a)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
b)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
c)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
d)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
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Chapter 10 Solutions
WebAssign for Zumdahl/Zumdahl/DeCoste's Chemistry, 10th Edition [Instant Access], Single-Term
- 1. Complete the following table in your laboratory notebook. Substance Formula Methanol CH3OH Ethanol C2H5OH 1-Propanol C3H7OH 1-Butanol C4H9OH Pentane C5H12 Hexane C6H14 Water H₂O Acetone C3H60 Structural Formula Molecular Weight (g/mol) Hydrogen Bond (Yes or No)arrow_forwardQ1: Compare the relative acidity in each pair of compounds. Briefly explain. (a) CH3OH vs NH 3 (b) HF vs CH3COOH (c) NH3 vs CH4 (d) HCI vs HI (e) CH3COOH vs CH3SH (f) H₂C=CH2 vs CH3 CH3 (g) compare the acidity of the two bolded hydrogens O. H N- (h) compare the acidity of the two bolded hydrogens, draw resonance structures to explain H H Harrow_forwardQ3: Rank the following molecules in order of decreasing boiling point: (a) 3-methylheptane; (b) octane; (c) 2,4-dimethylhexane; (d) 2,2,4-trimethylpentane.arrow_forward
- Q5: Conformations of Alkanes a) Draw a Newman Projection of the compound below about the C2-C3 bond. H3C Cli... H IIIH Br CH3arrow_forwardThe ability of atoms to associate with each other depends ona) the electronic structure and its spatial orientation.b) the electron affinity.c) The other two answers are correct.arrow_forwardWhat is the final volume after you reach the final temperature? I put 1.73 but the answer is wrong not sure why The initial volume of gas is 1.60 LL , the initial temperature of the gas is 23.0 °C°C , and the system is in equilibrium with an external pressure of 1.2 bar (given by the sum of a 1 bar atmospheric pressure and a 0.2 bar pressure due to a brick that rests on top of the piston). Then, as you did in Exercise 1, you heat the gas slowly until the temperature reaches 48.2 °Carrow_forward
- Q4: Identify the type of Carbon ( methyl, primary, secondary, etc. ) indicated by this arrow.arrow_forwardQ3: Curved Arrows, Lewis Acids & Bases, Nucleophiles and Electrophiles Considering the following reactions: a) Predict the products to complete the reactions. b) Use curved electron-pushing arrows to show the mechanism for the reaction in the forward direction. Redraw some of the compounds to explicitly illustrate all bonds that are broken and all bonds that are formed. c) Label Lewis acids and bases, nucleophiles and electrophiles in the reactions. A. S + AICI 3 B. + H₂Oarrow_forward3. A thermometer is placed in a test tube of chipped ice at -5.0 °C. The temperature is recorded at the time intervals shown below until room temperature is reached. Plot the data given below on graph paper and explain all flat, horizontal portions of the curve. Plot time on the X-axis! Time (min) Temperature (°C) 0 -5.0 2 -2.5 4 -1.0 6 0.0 10 0.0 15 0.0 20 0.0 25 0.0 30 1.5 35 4.0 40 8.0 45 11.5 50 15.0 55 17.5 60 19.0 65 20.0 70 20.0 75 20.0 80 20.0arrow_forward
- Naming the Alkanes a) Write the IUPAC nomenclature of the compound below b) Draw 4-isopropyl-2,4,5-trimethylheptane, identify the primary, secondary, tertiary, and quaternary carbons. c) Rank pentane, neopentane and isopentane for boiling point. pentane: H3C-CH2-CH2-CH2-CH3 neopentane: CH3 H3C-Ċ-CH3 I CH3 isopentane: CH3 H3C-CH2-CH-CH3arrow_forwardWhich will evaporate faster, 1-Butanol or Pentane? Explain your choice.arrow_forwardUsing the equation below, what is the rate of this reaction if the rate of disappearance of H2 is 0.44 M/sec? H2 + Br2 → 2HBrarrow_forward
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