Advanced Engineering Mathematics
6th Edition
ISBN: 9781284105902
Author: Dennis G. Zill
Publisher: Jones & Bartlett Learning
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Chapter 10.2, Problem 3E
To determine
The general solution of the given system.
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2. In a computer network some pairs of computers are connected by network cables.
Your goal is to set up the computers so that messages can be sent quickly from any
computer to any other computer. For this you have identified each of the n com-
puters uniquely with a number between 1 and n, and have decided that a message
should consist of two such numbers, identifying the sender and the recipient, fol-
lowed by the content of the message. As cables are relatively short, you can assume
that sending a message across a single cable takes an amount of time that is the
same irrespective of the length of the cable. You can further assume that at most
one message travels between computer at any point, so that you don't have to worry
about inference among messages.
(a) Define a graph or network that models the computer network and allows you
to answer the remaining parts of this question.
(b) Consider two computers, a sender and a recipient. Using the graph or network
you have defined,…
3. A spreadsheet consists of cells indexed by a row and a column. Each cell contains
either a value or a formula that depends on the values of other cells.
(a) Describe a graph, digraph, or network that models an arbitrary spreadsheet
and allows you to answer the remaining parts of this question.
(b) Explain, by referring to the graph, digraph, or network, when it is possible to
change the value of cell x without changing the value of cell y.
(c) Explain, by referring to the graph, digraph, or network, when it is possible to
calculate the values of all cells in the spreadsheet.
Consider the following spreadsheet with 5 rows, 7 columns, and 35 cells. For exam-
ple, cell el contains a value, whereas cell al contains a formula that depends on the
values cells el and 95.
a
b
с
1
el+g5 al-c5 110
d
al+cl 180
e
f
g
f5-el
c1+c2
2
al+b1 a2+c4 240
a2+c2 120
f5-e2
e3+e5
3 a2+b2 a3-c3 100
a3+c1 200
f5-e3 f1+f2
4
a3+b3 a4+c2 220
a4+c2 100 f5-e4 f3+f4
5 a4+b4 a5-c1 130 a5+c5 120 g3+g4 g1+g2
(d) Can…
1. Let W, U, and S be graphs defined as follows:
• V(W) is the set of countries in the world;
• V(U) is the set of countries in the European Union;
V(S) is the set of countries in the Schengen Area;
● for X = {W,U,S}, E(X) is the set of pairs of countries in V(X) that share a
land border.
Recall that land borders between countries in the Schengen Area are special in that
they can be crossed without a passport.
(a) The notions of a country and a land border are somewhat ambiguous. Explain
the notions you will use to get a precise definition of the graphs W, U, and S.
(b) Is S a subgraph of U? Is U an induced subgraph of W? Justify your answers.
(c) Using non-mathematical language, explain what it means for a country x if
VEV(S) and dw (v) = 0. Give all such countries.
Let A = {v Є V(W) \V(S) such that |Nw(v)| > 0 and Nw (v) ≤ V(S)}.
(d) Using non-mathematical language, explain what the set A represents in terms
of countries and land borders. Give a specific element of A or explain why A…
Chapter 10 Solutions
Advanced Engineering Mathematics
Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10E
Ch. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.2 - Prob. 35ECh. 10.2 - Prob. 36ECh. 10.2 - Prob. 37ECh. 10.2 - Prob. 38ECh. 10.2 - Prob. 39ECh. 10.2 - Prob. 40ECh. 10.2 - Prob. 41ECh. 10.2 - Prob. 42ECh. 10.2 - Prob. 43ECh. 10.2 - Prob. 44ECh. 10.2 - Prob. 45ECh. 10.2 - Prob. 46ECh. 10.2 - Prob. 47ECh. 10.2 - Prob. 48ECh. 10.2 - Prob. 49ECh. 10.2 - Prob. 50ECh. 10.2 - Prob. 51ECh. 10.2 - Prob. 52ECh. 10.2 - Prob. 53ECh. 10.2 - Prob. 55ECh. 10.4 - Prob. 1ECh. 10.4 - Prob. 2ECh. 10.4 - Prob. 3ECh. 10.4 - Prob. 4ECh. 10.4 - Prob. 5ECh. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Prob. 10ECh. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - Prob. 16ECh. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.4 - Prob. 29ECh. 10.4 - Prob. 30ECh. 10.4 - Prob. 31ECh. 10.4 - Prob. 32ECh. 10.4 - Prob. 33ECh. 10.4 - Prob. 34ECh. 10.4 - Prob. 35ECh. 10.5 - Prob. 1ECh. 10.5 - Prob. 2ECh. 10.5 - Prob. 3ECh. 10.5 - Prob. 4ECh. 10.5 - Prob. 5ECh. 10.5 - Prob. 6ECh. 10.5 - Prob. 7ECh. 10.5 - Prob. 8ECh. 10.5 - Prob. 13ECh. 10.5 - Prob. 14ECh. 10.5 - Prob. 15ECh. 10.5 - Prob. 16ECh. 10.5 - Prob. 17ECh. 10.5 - Prob. 18ECh. 10.5 - Prob. 25ECh. 10.5 - Prob. 26ECh. 10 - Prob. 1CRCh. 10 - Prob. 2CRCh. 10 - Prob. 3CRCh. 10 - Prob. 4CRCh. 10 - Prob. 5CRCh. 10 - Prob. 6CRCh. 10 - Prob. 7CRCh. 10 - Prob. 8CRCh. 10 - Prob. 9CRCh. 10 - Prob. 10CRCh. 10 - Prob. 11CRCh. 10 - Prob. 12CRCh. 10 - Prob. 13CRCh. 10 - Prob. 14CRCh. 10 - Prob. 15CRCh. 10 - Prob. 16CR
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