Prob. 49ECh. 10.2 - Prob. 50ECh. 10.2 - Prob. 51ECh. 10.2 - Prob. 52ECh. 10.2 - Prob. 53ECh. 10.2 - Prob. 54ECh. 10.2 - Prob. 55ECh. 10.2 - Prob. 56ECh. 10.2 - Prob. 57ECh. 10.2 - Prob. 58ECh. 10.2 - Prob. 59ECh. 10.2 - Prob. 60ECh. 10.2 - Prob. 61ECh. 10.2 - Prob. 62ECh. 10.2 - Prob. 63ECh. 10.2 - Prob. 64ECh. 10.2 - Prob. 65ECh. 10.2 - Prob. 66ECh. 10.2 - Prob. 67ECh. 10.2 - Prob. 68ECh. 10.2 - Prob. 69ECh. 10.2 - Prob. 70ECh. 10.2 - Solar heating. A parabolic reflector mirror is to...Ch. 10.2 - Prob. 72ECh. 10.2 - Flashlight. The shape of a parabolic flashlight...Ch. 10.2 - Flashlight. Repeat Exercise 73, assuming that the...Ch. 10.2 - Satellite dish. The of a parabolic satellite dish...Ch. 10.2 - Prob. 76ECh. 10.2 - Prob. 77ECh. 10.2 - Prob. 78ECh. 10.2 - Prob. 79ECh. 10.2 - Prob. 80ECh. 10.2 - Prob. 81ECh. 10.2 - Prob. 82ECh. 10.2 - Prob. 83ECh. 10.2 - Prob. 84ECh. 10.2 - Prob. 85ECh. 10.2 - Prob. 86ECh. 10.2 - Prob. 87ECh. 10.2 - Prob. 88ECh. 10.2 - Prob. 89ECh. 10.2 - Prob. 90ECh. 10.2 - Prob. 91ECh. 10.2 - Prob. 92ECh. 10.2 - Prob. 93ECh. 10.2 - Prob. 94ECh. 10.2 - Prob. 95ECh. 10.2 - Prob. 96ECh. 10.2 - Prob. 97ECh. 10.2 - Prob. 98ECh. 10.2 - Prob. 99ECh. 10.2 - Prob. 100ECh. 10.2 - Prob. 101ECh. 10.2 - Prob. 102ECh. 10.2 - Prob. 103ECh. 10.2 - Prob. 104ECh. 10.2 - Prob. 105ECh. 10.2 - Prob. 106ECh. 10.2 - Prob. 107ECh. 10.2 - Prob. 108ECh. 10.2 - Prob. 109ECh. 10.2 - Prob. 110ECh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - 5. True or False. The ellipse lies inside the box...Ch. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - In Exercises 23—42, find the vertices and foci for...Ch. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.3 - Prob. 48ECh. 10.3 - Prob. 49ECh. 10.3 - Prob. 50ECh. 10.3 - Prob. 51ECh. 10.3 - Prob. 52ECh. 10.3 - Prob. 53ECh. 10.3 - Prob. 54ECh. 10.3 - Prob. 55ECh. 10.3 - Prob. 56ECh. 10.3 - Prob. 57ECh. 10.3 - Prob. 58ECh. 10.3 - Prob. 59ECh. 10.3 - Prob. 60ECh. 10.3 - Prob. 61ECh. 10.3 - Prob. 62ECh. 10.3 - Prob. 63ECh. 10.3 - Prob. 64ECh. 10.3 - Prob. 65ECh. 10.3 - Prob. 66ECh. 10.3 - Prob. 67ECh. 10.3 - Prob. 68ECh. 10.3 - Prob. 69ECh. 10.3 - Prob. 70ECh. 10.3 - Prob. 71ECh. 10.3 - Prob. 72ECh. 10.3 - Prob. 73ECh. 10.3 - Prob. 74ECh. 10.3 - Prob. 75ECh. 10.3 - Prob. 76ECh. 10.3 - Prob. 77ECh. 10.3 - Prob. 78ECh. 10.3 - Prob. 79ECh. 10.3 - Prob. 80ECh. 10.3 - Prob. 81ECh. 10.3 - Prob. 82ECh. 10.3 - Prob. 83ECh. 10.3 - Prob. 84ECh. 10.3 - Prob. 85ECh. 10.3 - Prob. 86ECh. 10.3 - Prob. 87ECh. 10.3 - Prob. 88ECh. 10.3 - Prob. 89ECh. 10.3 - Prob. 90ECh. 10.3 - Prob. 91ECh. 10.3 - Prob. 92ECh. 10.3 - Prob. 93ECh. 10.3 - Prob. 94ECh. 10.3 - Prob. 95ECh. 10.3 - Prob. 96ECh. 10.3 - Prob. 97ECh. 10.3 - Prob. 98ECh. 10.3 - Prob. 99ECh. 10.3 - Prob. 100ECh. 10.3 - Prob. 101ECh. 10.3 - Prob. 102ECh. 10.3 - Prob. 103ECh. 10.3 - Prob. 104ECh. 10.3 - Prob. 105ECh. 10.3 - Prob. 106ECh. 10.3 - Prob. 107ECh. 10.3 - Prob. 108ECh. 10.3 - Prob. 109ECh. 10.3 - Prob. 110ECh. 10.3 - Prob. 111ECh. 10.3 - Prob. 112ECh. 10.3 - Prob. 113ECh. 10.3 - Prob. 114ECh. 10.3 - Prob. 115ECh. 10.3 - Prob. 116ECh. 10.3 - Prob. 117ECh. 10.3 - Prob. 118ECh. 10.3 - Prob. 119ECh. 10.3 - Prob. 120ECh. 10.3 - Prob. 121ECh. 10.3 - Prob. 122ECh. 10.3 - Prob. 123ECh. 10.3 - Prob. 124ECh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - In Exercises 17-28, the equation of a hyperbola is...Ch. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.4 - Prob. 36ECh. 10.4 - Prob. 37ECh. 10.4 - Prob. 38ECh. 10.4 - Prob. 39ECh. 10.4 - Prob. 40ECh. 10.4 - Prob. 41ECh. 10.4 - Prob. 42ECh. 10.4 - Prob. 43ECh. 10.4 - Prob. 44ECh. 10.4 - Prob. 45ECh. 10.4 - Prob. 46ECh. 10.4 - Prob. 47ECh. 10.4 - Prob. 48ECh. 10.4 - Prob. 49ECh. 10.4 - Prob. 50ECh. 10.4 - Prob. 51ECh. 10.4 - Prob. 52ECh. 10.4 - Prob. 53ECh. 10.4 - Prob. 54ECh. 10.4 - Prob. 55ECh. 10.4 - Prob. 56ECh. 10.4 - Prob. 57ECh. 10.4 - Prob. 58ECh. 10.4 - Prob. 59ECh. 10.4 - Prob. 60ECh. 10.4 - Prob. 61ECh. 10.4 - Prob. 62ECh. 10.4 - Prob. 63ECh. 10.4 - Prob. 64ECh. 10.4 - Prob. 65ECh. 10.4 - Prob. 66ECh. 10.4 - Prob. 67ECh. 10.4 - Prob. 68ECh. 10.4 - Prob. 69ECh. 10.4 - Prob. 70ECh. 10.4 - Prob. 71ECh. 10.4 - Prob. 72ECh. 10.4 - Prob. 73ECh. 10.4 - Prob. 74ECh. 10.4 - Prob. 75ECh. 10.4 - Prob. 76ECh. 10.4 - Prob. 77ECh. 10.4 - Prob. 78ECh. 10.4 - Prob. 79ECh. 10.4 - Prob. 80ECh. 10.4 - Prob. 81ECh. 10.4 - Prob. 82ECh. 10.4 - Prob. 83ECh. 10.4 - Prob. 84ECh. 10.4 - Prob. 85ECh. 10.4 - Using LORAN. LORAN navigational transmitters A, B,...Ch. 10.4 - Prob. 87ECh. 10.4 - Prob. 88ECh. 10.4 - Prob. 89ECh. 10.4 - Prob. 90ECh. 10.4 - Prob. 91ECh. 10.4 - Prob. 92ECh. 10.4 - Prob. 93ECh. 10.4 - Prob. 94ECh. 10.4 - Prob. 95ECh. 10.4 - Prob. 96ECh. 10.4 - Prob. 97ECh. 10.4 - Prob. 98ECh. 10.4 - Prob. 99ECh. 10.4 - Prob. 100ECh. 10.4 - Prob. 101ECh. 10.4 - Prob. 102ECh. 10.4 - Prob. 103ECh. 10.4 - Prob. 104ECh. 10.4 - Prob. 105ECh. 10.4 - Prob. 106ECh. 10.4 - Prob. 107ECh. 10.4 - Prob. 108ECh. 10.4 - Prob. 109ECh. 10.4 - Prob. 110ECh. 10.4 - Prob. 111ECh. 10.4 - Prob. 112ECh. 10.4 - Prob. 113ECh. 10.4 - Prob. 114ECh. 10.4 - Explain why each of the following represents a...Ch. 10.4 - Prob. 116ECh. 10.4 - Prob. 117ECh. 10.4 - Prob. 118ECh. 10.4 - Prob. 119ECh. 10.4 - Prob. 120ECh. 10.4 - Prob. 121ECh. 10.4 - Prob. 122ECh. 10.4 - Prob. 123ECh. 10.4 - Prob. 124ECh. 10.4 - Prob. 125ECh. 10.4 - Prob. 126ECh. 10.4 - Prob. 127ECh. 10.4 - Prob. 128ECh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - In Exercises 21-24, find an equation of the...Ch. 10 - Prob. 24RECh. 10 - Prob. 25RECh. 10 - Prob. 26RECh. 10 - Prob. 27RECh. 10 - Prob. 28RECh. 10 - Prob. 29RECh. 10 - Prob. 30RECh. 10 - Prob. 31RECh. 10 - Prob. 32RECh. 10 - Prob. 33RECh. 10 - In Exercises 33-36, find an equation of the...Ch. 10 - Prob. 35RECh. 10 - Prob. 36RECh. 10 - Prob. 37RECh. 10 - Prob. 38RECh. 10 - Prob. 39RECh. 10 - Prob. 40RECh. 10 - Prob. 41RECh. 10 - Prob. 42RECh. 10 - Prob. 43RECh. 10 - Prob. 44RECh. 10 - Prob. 45RECh. 10 - Prob. 46RECh. 10 - Prob. 47RECh. 10 - Prob. 48RECh. 10 - Prob. 49RECh. 10 - Prob. 50RECh. 10 - Prob. 51RECh. 10 - Prob. 52RECh. 10 - Prob. 53RECh. 10 - Prob. 54RECh. 10 - Prob. 55RECh. 10 - Parabolic arch. A parabolic arch has a height of...Ch. 10 - Prob. 57RECh. 10 - Prob. 58RECh. 10 - Prob. 1PTACh. 10 - Prob. 2PTACh. 10 - Prob. 3PTACh. 10 - Prob. 4PTACh. 10 - Prob. 5PTACh. 10 - Prob. 6PTACh. 10 - Prob. 7PTACh. 10 - Prob. 8PTACh. 10 - Prob. 9PTACh. 10 - Prob. 10PTACh. 10 - Prob. 11PTACh. 10 - Prob. 12PTACh. 10 - Prob. 13PTACh. 10 - Prob. 14PTACh. 10 - Prob. 15PTACh. 10 - Prob. 16PTACh. 10 - Prob. 17PTACh. 10 - Prob. 18PTACh. 10 - Prob. 19PTACh. 10 - Prob. 20PTACh. 10 - Prob. 1PTBCh. 10 - Prob. 2PTBCh. 10 - Prob. 3PTBCh. 10 - Prob. 4PTBCh. 10 - Prob. 5PTBCh. 10 - Prob. 6PTBCh. 10 - Prob. 7PTBCh. 10 - Prob. 8PTBCh. 10 - Prob. 9PTBCh. 10 - Prob. 10PTBCh. 10 - Prob. 11PTBCh. 10 - Prob. 12PTBCh. 10 - Prob. 13PTBCh. 10 - Prob. 14PTBCh. 10 - Prob. 15PTBCh. 10 - Prob. 16PTBCh. 10 - Prob. 17PTBCh. 10 - Prob. 18PTBCh. 10 - Prob. 19PTBCh. 10 - Prob. 20PTBCh. 10 - Prob. 1CRECh. 10 - Prob. 2CRECh. 10 - Prob. 3CRECh. 10 - Prob. 4CRECh. 10 - Prob. 5CRECh. 10 - Prob. 6CRECh. 10 - Prob. 7CRECh. 10 - Prob. 8CRECh. 10 - Prob. 9CRECh. 10 - Prob. 10CRECh. 10 - Prob. 11CRECh. 10 - Prob. 12CRECh. 10 - Prob. 13CRECh. 10 - Prob. 14CRECh. 10 - Prob. 15CRECh. 10 - Prob. 16CRECh. 10 - Prob. 17CRECh. 10 - Prob. 18CRECh. 10 - In Problems 18-20, an equation of a conic section...Ch. 10 - Prob. 20CRE
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.Similar questions
- (e) Without using a membership table, show that (A N B) U (A N B) = A. State all the rules used.arrow_forwardThe function r has vertical asymptotes x =____________ (smaller value) and x = __________ (larger value)arrow_forwardProblem 1. 1.1. In each of the below, find a complete list of subgroups of the group G and write down their orders. a) The group G = Z/48Z b) The group G of rotations in D14. c) The group G = Z13 of 13-th roots of unity in C. 1.2. Find all elements x of the group G from 1.1 b) which generate G. 1.3. Let H = [[20]) ℃ Z/48Z. Using only order, determine which of the subgroups from your solution to 1.1 a) H coincides with.arrow_forward
- my teacher told me the answer was 4a⁷b⁶ because of the product of a power how can I tell the truth us there any laws in math please provide the law to correct her tyarrow_forwarda=1 b=41)Find the vector and parametric scalar equations of the line L. Show that Q does not lieon L. 2)Without performing any numerical calculations, express d in terms of sin(θ) and |P Q| andhence show that d = |P Q × v(v with a hat)|. Proceed to use your points P and Q and the vector v(hat) to find d. 3)Find the point R such that PR =(P Q · v(hat)/|v(hat)| 2⃗ ) * v(hat). Confirm that R lies on the line L. Interpret the vector P R. Finally, verify that d = |RQ|.arrow_forwardDirections: Use your knowledge of properties of quadratic equations to answer each question. Show all work and label your answers with appropriate units. Round any decimals to the nearest hundredths place. 1. The hypotenuse of a right triangle is 5 centimeters longer than one leg and 10 centimeters longer than the other leg. What are the dimensions of the triangle? 2. The profit of a cell phone manufacturer is found by the function y = -2x²+ 108x+75, where x is the price of the cell phone. At what price should the manufacturer sell the phone to maximize its profits? What will the maximum profit be? 3. A farmer wants to build a fence around a rectangular area of his farm with one side of the region against his barn. He has 76 feet of fencing to use for the three remaining sides. What dimensions will make the largest area for the region? 4. A 13-foot ladder is leaning against a building, forming a right triangle. The height where the ladder touches the building is 7 feet more than the…arrow_forward
- Consider the linear system: x12x2ax3 - 3x1 + x2 3x3 -3x14x2+7x3 a) For what value of a we can not solve the above system using Cramer's Rule? a b) If we take a 3 what will be the value of x₁? x1 = == 4. =-7 ==arrow_forwardIf u and v are any elements in vector space V and u v is not in V then V is not closed under the operation . ○ True ○ Falsearrow_forwardConsider the linear system: x1 + 2x2 + 3x3 3x1 + 2x2 + x3 = 17 = 11 x1 - 5x2 + x3 =-5 Let A be the coefficient matrix of the given system and using Cramer's Rule x = • x1 = = det(A2) = ÷ det(Ai) det(A)arrow_forward
- The linear system can be solved by Cramer's Rule. ○ True ○ False 2x14x26x3 = 2, x1 + 2x3 = 0, 2x13x2 x3 = −5arrow_forwardConsider the linear system: 2x1 +7x2 = -21 -x1-3x2 = = 14 Which one of the following gives the value of x₁ using Cramer's rule? Select one: 21 7 14 -3 x1 = 2 7 -1 -3 -21 7 14 -3 x1 2 7 1 -3 O None of these. -21 -1 14 x1 = 2 7 -1 -3 -21 -1 14 x1 = 2 7 1 -3arrow_forwardWrite the augmented matrix of the system -70y +4z 6 20x +60z -48 -3x -4y-48z -12arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College AlgebraAlgebraISBN:9781305115545Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning
Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage
Algebra and Trigonometry (MindTap Course List)AlgebraISBN:9781305071742Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning
College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
College Algebra
Algebra
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:Cengage Learning
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:Cengage Learning
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
What is a Linear Equation in One Variable?; Author: Don't Memorise;https://www.youtube.com/watch?v=lDOYdBgtnjY;License: Standard YouTube License, CC-BY
Linear Equation | Solving Linear Equations | What is Linear Equation in one variable ?; Author: Najam Academy;https://www.youtube.com/watch?v=tHm3X_Ta_iE;License: Standard YouTube License, CC-BY