Explanation Given data: Mass of the swordfish ( m ) is 650 kg. Cross-sectional area of the swordfish ( A ) is 0.92 m 2 . The drag coefficient of the swordfish ( C D ) is 0.0091. Speed of the swordfish ( v ) is 30 m s . Density of the seawater ( ρ ) is 1026 kg m 3 Formula used: Write the expression to find the specific power for the swordfish as follows. specific power = P m (1) Here, P is the power transformed by the swordfish in its motion, and m is the mass of the swordfish. Refer to the equation (10.25) in the textbook, and modify the expression for transformation power by the swordfish as follows. P = D v (2) Here, D is the drag force acting on the swordfish, and v is the speed of the swordfish. Refer to the equation (5.12) in the textbook, and write the expression for drag force acting on the swordfish as follows. D = 1 2 C D ρ A v 2 (3) Here, C D is the drag coefficient, ρ is the density of the seawater, and A is the cross-sectional area of the swordfish. Explanation: Calculation of specific power for the motion of swordfish: From equation (2), substitute ( D v ) for P in equation (1), specific power = D v m From equation (3), substitute ( 1 2 C D ρ A v 2 ) for D , specific power = ( 1 2 C D ρ A v 2 ) v m = C D ρ A v 3 2 m Substitute 0

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

4th Edition

ISBN: 9780134700502

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Question

Chapter 10, Problem 88GP

To determine

To find: The specific power for the motion of swordfish.

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Chapter 10, Problem 87GP

Chapter 10, Problem 89GP

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College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

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