Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
9th Edition
ISBN: 9781319013387
Author: David S. Moore, George P. McCabe, Bruce A. Craig
Publisher: W. H. Freeman
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Chapter 10, Problem 49E

(a)

To determine

To find: The variables IBI and Forest using numerical method.

(a)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The obtained result can be shown in tabular form as follows:

Variable

Mean

Standard deviation

Forest

39.39

32.20

IBI

65.94

18.28

Explanation of Solution

Calculation: Calculate the average and standard deviation of IBI and Forest using Minitab as follows:

Step 1: Enter the data in Minitab.

Step 2: Go to Graphs > Histogram > Simple histogram.

Step 3: Double click on ‘Forest’ and ‘IBI’ to move it to variables column.

Step 4: Click on ‘Statistics’ and check the box for mean and standard deviation.

Step 5: Click ‘OK’ twice to obtain the result.

Results are obtained as:

Variable

Mean

Standard deviation

Forest

39.39

32.20

IBI

65.94

18.28

To determine

To find: The variables IBI and Forest using graphical method.

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The graph of Forest is right skewed and the graph of IBI is left skewed.

Explanation of Solution

Graph: Construct the histograms to check the skewness using Minitab as follows:

Step 1: Click on Graphs --> Histogram. Select simple histogram.

Step 2: Double click on ‘Forest’ and ‘IBI’ to move it to variables column.

Step 3: Click ‘OK’ to obtain the result.

Introduction to the Practice of Statistics, Chapter 10, Problem 49E , additional homework tip  1

Interpretation: The graph of Forest is right skewed and the graph of IBI is left skewed.

(b)

To determine

To graph: A scatterplot.

(b)

Expert Solution
Check Mark

Explanation of Solution

Graph: Construct a scatter plot as follows:

Step 1: Enter the data in Minitab.

Step 2: Click on Graph --> Scatterplot. Select scatterplot with regression.

Step 3: Double click on ‘BAC’ to move it Y variable and ‘Beer’ to move it to X variable column.

Step 4: Click ‘Ok’ twice to obtain the graph.

The scatter plot is obtained as:

Introduction to the Practice of Statistics, Chapter 10, Problem 49E , additional homework tip  2

Interpretation: The graph shows weak linear relationship between IBI and Forest with no unusual activity.

(c)

To determine

To explain: The statistical model for simple linear regression.

(c)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The model is IBI(y^)=β0+β1Forest(x)+ε_.

Explanation of Solution

The statistical model for the provided problem can be shown as follows:

IBI(y^)=β0+β1Forest(x)+ε

Where,

IBI is the response varibaleβ0 is the inetrceptβ1 is the slopeForest is the explanatory variableε is the error term

(d)

To determine

To explain: The null and alternate hypotheses.

(d)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The null and alternative hypotheses are:

H0:β1=0H1:β10

Explanation of Solution

Consider the null and alternate hypothesis as follows:

H0:(There is no significant relationshipbetween IBI and Forest)H1:(There is a significant relationshipbetween IBI and Forest)

So, the null and alternative hypothesis can be stated as:

H0:β1=0H1:β10

(e)

To determine

To test: The least square regression analysis.

(e)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The obtained output represents that the p-value is greater than 0.05. So there is no enough evidence for the linearity in the regression line.

Explanation of Solution

Calculation: Obtain the regression line using Minitab as follows:

Step 1: Enter the data in Minitab.

Step 2: Click on Stat --> Regression --> Regression.

Step 3: Double click on ‘IBI’ to move it response column and ‘Forest’ to move it to predictor column.

Step 4: Click ‘Ok’ to obtain the result.

Conclusion: From the obtained output the value of test statistic is 1.92 and the p-value is 0.061. Since the p-value is greater than 0.05, it can be concluded that there is no enough evidence for the linearity in the regression line

(f)

To determine

To find: The residuals.

(f)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The residuals are as follows:

Forest

IBI

Residuals

0

47

-12.9072

0

76

16.0928

9

33

-28.2854

17

78

15.4895

25

62

-1.7355

33

78

13.0394

47

33

-34.1045

59

64

-4.9420

79

83

10.9953

95

67

-7.4548

0

61

1.0928

3

85

24.6334

10

46

-15.4386

17

53

-9.5105

31

55

-9.6543

39

71

5.1206

49

59

-8.4107

63

41

-28.5546

80

82

9.8422

95

56

-18.4548

0

39

-20.9072

3

89

28.6334

10

32

-29.4386

18

43

-19.6636

32

29

-35.8075

41

55

-11.1857

49

81

13.5893

68

82

11.6798

86

82

8.9234

100

85

9.7795

0

59

-0.9072

7

74

13.0208

11

80

18.4083

21

88

24.8770

33

29

-35.9606

43

58

-8.4919

52

71

3.1299

75

60

-11.3922

89

86

12.4640

100

91

15.7795

0

72

12.0928

8

89

27.8677

14

80

17.9489

22

84

20.7238

33

54

-10.9606

43

71

4.5081

52

75

7.1299

79

84

11.9953

90

79

5.3109

Explanation of Solution

Calculation: Obtain the regression line using Minitab as follows:

Step 1: Enter the data in Minitab.

Step 2: Click on Stat --> Regression --> Regression.

Step 3: Double click on ‘IBI’ to move it response column and ‘Forest’ to move it to predictor column.

Step 4: Click on ‘Storage’ and check the box for residuals.

Step 5: Click ‘Ok’ twice to obtain the result.

To determine

To graph: The scatterplot.

Expert Solution
Check Mark

Explanation of Solution

Graph: Construct a scatterplot using Minitab as follows:

Step 1: Enter the data in Minitab.

Step 2: Click on Graph --> Scatterplot. Select scatterplot with regression.

Step 3: Double click on ‘Forest’ to move it X variable and ‘Residuals’ to move it to Y variable column.

Step 4: Click ‘Ok’ to obtain the graph.

The scatter plot is obtained as:

Introduction to the Practice of Statistics, Chapter 10, Problem 49E , additional homework tip  3

Interpretation: The graph shows that there is more variation for small x.

To determine

To explain: Whether there is something unusual.

Expert Solution
Check Mark

Answer to Problem 49E

Solution: No, there is nothing unusual.

Explanation of Solution

The observations in the obtained residuals plot are scatters randomly over the line of origin. There is no pattern observed in the plot. So it can be concluded that the errors are independent.

(g)

To determine

To find: That residuals are normal or not.

(g)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The residuals are approximately normally distributed.

Explanation of Solution

Construct the probability plot for residuals to test for the normality using Minitab as follows:

Step 1: Click on Stat --> Descriptive statistics --> Normality test.

Step 2: Double click on ‘Residuals’ to move it to the variable column.

Step 3: Click ‘OK’ to obtain the graph.

The graph is obtained.

Interpretation: All the points lie near the trend line. Therefore, it can be concluded that residuals are approximately normally distributed.

(h)

To determine

To explain: If the assumptions of statistical inference in satisfied or not.

(h)

Expert Solution
Check Mark

Answer to Problem 49E

Solution: The assumptions are not reasonable.

Explanation of Solution

Consider the solutions of part (c). Since, the residuals are independent and normally distributed with 0 mean and unknown standard deviation. Therefore, residuals are not normal but left skewed. Thus, it can be concluded that the assumptions for statistical inference are not reasonably satisfied.

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