Explanation Given: The functions are g ( x ) = 2 x , x ≠ 0 and h ( x ) = x + 1 x − 4 , x ≠ 4 . Formula used: The division of two functions f ( x ) and g ( x ) , f ( x ) g ( x ) = ( f g ) ( x ) Calculation: Consider the following functions. h ( x ) = x + 1 x − 4 , x ≠ 4 g ( x ) = 2 x , x ≠ 0 Recall the division property, g ( x ) h ( x ) = ( g h ) ( x ) Substitute 2 x for g ( x ) , and x + 1 x − 4 for h ( x ) , ( g h ) (</

8th Edition

ISBN: 9780134178967

Author: John Tobey Jr., Jeffrey Slater, Jamie Blair, Jenny Crawford

Publisher: PEARSON

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Chapter 10, Problem 31RP

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To calculate: The value of (gh)(−2) for functions g(x)=2x,x≠0 and h(x)=x+1x−4,x≠4.

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Chapter 10, Problem 30RP

Chapter 10, Problem 32RP

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Concept Check Explain how you can use a...Ch. 10.3 - Prob. 1E Ch. 10.3 - Prob. 2E Ch. 10.3 - Prob. 3E Ch. 10.3 - Prob. 4E Ch. 10.3 - Prob. 5E Ch. 10.3 - Prob. 6E Ch. 10.3 - Prob. 7E Ch. 10.3 - Prob. 8E Ch. 10.3 - Prob. 9E Ch. 10.3 - For the following functions, find (a) ( f + g ) (...Ch. 10.3 - Prob. 11E Ch. 10.3 - Prob. 12E Ch. 10.3 - Prob. 13E Ch. 10.3 - Prob. 14E Ch. 10.3 - For the following functions, find (a) and (b)...Ch. 10.3 - Prob. 16E Ch. 10.3 - Prob. 17E Ch. 10.3 - Prob. 18E Ch. 10.3 - Prob. 19E Ch. 10.3 - Prob. 20E Ch. 10.3 - Prob. 21E Ch. 10.3 - Prob. 22E Ch. 10.3 - Prob. 23E Ch. 10.3 - Let , and . Find the following: 24. 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The value of ( g h ) ( − 2 ) for functions g ( x ) = 2 x , x ≠ 0 and h ( x ) = x + 1 x − 4 , x ≠ 4 .

Solution Summary: The author explains the formula used to calculate the value of (gh)

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To calculate: The value of (gh)(−2) for functions g(x)=2x,x≠0 and h(x)=x+1x−4,x≠4.

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Chapter 10 Solutions