Electrical Motor Controls for Integrated Systems
5th Edition
ISBN: 9780826912268
Author: Gary Rockis;Glen A. Mazur
Publisher: American Technical Publishers
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Question
Chapter 10.2, Problem 5CP
To determine
To explain: The type of connection that has equal phase-to-neutral voltage.
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3. As the audio frequency of Fig. 11-7 goes down, what components of Fig.
12-4 must be modified for normal operation?
OD
C₂ 100
HF
R₁ 300
Re 300
ww
100A
R
8
Voc
Rz
10k
reset
output 3
R7
8
Voc
3
reset
output
Z
discharge
VR₁
5k
2
trigger
2 trigger
7
discharge
R 3
1k
5
control
voltage
threshold 6
5 control
voltage
6
threshold
GND
Rs
2k
C.
C.
100
GND
Uz LM555 1
Ce
0.01
U, LM555
0.01
8.01.4
PRO
Fig. 11-7
Audio lutput
Pulse width modulator
R4 1k
ww
C7
Re 1k
ww
R7 100
VR
50k
10μ
Ra
R10
C₁.
R1
3.9k
3.9k
0.14 100k
TO
w
Rs 51
82
3
H
10
Carrier
U₁
Ca
Input
A741
2.2
Us
MC1496
PWM signal
input
R2
0.1100k
Uz
A741
41
Cs
1
Re
10k
VR2
50k
VR3
100k
14
12
C3.
3% +
Ce
0.1
10μ
5
1A
HH
C
+12V
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O PWM
Output
C
0.02-
R
100k +12 V
Demodulated
output
6
Ca
0.33
w
R
10k
R12
100k
ww 31
о
+
4A741
-12 V
Fig. 12-4 PWM demodulator
C
1500p
DUC
1. In Fig. 12-4, what are the functions of the VR1 and VR2?
2. In Fig. 12-4, what is the function of the VR3?
VR₁
50k
C₁ R1
0.1 100k
Carrier
Input
U₁
A741
PWM signal
input
R41k
www
Re 1k
w
C7 ±
10μT
R7 100
ww
=L
H
C4
2.2
H
W82
Rs 51
3
10
U3
MC1496
C2
R2
U2
A741
22
0.1 100k
VR2
50k
VR3
100kr
14
C3
10μ
1k
0.1
4
5
6
12
m
Re
10k
R9 R102
3.9k 3.9k
HHI
C10
0.1
-0
+12V
C11
R
0.02 100k +12 V
Demodulated
output
C
R11
R12
A741
0.33 10k
100k
-12 V
Ca
1μ
C12
1500p
PRODUC
Fig. 12-4 PWM demodulator
PRODUCTS
10.37 Use mesh analysis to find currents I₁, I2, and I3 in
the circuit of Fig. 10.82.
ML
120-90° V
120 -30° V
Figure 10.82
For Prob. 10.37.
N
N
Z=80-135
Chapter 10 Solutions
Electrical Motor Controls for Integrated Systems
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- 3. Find the phasor current I。 in the circuit shown below. Be aware of the direction markings. (15 pts) 1052 I 5057 ①520 Amps 2012 j5052arrow_forward10.93 Figure 10.135 shows a Colpitts oscillator. Show that the ed oscillation frequency is 1 fo= 2π √√LCT where CTC₁C2/(C₁ + C₂). Assume R; >>> R₁ + Rf ww Vo L m C₂ C₁ 5 Xci Figure 10.135 A Colpitts oscillator; for Prob. 10.93. (Hint: Set the imaginary part of the impedance in the feedback circuit equal to zero.)arrow_forwardDetermine (a) the average and (b) rms values of the periodiccurrent waveform shown in Fig. P8.3.arrow_forward
- 10.68 Find the Thevenin equivalent at terminals a-b in the circuit of Fig. 10.111. ML 6 sin 10t V 492 Figure 10.111 For Prob. 10.68. 5913 + 410 + -2 F 20 1H Vo obarrow_forward10.79 For the op amp circuit in Fig. 10.122, obtain Vo. 5 cos 10³t V(+ Figure 10.122 For Prob. 10.79. 10 ΚΩ www 20 ΚΩ www 0.1 µF 40 ΚΩ 0.2 μFarrow_forward10.19 Obtain V, in Fig. 10.68 using nodal analysis. # ML ΖΩ j20 m 12/0° V 492 (+ ww www ' < ་ + V -j4 0.2V Figure 10.68 For Prob. 10.19.arrow_forward
- 10.47 Determine i, in the circuit of Fig. 10.92, using the superposition principle. ML 10 sin(t -30°) V 1Ω www Figure 10.92 For Prob. 10.47. 96 F 202 www 24 V +) 2 H m io 2 cos 3t www 42arrow_forward10.53 Use the concept of source transformation to find V, in the circuit of Fig. 10.97. 492 www -j30 j40 m + 20/0° V(+ j20 ΖΩ www -120 V ° Figure 10.97 For Prob. 10.53.arrow_forward2. Given you have a real valued signal with the following single sided baseband signal spectrum: ↑ ❘m(f)| A f=0 500 750 Sketch the frequency domain of |X(f)| given: a. x1(t) =m(t)cos(2**5000*) b. x2(t)=m(t)cos(2**600) Frequency (Hz)arrow_forward
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