Chapter 10.1, Problem 10.3BFP

(a)

Interpretation Introduction

Interpretation:

The Lewis structure of ${\text{NO}}^{+}$ is to be drawn.

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons.

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons.

(b)

Interpretation Introduction

Interpretation:

The Lewis structure of the ${\text{H}}_2\text{CO}$ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

(c)

Interpretation Introduction

Interpretation:

The Lewis structure of the ${\text{N}}_2{\text{H}}_2$ is to be drawn

Concept introduction:

To draw the Lewis structure of the molecule with multiple bonds electrons there are following steps:

Step 1: Find the central atom and place the other atoms around it. The atom in a compound which has the lowest group number or lowest electronegativity considered as the central atom.

Step 2: Calculate the total number of valence electrons

Step 3: Connect the other atoms around the central atoms to the central atom with a single bond and lower the value of valence electrons by 2 of every single bond.

Step 4: Allocate the remaining electrons in pairs so that each atom can get 8 electrons

Step 5: Convert the lone pair into bond pair.