Business Driven Technology
Business Driven Technology
6th Edition
ISBN: 9780073376905
Author: Paige Baltzan Instructor
Publisher: McGraw-Hill Education
Question
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Chapter 10, Problem 3CQ
Program Plan Intro

Radio – Frequency Identification (RFID):

Radio-Frequency Identification uses the radio waves which automatically read and grasp the information stored on tag which is attached to an object. The tag attached on the object holds the electronically stored information.

RFID tag and reader:

  • An electronic identification device that is built using the chip and antenna is called as RFID tag.
  • The contents that are present in the RFID tags are read using RFID reader.
  • The process of providing data and commands to an instruction into the computer is known as input and there are some input devices that are used to retrieve data and instructions into Random Access Memory (RAM).
  • It detects the radio signals emitted by the tag and picks up the signals into the RFID reader placed on a wall which is away from numerous feet.

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#include int main (void) { int i, *p, count } p = &count; = 10%; for (i = 5; i >= 0; i--) { count++; (*p) ++; } printf("count return 0; = %d, Have a wonderful day.\n", count); 1. [20 pts] What is the output of the program? Please explain why. 2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p = &count;)? 3. [15 pts] Explain in your own words how the [break. need to use such command? ... if expr] command works. When might you
Please run and debug the following program and answer the questions.
(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
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