Explanation Given T = room temperature V = same for both gases n = same for both gases Formula used KE = 3 2 R T , P = n R T V , Velocity 8 R T M , and , r 1 r 2 = M 2 M 1 Calculation a.PN 2 =PXe because we know n R T V ; here all values are same for both the gases. b. V av for N 2 = 8 R T M = 8 × 8 . 314 J / m o l K × 298 K 3 ...

Chemistry: Structure and Properties Plus Mastering Chemistry with Pearson eText -- Access Card Package (2nd Edition) (New Chemistry Titles from Niva Tro)

2nd Edition

ISBN: 9780134436524

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 10, Problem 72E

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Chapter 10, Problem 71E

Chapter 10, Problem 73E

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When two solutions, one of 0.1 M KCl (I) and the other of 0.1 M MCl (II), are brought into contact by a membrane. The cation M cannot cross the membrane. At equilibrium, x moles of K+ will have passed from solution (I) to (II). To maintain the neutrality of the two solutions, x moles of Cl- will also have to pass from I to II. Explain this equality: (0.1 - x)/x = (0.1 + x)/(0.1 - x)

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Chemistry: Structure and Properties Plus Mastering Chemistry with Pearson eText -- Access Card Package (2nd Edition) (New Chemistry Titles from Niva Tro)

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Chapter 10 Solutions

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