Calculus
6th Edition
ISBN: 9781465208880
Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE
Publisher: Kendall Hunt Publishing
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Chapter 10.2, Problem 16PS
To determine
To calculate: the particle’s velocity and acceleration
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At time t = 0, a particle is located at the point (5,9,4). It travels in a straight line to the point (2,1,3), has speed 5 at (5,9,4) and constant acceleration - 3i-8j - k. Find an equation for the position
vector r(t) of the particle at time t.
The equation for the position vector r(t) of the particle at time t is r(t) =
(Type exact answers, using radicals as needed.)
i+
j+ k.
A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 4 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in
feet per second)
Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.)
Take as the gravitational acceleration 32 feet per second per second.
y =
solve question 4 A, B and C
Chapter 10 Solutions
Calculus
Ch. 10.1 - Prob. 1PSCh. 10.1 - Prob. 2PSCh. 10.1 - Prob. 3PSCh. 10.1 - Prob. 4PSCh. 10.1 - Prob. 5PSCh. 10.1 - Prob. 6PSCh. 10.1 - Prob. 7PSCh. 10.1 - Prob. 8PSCh. 10.1 - Prob. 9PSCh. 10.1 - Prob. 10PS
Ch. 10.1 - Prob. 11PSCh. 10.1 - Prob. 12PSCh. 10.1 - Prob. 13PSCh. 10.1 - Prob. 14PSCh. 10.1 - Prob. 15PSCh. 10.1 - Prob. 16PSCh. 10.1 - Prob. 17PSCh. 10.1 - Prob. 18PSCh. 10.1 - Prob. 19PSCh. 10.1 - Prob. 20PSCh. 10.1 - Prob. 21PSCh. 10.1 - Prob. 22PSCh. 10.1 - Prob. 23PSCh. 10.1 - Prob. 24PSCh. 10.1 - Prob. 25PSCh. 10.1 - Prob. 26PSCh. 10.1 - Prob. 27PSCh. 10.1 - Prob. 28PSCh. 10.1 - Prob. 29PSCh. 10.1 - Prob. 30PSCh. 10.1 - Prob. 31PSCh. 10.1 - Prob. 32PSCh. 10.1 - Prob. 33PSCh. 10.1 - Prob. 34PSCh. 10.1 - Prob. 35PSCh. 10.1 - Prob. 36PSCh. 10.1 - Prob. 37PSCh. 10.1 - Prob. 38PSCh. 10.1 - Prob. 39PSCh. 10.1 - Prob. 40PSCh. 10.1 - Prob. 41PSCh. 10.1 - Prob. 42PSCh. 10.1 - Prob. 43PSCh. 10.1 - Prob. 44PSCh. 10.1 - Prob. 45PSCh. 10.1 - Prob. 46PSCh. 10.1 - Prob. 47PSCh. 10.1 - Prob. 48PSCh. 10.1 - Prob. 49PSCh. 10.1 - Prob. 50PSCh. 10.1 - Prob. 51PSCh. 10.1 - Prob. 52PSCh. 10.1 - Prob. 53PSCh. 10.1 - Prob. 54PSCh. 10.1 - Prob. 55PSCh. 10.1 - Prob. 56PSCh. 10.1 - Prob. 57PSCh. 10.1 - Prob. 58PSCh. 10.1 - 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Prob. 37PSCh. 10.3 - Prob. 38PSCh. 10.3 - Prob. 39PSCh. 10.3 - Prob. 40PSCh. 10.3 - Prob. 41PSCh. 10.3 - Prob. 42PSCh. 10.3 - Prob. 43PSCh. 10.3 - Prob. 44PSCh. 10.3 - Prob. 45PSCh. 10.3 - Prob. 46PSCh. 10.3 - Prob. 47PSCh. 10.3 - Prob. 48PSCh. 10.3 - Prob. 49PSCh. 10.3 - Prob. 50PSCh. 10.3 - Prob. 51PSCh. 10.3 - Prob. 52PSCh. 10.3 - Prob. 53PSCh. 10.3 - Prob. 54PSCh. 10.3 - Prob. 55PSCh. 10.3 - Prob. 56PSCh. 10.3 - Prob. 57PSCh. 10.3 - Prob. 58PSCh. 10.3 - Prob. 59PSCh. 10.3 - Prob. 60PSCh. 10.4 - Prob. 1PSCh. 10.4 - Prob. 2PSCh. 10.4 - Prob. 3PSCh. 10.4 - Prob. 4PSCh. 10.4 - Prob. 5PSCh. 10.4 - Prob. 6PSCh. 10.4 - Prob. 7PSCh. 10.4 - Prob. 8PSCh. 10.4 - Prob. 9PSCh. 10.4 - Prob. 10PSCh. 10.4 - Prob. 11PSCh. 10.4 - Prob. 12PSCh. 10.4 - Prob. 13PSCh. 10.4 - Prob. 14PSCh. 10.4 - Prob. 15PSCh. 10.4 - Prob. 16PSCh. 10.4 - Prob. 17PSCh. 10.4 - Prob. 18PSCh. 10.4 - Prob. 19PSCh. 10.4 - Prob. 20PSCh. 10.4 - Prob. 21PSCh. 10.4 - Prob. 22PSCh. 10.4 - Prob. 23PSCh. 10.4 - Prob. 24PSCh. 10.4 - Prob. 25PSCh. 10.4 - 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Prob. 15PSCh. 10.5 - Prob. 16PSCh. 10.5 - Prob. 17PSCh. 10.5 - Prob. 18PSCh. 10.5 - Prob. 19PSCh. 10.5 - Prob. 20PSCh. 10.5 - Prob. 21PSCh. 10.5 - Prob. 22PSCh. 10.5 - Prob. 23PSCh. 10.5 - Prob. 24PSCh. 10.5 - Prob. 25PSCh. 10.5 - Prob. 26PSCh. 10.5 - Prob. 27PSCh. 10.5 - Prob. 28PSCh. 10.5 - Prob. 29PSCh. 10.5 - Prob. 30PSCh. 10.5 - Prob. 31PSCh. 10.5 - Prob. 32PSCh. 10.5 - Prob. 33PSCh. 10.5 - Prob. 34PSCh. 10.5 - Prob. 35PSCh. 10.5 - Prob. 36PSCh. 10.5 - Prob. 37PSCh. 10.5 - Prob. 38PSCh. 10.5 - Prob. 39PSCh. 10.5 - Prob. 40PSCh. 10.5 - Prob. 41PSCh. 10.5 - Prob. 42PSCh. 10.5 - Prob. 43PSCh. 10.5 - Prob. 44PSCh. 10.5 - Prob. 45PSCh. 10.5 - Prob. 46PSCh. 10.5 - Prob. 47PSCh. 10.5 - Prob. 48PSCh. 10.5 - Prob. 49PSCh. 10.5 - Prob. 50PSCh. 10.5 - Prob. 51PSCh. 10.5 - Prob. 52PSCh. 10.5 - Prob. 53PSCh. 10.5 - Prob. 54PSCh. 10.5 - Prob. 55PSCh. 10.5 - Prob. 56PSCh. 10.5 - Prob. 57PSCh. 10.5 - Prob. 58PSCh. 10.5 - Prob. 59PSCh. 10.5 - Prob. 60PSCh. 10 - Prob. 1PECh. 10 - Prob. 2PECh. 10 - 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- A hollow steel ball weighing 4 pounds is suspended from a spring. This stretches the spring feet. The ball is started in motion from the equilibrium position with a downward velocity of 3 feet per second. The air resistance (in pounds) of the moving ball numerically equals 4 times its velocity (in feet per second). Suppose that after t seconds the ball is y feet below its rest position. Find y in terms of t. (Note that the positive direction is down.) Take as the gravitational acceleration 32 feet per second per second. y = Hint: e^(-16t)(((1/(2sqrt(2))*e^(8sqrt(2)t)-(1/(2sqrt(2))*e^(-8sqrt(2)t))arrow_forward13.2.21 Question Help At time t = 0, a particle is located at the point (4,9,7). It travels in a straight line to the point (6,1,1), has speed 7 at (4,9,7) and constant acceleration 21 - 8j – 6k. Find an equation for the position vector r(t) of the particle at time t. The equation for the position vector r(t) of the particle at timet is r(t) = ( Di+ ( Dij+ () k. (Type exact answers, using radicals as needed.) Enter your answer in the edit fields and then click Check Answer. Clear All Check Answer All parts showing Terms of Use Privacy Policy Permissions Contact Us Copyright 2020 Pearson Education InC. All rights reserved. e to search (27arrow_forwardPart 1.Given that the acceleration vector is a(t)=(−16cos(−4t))i+(−16sin(−4t))j+(3t)k the initial velocity is v(0)=i+k, and the initial position vector is r(0)=i+j+k, compute: A. The position vector r(t) B. The velocity vector v(t) Part2.Find the arclength of the curve r(t)=⟨72–√t,e7t,e−7t⟩r(t)=⟨72t,e7t,e−7t⟩, 0≤t≤1arrow_forward
- i need the answer quicklyarrow_forwardplease solve it neat and cleanarrow_forward6. Find the following for the given equation. r(t) = (e−t, 2t2, 8 tan(t)) (a) r'(t) = (b) r''(t) = (c) Find r'(t) · r''(t). 7. The position vector r describes the path of an object moving in space. Find the velocity v(t), speed s(t), and acceleration a(t), of the object. r(t) = (et cos(t), et sin(t), et ) v(t) = s(t) = a(t) =arrow_forward
- 1.) Let s(t)= tlnt-t be the displacement of a particle (in feet) from the origin after t seconds. a.) Find the velocity of the particle at 5 seconds. (Show all your work and include units) b.) Find the acceleration of the particle after 5 seconds. (Show all your work and include units)arrow_forwardSuppose a rock falls from rest from a height of 100 meters and the only force acting on it is gravity. Find an equation for the velocity v(t) as a function of time, measured in meters per second. Hint What is the initial velocity of the rock?arrow_forward1. An object moves in space with acceleration a(t) = 12t²i+6tj+2k. When t 0, the object is at (1, 0, -1) with initial velocity v(0) = 2i - 3k. Find the position vector of the object, r(t).arrow_forward
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