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State the number of valence electrons, bonding pairs, and lone pairs in each of the following Lewis structures: (10.1) 
(a)
Interpretation:
Interpret number of valence electron, bond pair and lone pair in the given Lewis structure.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with another atom.
The bond formed between two atoms by sharing of electrons is known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule.
For example, inHxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
Answer to Problem 59UTC
Total number of valence electron = 2
Bond pair = 1
Lone pair = 0
Explanation of Solution
The given Lewis structure is as follows:
Total number of valence electron = number of H (valence electron of H)
Total number of valence electron = 2
Bond pair = 1
Lone pair = 0
(b)
Interpretation:
Interpret number of valence electron, bond pair and lone pair in given Lewis structure.
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with another atom.
The bond formed between two atoms by sharing of electrons is known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule.
For example, inHxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
Answer to Problem 59UTC
Total number of valence electron = 8
Bond pair = 1
Lone pair = 3
Explanation of Solution
The given Lewis structure is of HBr.
Total number of valence electron = number of H (valence electron of H) + number of Br (valence electron of Br)
Total number of valence electron = 1 (1) + 1 (7) = 8
Bond pair = 1
Lone pair = 3
(c)
Interpretation:
Interpret number of valence electron, bond pair and lone pair in Br-Br
Concept Introduction:
Valence electrons are the electrons present in the outermost orbital or shell of an atom which participates in the formation of bond with another atom.
The bond formed between two atoms by sharing of electrons is known as covalent bond. A single chemical bond is formed by sharing of 2 electrons while double bond is formed by sharing of 4 and triple bond is formed by sharing of 6 electrons.
Total number of valence electron can be determined by adding all the electrons present in the outermost shell of each atom present in a molecule.
For example, inHxOy
Total number of valence electron = number of H (valence electron of H) + number of O (valence electron of O)
Answer to Problem 59UTC
Total number of valence electron = 2 (7) = 14
Bond pair = 1
Lone pair = 6
Explanation of Solution
The given Lewis structure is of Br2.
Total number of valence electron = number of Br (valence electron of Br)
Total number of valence electron = 2 (7) = 14
Bond pair = 1
Lone pair = 6
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Chapter 10 Solutions
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Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning