The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated. Concept introduction: According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation, E = hν where ν = c λ E = energy h = Planck's constant ν = frequency c = velocity of light λ = wavelength
Solution Summary: The author explains that the wavelength of the light emitted by Aluminium phosphide diode has to be calculated. The energy gap between the valence band and conduction band is represented by Planck’s equation
The wavelength of the light emitted by Aluminium phosphide diode has to be calculated.
Concept introduction:
According to Band theory of solids, the energy levels of a substance are imagined as “bands”. There are two types of bands – valence band and conduction band. Low lying bands are valence band and conduction band where the conduction takes place, lies above the valence band. The energy gap between the valence band and conduction band is called “band gap”. The energy gap can be represented by Planck’s equation,
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Curved arrows are used to
illustrate the flow of electrons.
Use the reaction conditions
provided and follow the curved
arrows to draw the product of
this carbocation rearrangement.
Include all lone pairs and
charges as appropriate.
H
1,2-alkyl shift
+
Would the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.
Below is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero
formal charges. In the third box, draw the two enantiomeric products that will be produced.
5th attempt
Please draw all four bonds at chiral centers.
Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers.
1000
4th attempt
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Please draw all four bonds at chiral centers.
8.
R5
HO:
See Periodic Table
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H
Cl
Br
Jid See Periodic Table See Hint
Chapter 10 Solutions
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