A gas of unknown molecular mass is given to be allowed to effuse through a small opening under constant pressure condition. The gas has been given to require 105 s for 1 litre of it to effuse. The given unknown gas under identical experimental condition requires 31 s for 1 litre of O 2 gas. The molar mass of unknown gas is to be stated. Concept introduction: According to Graham’s law the rate of effusion of two gases under constant pressure and temperature condition is given by, r 1 r 2 = M 2 M 1 To determine: The molar mass of given gas having unknown molecular mass.

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Chapter 10, Problem 90E

Interpretation Introduction

Interpretation:

A gas of unknown molecular mass is given to be allowed to effuse through a small opening under constant pressure condition. The gas has been given to require 105 s for 1 litre of it to effuse.
The given unknown gas under identical experimental condition requires 31 s for 1 litre of O2 gas. The molar mass of unknown gas is to be stated.

Concept introduction: According to Graham’s law the rate of effusion of two gases under constant pressure and temperature condition is given by,
r1r2=M2M1

To determine: The molar mass of given gas having unknown molecular mass.

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