Cells use the hydrolysis of adenosine triphosphate, abbreviatedATP, as a source of energy. Symbolically, thisreaction can be represented as ATP( a q )+H 2 O( l ) → ADP( a q )+H 2 PO 4 – ( a q ) where ADP represents adenosine diphosphate. For thisreaction Δ G °=-30 .5 kJ/mol . a. Calculate K at 25°C. b. If all the free energy from the metabolism of glucose C 6 H 12 O 6 ( s )+6O 2 ( g ) → 6CO 2 ( g )+6H 2 O( l ) goes into the production of ATP, how many ATPmolecules can be produced for every molecule ofglucose?
Cells use the hydrolysis of adenosine triphosphate, abbreviatedATP, as a source of energy. Symbolically, thisreaction can be represented as ATP( a q )+H 2 O( l ) → ADP( a q )+H 2 PO 4 – ( a q ) where ADP represents adenosine diphosphate. For thisreaction Δ G °=-30 .5 kJ/mol . a. Calculate K at 25°C. b. If all the free energy from the metabolism of glucose C 6 H 12 O 6 ( s )+6O 2 ( g ) → 6CO 2 ( g )+6H 2 O( l ) goes into the production of ATP, how many ATPmolecules can be produced for every molecule ofglucose?
Solution Summary: The author explains that the Gibbs free energy for a reaction at equilibrium is related to the equilibrium constant (K), and the number of ATP molecules that can be produced for every molecule of glucose that is metabolized needs
Cells use the hydrolysis of adenosine triphosphate, abbreviatedATP, as a source of energy. Symbolically, thisreaction can be represented as
ATP(
a
q
)+H
2
O(
l
)
→
ADP(
a
q
)+H
2
PO
4
–
(
a
q
)
where ADP represents adenosine diphosphate. For thisreaction
Δ
G
°=-30
.5 kJ/mol
. a. Calculate K at 25°C. b. If all the free energy from the metabolism of glucose
C
6
H
12
O
6
(
s
)+6O
2
(
g
)
→
6CO
2
(
g
)+6H
2
O(
l
)
goes into the production of ATP, how many ATPmolecules can be produced for every molecule ofglucose?
Chemical pathways by which living things function, especially those that provide cellular energy, such as the transformation of energy from food into the energy of ATP. Metabolism also focuses on chemical pathways involving the synthesis of new biomolecules and the elimination of waste.
Choose the Lewis structure for the compound below:
H2CCHOCH2CH(CH3)2
HH
H
:d
H
H
H C.
Η
H
H
HH
H
H
H
H.
H
H
H
HH
H
H
H
H
H-
H
H
H
C-H
H
H
HHHH
Each of the highlighted carbon atoms
is connected to
hydrogen atoms.
く
Complete the reaction in the drawing area below by adding the major products to the right-hand side.
If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area
instead.
Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge
bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center.
More...
No reaction.
Explanation
Check
O
+
G
1. Na O Me
Click and drag to start
drawing a structure.
2. H
+
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000
Ar
P
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