PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Locate the centroid y¯ of the channel's cross-sectional area.
Then determine the moment of inertia with respect to the x′ axis passing through the centroid.
Take that a = 2.2 in.
The shaded area has the following properties:
4 = 126 x10 mm* ; 1, = 6,55 x10* mm* ; and
Pay =-1.02 10° mm*
Determine the moments of inertia of the area about
the x' and v' axes if e=30°.
H6.
Find the position of the cross-section’s centroid. Then, determine the moments of inertia of horizontal & vertical axes through the centroid.
(I'm not sure if the width of the verticle rectangle is needed or not. If it is, assume 5 mm.)
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- The moment of inertia of the plane region about the x-axis and the centroidal x-axis are Ix=0.35ft4 and Ix=0.08in.4, respectively. Determine the coordinate y of the centroid and the moment of inertia of the region about the u-axis.arrow_forwardThe moments of inertia of the plane region about the x- and u-axes are Ix=0.4ft4 and Iu=0.6ft4, respectively. Determine y (the y-coordinate of the centroid C) and Ix (the moment of inertia about the centroidal x-axis).arrow_forward3. Determine the distance y to the centroid for the beam's cross sectional area; then determine the moment of inertia about the x' axis. 25 mm 50 mm 100 mm 75 mm C 25 mm 25 mm 75 mm- 50 mm 100 mm 25 mm -Xarrow_forward
- 1). Locate the centroid C (x,j) of the shaded area. C(x.Y) 2). Determine the moment of inertia of the shaded area about the x-axis and y-axis. 3). Find the radius of gyration about the area, kx and ky y=2.5-0.12 2.5 ft 2 ft 5ftarrow_forwardANSWER THE FOLLOWING CORRECTLY AND PROVIDE A DETAILED SOLUTION. 1. DETERMINE THE MOMENT OF INERTIA OF THE SHADED SECTION ABOUT THE GIVEN X-AXIS.arrow_forwardDetermine the location of centroidal x and y and the moment of inertia Ix of the figure shown. Use the parallel axis theorem. Where B = 9, and Y = 82arrow_forward
- The shaded area shown. is bounded by the line y=x m and the curve y2=1.2x m2, where x is in m. Suppose that a = 1.2 m. Determine the moment of inertia for the shaded area about the y axis.arrow_forwardDetermine the moment of inertia and the radius of gyration of the shaded area with respect to the x-axis. Given: r = 79 mm. 125 mm 125 mm - 250 mm The moment of inertia is The radius of gyration is *106 mm4. mm.arrow_forwardDetermine the centroid of the composite body. Then, determine the moment of inertia about the x'-x' axis.arrow_forward
- Determine the moment of inertia of the area about: A. the x-axis B. the y-axis Hint: See Appendix A for the textbook for common integral solutions. 9 in. 3 in. y=9-x² Xarrow_forwardFind the moment of inertia about centroidal X-axis and centroidal Y-axis of the given geometryarrow_forwardThe variable h designates the arbitrary vertical location of the center of the circular cutout within the semicircular area. Determine the area moment of inertia about the x-axis for (a) h = 0 and (b) h = 4 in. y 3" 12" h LL Amswers: (a) h = 0 in.4 (b) h = 4 in. Ix= i in.4arrow_forward
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