Explanation Given data: Refer to the Figure P10.28 in the textbook for the required data. The figure shows the restoring force of an abduction pad versus the compression length of the pad. Formula used: Refer to the equation (10.16) in the textbook, and write the expression for the elastic potential energy stored. U s = 1 2 k x 2 (1) Here, k is the spring constant, and x is the length of the spring (pad) compression. Explanation: The slope of the graph in given figure gives the spring constant. At 0.20 mm of the compression length of the pad, the restoring force is 2.5 N. F = 2.5 N x = 0.20 mm Write the expression for the spring constant as follows. k = F x Substitute 2.5 N for F , and 0.20 mm for x , k = 2.5 N 0.20 mm = 2.5 N 0.20 × 10 − 3 m = 12.5 × 10 3 N m Calculation of amount of elastic potential energy stored when the pad is compressed by 0.15 mm ( U s ) : Substitute 12.5 × 10 3 N m for k , and 0

College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

4th Edition

ISBN: 9780134700502

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Question

Chapter 10, Problem 28P

To determine

To find: The amount of elastic potential energy stored when the pad compresses by 0.15 mm.

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Chapter 10, Problem 27P

Chapter 10, Problem 29P

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College Physics: A Strategic Approach, Books a la Carte Edition (4th Edition)

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