Drive safely: How often does the average driver have an accident? The Allstate Insurance Company determined the average number of years between accidents for drivers in a large number of U.S. cities. Following are the results for 32 cities east of the Mississippi River and 32 cities west of the Mississippi River. Construct a 95% confidence interval for the difference in mean scores between western and eastern cities. An insurance company executive claims that the mean number of years between accidents for western cities is 1.5 years greater than the mean for eastern cities. Does the confidence interval contradict this claim?

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 10.1, Problem 26E

Drive safely: How often does the average driver have an accident? The Allstate Insurance Company determined the average number of years between accidents for drivers in a large number of U.S. cities. Following are the results for 32 cities east of the Mississippi River and 32 cities west of the Mississippi River.

Chapter 10.1, Problem 26E, Drive safely: How often does the average driver have an accident? The Allstate Insurance Company

Construct a 95% confidence interval for the difference in mean scores between western and eastern cities.
An insurance company executive claims that the mean number of years between accidents for western cities is 1.5 years greater than the mean for eastern cities. Does the confidence interval contradict this claim?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

65% of all violent felons in the prison system are repeat offenders. If 43 violent felons are randomly selected, find the probability that a. Exactly 28 of them are repeat offenders. b. At most 28 of them are repeat offenders. c. At least 28 of them are repeat offenders. d. Between 22 and 26 (including 22 and 26) of them are repeat offenders.

08:34 ◄ Classroom 07:59 Probs. 5-32/33 D ا. 89 5-34. Determine the horizontal and vertical components of reaction at the pin A and the normal force at the smooth peg B on the member. A 0,4 m 0.4 m Prob. 5-34 F=600 N fr th ar 0. 163586 5-37. The wooden plank resting between the buildings deflects slightly when it supports the 50-kg boy. This deflection causes a triangular distribution of load at its ends. having maximum intensities of w, and wg. Determine w and wg. each measured in N/m. when the boy is standing 3 m from one end as shown. Neglect the mass of the plank. 0.45 m 3 m

Examine the Variables: Carefully review and note the names of all variables in the dataset. Examples of these variables include: Mileage (mpg) Number of Cylinders (cyl) Displacement (disp) Horsepower (hp) Research: Google to understand these variables. Statistical Analysis: Select mpg variable, and perform the following statistical tests. Once you are done with these tests using mpg variable, repeat the same with hp Mean Median First Quartile (Q1) Second Quartile (Q2) Third Quartile (Q3) Fourth Quartile (Q4) 10th Percentile 70th Percentile Skewness Kurtosis Document Your Results: In RStudio: Before running each statistical test, provide a heading in the format shown at the bottom. “# Mean of mileage – Your name’s command” In Microsoft Word: Once you've completed all tests, take a screenshot of your results in RStudio and paste it into a Microsoft Word document. Make sure that snapshots are very clear. You will need multiple snapshots. Also transfer these results to the…

Answer 2

Textbook Question

Chapter 10.1, Problem 26E

Drive safely: How often does the average driver have an accident? The Allstate Insurance Company determined the average number of years between accidents for drivers in a large number of U.S. cities. Following are the results for 32 cities east of the Mississippi River and 32 cities west of the Mississippi River.

Chapter 10.1, Problem 26E, Drive safely: How often does the average driver have an accident? The Allstate Insurance Company

Construct a 95% confidence interval for the difference in mean scores between western and eastern cities.
An insurance company executive claims that the mean number of years between accidents for western cities is 1.5 years greater than the mean for eastern cities. Does the confidence interval contradict this claim?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 10.1, Problem 26E

Drive safely: How often does the average driver have an accident? The Allstate Insurance Company determined the average number of years between accidents for drivers in a large number of U.S. cities. Following are the results for 32 cities east of the Mississippi River and 32 cities west of the Mississippi River.

Chapter 10.1, Problem 26E, Drive safely: How often does the average driver have an accident? The Allstate Insurance Company

Construct a 95% confidence interval for the difference in mean scores between western and eastern cities.
An insurance company executive claims that the mean number of years between accidents for western cities is 1.5 years greater than the mean for eastern cities. Does the confidence interval contradict this claim?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 10.1, Problem 26E

Drive safely: How often does the average driver have an accident? The Allstate Insurance Company determined the average number of years between accidents for drivers in a large number of U.S. cities. Following are the results for 32 cities east of the Mississippi River and 32 cities west of the Mississippi River.

Chapter 10.1, Problem 26E, Drive safely: How often does the average driver have an accident? The Allstate Insurance Company

Construct a 95% confidence interval for the difference in mean scores between western and eastern cities.
An insurance company executive claims that the mean number of years between accidents for western cities is 1.5 years greater than the mean for eastern cities. Does the confidence interval contradict this claim?

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Answer 8

a.

Expert Solution

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

To find: The 95% confidence interval for the difference in mean scores between western and eastern cities.

Answer 13

Answer to Problem 26E

The 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Answer 14

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

The steps for the confidence interval are,

Import the data, select start and choose the basic statistics option then select the 2 sample t and enter summarized data.

Click option button choose confidence level, test difference and alternative hypothesis and then click ok.

The data is shown below.

Elementary Statistics (Text Only), Chapter 10.1, Problem 26E

Figure-1

Therefore, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) .

Answer 15

b.

Expert Solution

To determine

To find: Whether the confident interval contradict the claim.

Answer to Problem 26E

The confident interval contradicts the claim.

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

To find: Whether the confident interval contradict the claim.

Answer 20

Answer to Problem 26E

The confident interval contradicts the claim.

Answer 21

Explanation of Solution

Given information:

The data is,

East
10.2	9.5	11.2	1 1.4	9.8	10.0	11.6	1 0.7
9.5	9.0	7.2	11.5	7.7	9.0	8.9	8.4
6.8	5.3	8.0	8.8	9.0	10.0	9.7	11.6
7.9	9.9	10.5	11.9	10.9	8.6	6.7	9.6

West
9.5	7.9	13.4	12.6	9.7	8.2	14.0	7.1
10.2	9.4	10.8	9.5	7.5	9.1	8.4	7.6
7.4	7.7	7.1	11.9	10.2	11.9	7.7	7.0
10.0	8.1	11.5	8.4	9.6	9.5	9.9	11.5

Concept used:

Minitab is used.

Calculation:

Since, the 95% confidence interval for the difference in mean scores between western and eastern cities is (−0.773,0.992) and it does not include 1.5 .

Therefore, the confident interval contradicts the claim.

Answer 22

Ch. 10.1 - In Exercises 5 and 6, fill in each blank with e...Ch. 10.1 - In Exercises 5 and 6, fill in each blank with e...Ch. 10.1 - Prob. 7E Ch. 10.1 - Prob. 8E Ch. 10.1 - In Exercises 9-14, construct the confidence...Ch. 10.1 - Prob. 10E Ch. 10.1 - In Exercises 9-14, construct the confidence...Ch. 10.1 - Prob. 12E Ch. 10.1 - Prob. 13E Ch. 10.1 - Prob. 14E

Videos

Answer to Problem 26E

Explanation of Solution

Answer to Problem 26E

Explanation of Solution

Want to see more full solutions like this?

Chapter 10 Solutions