Probability and Statistics for Engineering and the Sciences
9th Edition
ISBN: 9781305251809
Author: Jay L. Devore
Publisher: Cengage Learning
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Chapter 10, Problem 45SE
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Justify the way the value of the F statistic computed from the
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Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S.
Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not
assume that the population standard deviations are equal. Complete parts (a) and (b).
Click the icon to view the ANSUR data.
a. Use a 0.05 significance level to test the claim that the mean weight of the 1988…
solving problem 1
select bmw stock. you can assume the price of the stock
Chapter 10 Solutions
Probability and Statistics for Engineering and the Sciences
Ch. 10.1 - In an experiment to compare the tensile strengths...Ch. 10.1 - Suppose that the compression-strength observations...Ch. 10.1 - The lumen output was determined for each of I = 3...Ch. 10.1 - It is common practice in many countries to destroy...Ch. 10.1 - Consider the following summary data on the modulus...Ch. 10.1 - The article Origin of Precambrian Iron Formations...Ch. 10.1 - An experiment was carried out to compare...Ch. 10.1 - A study of the properties of metal plate-connected...Ch. 10.1 - Six samples of each of four types of cereal grain...Ch. 10.1 - In single-factor ANOVA with I treatments and J...
Ch. 10.2 - An experiment to compare the spreading rates of...Ch. 10.2 - In Exercise 11, suppose x3. = 427.5. Now which...Ch. 10.2 - Prob. 13ECh. 10.2 - Use Tukeys procedure on the data in Example 10.3...Ch. 10.2 - Exercise 10.7 described an experiment in which 26...Ch. 10.2 - Reconsider the axial stiffness data given in...Ch. 10.2 - Prob. 17ECh. 10.2 - Consider the accompanying data on plant growth...Ch. 10.2 - Prob. 19ECh. 10.2 - Refer to Exercise 19 and suppose x1 = 10, x2 = 15,...Ch. 10.2 - The article The Effect of Enzyme Inducing Agents...Ch. 10.3 - The following data refers to yield of tomatoes...Ch. 10.3 - Apply the modified Tukeys method to the data in...Ch. 10.3 - The accompanying summary data on skeletal-muscle...Ch. 10.3 - Lipids provide much of the dietary energy in the...Ch. 10.3 - Samples of six different brands of diet/imitation...Ch. 10.3 - Although tea is the worlds most widely consumed...Ch. 10.3 - For a single-factor ANOVA with sample sizes Ji(i =...Ch. 10.3 - When sample sizes are equal (Ji = J). the...Ch. 10.3 - Reconsider Example 10.8 involving an investigation...Ch. 10.3 - When sample sizes are not equal, the non...Ch. 10.3 - In an experiment to compare the quality of four...Ch. 10.3 - Prob. 33ECh. 10.3 - Simplify E(MSTr) for the random effects model when...Ch. 10 - An experiment was carried out to compare flow...Ch. 10 - Cortisol is a hormone that plays an important role...Ch. 10 - Numerous factors contribute to the smooth running...Ch. 10 - An article in the British scientific journal...Ch. 10 - Prob. 39SECh. 10 - Prob. 40SECh. 10 - Prob. 41SECh. 10 - The critical flicker frequency (cff) is the...Ch. 10 - Prob. 43SECh. 10 - Four types of mortarsordinary cement mortar (OCM)....Ch. 10 - Prob. 45SECh. 10 - Prob. 46SE
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- Microsoft Excel snapshot for random sampling: Also note the formula used for the last column 02 x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51)) A B 1 No. States 2 1 ALABAMA Rand No. 0.925957526 3 2 ALASKA 0.372999976 4 3 ARIZONA 0.941323044 5 4 ARKANSAS 0.071266381 Random Sample CALIFORNIA NORTH CAROLINA ARKANSAS WASHINGTON G7 Microsoft Excel snapshot for systematic sampling: xfx INDEX(SD52:50551, F7) A B E F G 1 No. States Rand No. Random Sample population 50 2 1 ALABAMA 0.5296685 NEW HAMPSHIRE sample 10 3 2 ALASKA 0.4493186 OKLAHOMA k 5 4 3 ARIZONA 0.707914 KANSAS 5 4 ARKANSAS 0.4831379 NORTH DAKOTA 6 5 CALIFORNIA 0.7277162 INDIANA Random Sample Sample Name 7 6 COLORADO 0.5865002 MISSISSIPPI 8 7:ONNECTICU 0.7640596 ILLINOIS 9 8 DELAWARE 0.5783029 MISSOURI 525 10 15 INDIANA MARYLAND COLORADOarrow_forwardSuppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined. 1.What percent of the refunds are more than $3,500? 2. What percent of the refunds are more than $3500 but less than $3579? 3. What percent of the refunds are more than $3325 but less than $3579?arrow_forwardA normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forward
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