Introduction to the Practice of Statistics: w/CrunchIt/EESEE Access Card
Introduction to the Practice of Statistics: w/CrunchIt/EESEE Access Card
8th Edition
ISBN: 9781464158933
Author: David S. Moore, George P. McCabe, Bruce A. Craig
Publisher: W. H. Freeman
bartleby

Videos

Question
Book Icon
Chapter 10, Problem 52E

(a)

To determine

To find: The mean of the predicted values of the ACT scores and its comparison with the mean of the ACT scores.

(a)

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The mean value of the ACT score is 21.133 and the mean value of the predicted value of ACT score is 21.162. Both the mean values are identical.

Explanation of Solution

Calculation: The predicted values can be obtained by using the referred Exercise 10.61.

The regression equation is

ACT=1.63+0.0214 SAT

The predicted values for ACT corresponding to the SAT score of 1000 is calculated as shown below:

ACT=1.63+0.0214 SAT=1.63+0.0214 (1000)=23.03

Similarly, obtain the predicted values for ACT corresponding to the remaining SAT scores as shown below:

Obs

SAT

Predicted values for ACT

1

1000

23.03

2

1010

23.24

3

920

21.32

4

840

19.61

5

830

19.39

6

1440

32.45

7

490

12.12

8

1050

24.1

9

870

20.25

10

970

22.39

11

920

21.32

12

810

18.96

13

1080

24.74

14

1000

23.03

15

1030

23.67

16

870

20.25

17

880

20.46

18

850

19.82

19

780

18.32

20

830

19.39

21

1190

27.1

22

800

18.75

23

830

19.39

24

890

20.68

25

880

20.46

26

980

22.6

27

1030

23.67

28

1220

27.74

29

1080

24.74

30

970

22.39

31

1090

24.96

32

860

20.03

33

740

17.47

34

500

12.33

35

780

18.32

36

1120

25.6

37

590

14.26

38

990

22.82

39

700

16.61

40

930

21.53

41

860

20.03

42

420

10.62

43

800

18.75

44

1140

26.03

45

920

21.32

46

800

18.75

47

1040

23.89

48

840

19.61

49

1060

24.31

50

870

20.25

51

1120

25.6

52

800

18.75

53

960

22.17

54

880

20.46

55

1020

23.46

56

790

18.54

57

620

14.9

58

1150

26.24

59

970

22.39

60

1060

24.31

The mean value for the predicted values of ACT can be calculated as shown below:

Mean=Sum of the predicted values of ACTTotal number of values=1269.6960=21.162

With the help of Minitab, the mean of the ACT scores can be calculated as shown below:

Step 1: Enter the data into the worksheet of Minitab.

Step 2: Go to StatBasic StatisticsDisplay Descriptive Statistics. In the “Variables” textbox, enter the variable “ACT.”

Step 3: Go to statistics and select mean. Click on “OK” twice.

Hence, the required mean obtained is 21.133.

Interpretation: Therefore, it can be concluded that the mean value of the ACT score and the mean value of the predicted value of ACT score are identical.

(b)

To determine

To find: The standard deviation of the predicted values and its comparison with the standard deviation of the actual ACT scores.

(b)

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The standard deviation of the ACT score is 4.714 and the standard deviation of the predicted ACT scores is 3.854.

Explanation of Solution

Calculation: With the help of Minitab, the standard deviation of the ACT scores can be calculated as shown below:

Step 1: Enter the data into the worksheet of Minitab.

Step 2: Go to StatBasic StatisticsDisplay Descriptive Statistics. In the “Variables,” enter the variable “ACT.”

Step 3: Go to statistics and select standard deviation. Click on “OK” twice.

Hence, the required standard deviation obtained is 4.714.

Use the predicted values of the ACT scores, which is obtained in the part (a). With the help of Minitab, the standard deviation of the predicted ACT scores or fitted values can be calculated as shown below:

Step 1: Enter the data of the predicted values of the ACT scores into the worksheet of Minitab.

Step 2: Go to StatBasic StatisticsDisplay Descriptive Statistics. In the “Variables” textbox, enter the variable “Predicted ACT scores.”

Step 3: Go to statistics and select standard deviation. Click on “OK” twice.

Hence, the required standard deviation obtained is 3.854.

Interpretation: Therefore, it can be concluded that the variability in the predicted ACT scores is less in comparison to the variability in the ACT scores.

(c)

To determine

To find: The SAT score for a student who is one standard deviation above the mean.

(c)

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The SAT score for a student who is one standard deviation above the mean is 1092.8.

Explanation of Solution

Calculation: With the help of Minitab, the mean of the SAT scores can be calculated as shown below:

Step 1: Enter the data into the worksheet of Minitab.

Step 2: Go to StatBasic StatisticsDisplay Descriptive Statistics. In the “Variables” textbox, enter the variable “SAT.”

Step 3: Go to statistics and select mean. Click on “OK” twice.

Hence, the required mean obtained is 912.7.

With the help of Minitab, the standard deviation of the SAT scores can be calculated as shown below:

Step 1: Enter the data into the worksheet of Minitab.

Step 2: Go to StatBasic StatisticsDisplay Descriptive Statistics. In the “Variables,” enter the variable “SAT.”

Step 3: Go to statistics and select standard deviation. Click on “OK” twice.

Hence, the required standard deviation obtained is 180.1.

For z=1, the SAT score for a student who is one standard deviation above the mean is calculated as

SAT score=Mean of SAT scores+Standard deviation of SAT scores=912.7+180.1=1092.8 

Interpretation: Therefore, it can be concluded that the predicted SAT score is 1092.8, which provides a standard score of about one by using the standard deviation of the predicted SAT scores.

To determine

To find: The predicted ACT score for a student who is one standard deviation above the mean and standardize this predicted ACT score.

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The required predicted ACT score is 25.02.

Explanation of Solution

Calculation: The predicted ACT score can be calculated as

ACT=1.63+0.0214 (SAT)=1.63+0.0214 (1092.8)=25.02

Interpretation: Therefore, it can be concluded that the predicted ACT score is 25.02, which provides a standard score of about one by using the standard deviation of the predicted ACT scores.

(d)

To determine

To find: The SAT score for a student who is one standard deviation below the mean.

(d)

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The SAT score for a student who is one standard deviation below the mean is 732.6.

Explanation of Solution

Calculation: For z=1, the SAT score for a student who is one standard deviation below the mean is calculated as

SAT score=Mean of SAT scoresStandard deviation of SAT scores=912.7180.1=732.6

To determine

To find: The predicted ACT score for a student who is one standard deviation below the mean and standardize this predicted ACT score.

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The required predicted ACT score is 17.3.

Explanation of Solution

Calculation: For z=1, the SAT score for a student who is one standard deviation below the mean is calculated as

SAT score=Mean of SAT scoresStandard deviation of SAT scores=912.7180.1=732.6

The predicted ACT score is

ACT=1.63+0.0214 (SAT)=1.63+0.0214 (732.6)=17.3

(e)

To determine

To explain: The conclusions on the basis of part (c) and part (d).

(e)

Expert Solution
Check Mark

Answer to Problem 52E

Solution: The standard score of the predicted value is same as the explanatory variable’s standard score for the parts (c) and (d).

Explanation of Solution

For the part (c), the predicted ACT score is 25.02 and the corresponding SAT score is 1120, which is similar to the standardized SAT score 1092.8. For the part (d), the predicted ACT score is 17.3 and the corresponding SAT score is 740, which is similar to the standardized SAT score 732.6. So, for the parts (c) and (d), it can be said that explanatory variable’s standard score is appears to be same as the standard score of the predicted value.

Therefore, it can be said that the standard score of the predicted value is the same as the explanatory variable’s standard score.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
An Arts group holds a raffle.  Each raffle ticket costs $2 and the raffle consists of 2500 tickets.  The prize is a vacation worth $3,000.    a. Determine your expected value if you buy one ticket.     b. Determine your expected value if you buy five tickets.     How much will the Arts group gain or lose if they sell all the tickets?
Please show as much work as possible to clearly show the steps you used to find each solution. If you plan to use a calculator, please be sure to clearly indicate your strategy.        Consider the following game.  It costs $3 each time you roll a six-sided number cube.  If you roll a 6 you win $15.  If you roll any other number, you receive nothing.   a) Find the expected value of the game.         b) If you play this game many times, will you expect to gain or lose money?
= 12:02 WeBWorK / 2024 Fall Rafeek MTH23 D02 / 9.2 Testing the Mean mu / 3 38 WEBWORK Previous Problem Problem List Next Problem 9.2 Testing the Mean mu: Problem 3 (1 point) Test the claim that the population of sophomore college students has a mean grade point average greater than 2.2. Sample statistics include n = 71, x = 2.44, and s = 0.9. Use a significance level of a = 0.01. The test statistic is The P-Value is between : The final conclusion is < P-value < A. There is sufficient evidence to support the claim that the mean grade point average is greater than 2.2. ○ B. There is not sufficient evidence to support the claim that the mean grade point average is greater than 2.2. Note: You can earn partial credit on this problem. Note: You are in the Reduced Scoring Period. All work counts for 50% of the original. Preview My Answers Submit Answers You have attempted this problem 0 times. You have unlimited attempts remaining. . Oli wwm01.bcc.cuny.edu
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman
F- Test or F- statistic (F- Test of Equality of Variance); Author: Prof. Arvind Kumar Sing;https://www.youtube.com/watch?v=PdUt7InTyc8;License: Standard Youtube License
Statistics 101: F-ratio Test for Two Equal Variances; Author: Brandon Foltz;https://www.youtube.com/watch?v=UWQO4gX7-lE;License: Standard YouTube License, CC-BY
Hypothesis Testing and Confidence Intervals (FRM Part 1 – Book 2 – Chapter 5); Author: Analystprep;https://www.youtube.com/watch?v=vth3yZIUlGQ;License: Standard YouTube License, CC-BY
Understanding the Levene's Test for Equality of Variances in SPSS; Author: Dr. Todd Grande;https://www.youtube.com/watch?v=udJr8V2P8Xo;License: Standard Youtube License