
a)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
b)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
c)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.
d)
Interpretation:
The difference in the boiling points of the given set of compounds has to be rationalized.
Concept Introduction:
- Boiling point of any compound, depends upon its strength of Intramolecular force and Intermolecular force present in it.
- Intramolecular force refers to type of bonding between the atoms.
- Intermolecular forces are the forces that bind the molecules together to attribute to a stability of a compound.
- If the strength of intermolecular forces is high, boiling point will be high and if it is low, boiling point will be low.
- They are collectively known as “Interparticle forces”. The classification can be summarized as follows –
Figure 1
Figure 2
Figure 3
The type of bonding between atoms or ions is Intramolecular force. The intramolecular force in ionic compounds is electrostatic force of attraction between the ions of opposite charges. Usually ionic compounds are solids with high melting points. Covalent bonds are of two types, that is polar covalent bond and non-polar covalent bond. Covalent compounds are found as solids and liquids with moderate melting and boiling point. Metallic bond is formed between the metal atoms of an element.
Intermolecular forces are Van der Waals forces. They are weak and are of three types - London dispersion forces, dipole-dipole forces and hydrogen bonding. Hydrogen bonding is formed in polar covalent compounds containing hydrogen and other high electronegativity like fluorine, oxygen or nitrogen. These atoms in a molecule partially bond to hydrogen of the other same molecule or within a molecule. It is relatively the strongest one. Hydrogen bonded compounds are usually liquids. They exhibit high boiling point.
London dispersion forces exist in all types of molecules. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
Dipole-dipole forces exist in polar covalent compounds. Hydrogen bonding exists in polar covalent compounds containing Fluorine, Oxygen or Nitrogen directly bonded to Hydrogen.

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Chapter 10 Solutions
Bundle: Chemistry, Loose-Leaf Version, 10th + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
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- 1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward✓ Check the box under each molecule that has a total of five ẞ hydrogens. If none of the molecules fit this description, check the box underneath the table. tab OH CI 0 Br xx Br None of these molecules have a total of five ẞ hydrogens. esc Explanation Check caps lock shift 1 fn control 02 F2 W Q A N #3 S 80 F3 E $ t 01 205 % 5 F5 & 7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility FT * 8 R T Y U כ F6 9 FIG F11 F D G H J K L C X V B < N M H option command P H + F12 commandarrow_forward
- Draw the major product of this reaction. Ignore inorganic byproducts and the carboxylic acid side product. O 1. CHзMgBr (excess) 2. H₂O ✓ W X 人arrow_forwardIf cyclopentyl acetaldehyde reacts with NaOH, state the product (formula).arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. N S S HgCl2, H2SO4 く 8 W X Parrow_forward
- tab esc く Drawing the After running various experiments, you determine that the mechanism for the following reaction occurs in a step-wise fashion. Br + OH + Using this information, draw the correct mechanism in the space below. 1 Explanation Check F2 F1 @2 Q W A os lock control option T S # 3 80 F3 Br $ 4 0105 % OH2 + Br Add/Remove step X C F5 F6 6 R E T Y 29 & 7 F D G H Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce A F7 DII F8 C Ո 8 * 9 4 F10 F C J K L C V Z X B N M H command P ge Coarrow_forwardIndicate compound A that must react with ethylbenzene to obtain 4-ethylbenzene-1-sulfonic acid. 3-bromo-4-ethylbenzene-1-sulfonic acid.arrow_forwardPart 1 of 2 Draw the structure of A, the minor E1 product of the reaction. esc I Skip Part Check H₂O, D 2 A + Click and drag to start drawing a structure. -0- F1 F2 1 2 # 3 Q A 80 F3 W E S D F4 $ 4 % 5 F5 ㅇ F6 R T Y F G X 5 & 7 + Save 2025 McGraw Hill LLC. All Rights Reserved. DII F7 F8 H * C 80 J Z X C V B N 4 F9 6arrow_forward
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