To prove: The general solution of the nonhomogeneous linear system X ′ = ( − 1 − 1 − 1 1 ) X + ( 1 1 ) t 2 + ( 4 − 6 ) t + ( − 1 5 ) on the interval ( − ∞ , ∞ ) is X = c 1 ( 1 − 1 − 2 ) e 2 t + c 2 ( 1 − 1 + 2 ) e − 2 t + ( 1 0 ) t 2 + ( − 2 4 ) t + ( 1 0 ) .

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Answer 1

Question

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

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Answer 2

Question

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

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Answer 3

Question

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

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Answer 4

Question

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

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Answer 5

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

Answer 6

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

Answer 7

Chapter 10.1, Problem 26E

To determine

To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 10.1 - Prob. 1E Ch. 10.1 - Prob. 2E Ch. 10.1 - Prob. 3E Ch. 10.1 - Prob. 4E Ch. 10.1 - Prob. 5E Ch. 10.1 - Prob. 6E Ch. 10.1 - Prob. 7E Ch. 10.1 - Prob. 8E Ch. 10.1 - Prob. 9E Ch. 10.1 - Prob. 10E

To prove: The general solution of the nonhomogeneous linear system X ′ = ( − 1 − 1 − 1 1 ) X + ( 1 1 ) t 2 + ( 4 − 6 ) t + ( − 1 5 ) on the interval ( − ∞ , ∞ ) is X = c 1 ( 1 − 1 − 2 ) e 2 t + c 2 ( 1 − 1 + 2 ) e − 2 t + ( 1 0 ) t 2 + ( − 2 4 ) t + ( 1 0 ) .

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To prove: The general solution of the nonhomogeneous linear system X′=(−1−1−11)X+(11)t2+(4−6)t+(−15) on the interval (−∞,∞) is X=c1(1−1−2)e2t+c2(1−1+2)e−2t+(10)t2+(−24)t+(10).

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Chapter 10 Solutions