Chapter 10, Problem 62E

Interpretation Introduction

Interpretation:

The value of ${\text{ΔG}}^o$ for the following reaction should be calculated.

  ${\text{6C(s)+3H}}_{\text{2}}\text{(g)}\to {\text{C}}_{\text{6}}{\text{H}}_{\text{6}}\text{(l)}$

Concept Introduction:

At standard states, the free energy charge which is responsible for the production of 1 mole of a molecule from its elements is known as standard free energy of formation and it is represented by ${\text{ΔG}}_{\text{f}}^{\text{o}}$.

If the value of ${\text{ΔG}}_{298}^{\text{o}}$ is more than zero, then non-spontaneous will be the reaction whereas If the value of ${\text{ΔG}}_{298}^{\text{o}}$ is less than zero, then spontaneous will be the reaction.

The mathematical expression for ${\text{ΔG}}_{\text{f}}^{\text{o}}$ at standard state is given by:

  ${\text{ΔG}}_{\text{298}}^{\text{o}}\text{=ΔH°-TΔS°}$ or,

  $\Delta G°=\Delta G{°}_{298}={\displaystyle \sum \text{n}}{\text{G°}}_{\text{298}}\text{(products})-{\displaystyle \sum \text{p}}{\text{G°}}_{\text{298}}\text{(reactants)}$

Where, n and p represents the coefficients of reactants and products in the balanced chemical equation.