Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Question
Chapter 10, Problem 2PP
Program Plan Intro
BullsEye
Program plan:
BullsEyeViewer.java:
- Import required package.
- Define the main class “BullsEyeViewer”.
- Declare required variables.
- Declare component for “bullsEyeComponent”.
- Define the constructor for “BullsEyeViewer”.
- Instantiate “bullsEyeComponent”.
- Set the size of the frame
- Set the close operation of the frame.
- Add the component to the frame.
- Set the visibility of the frame to “true”.
- Define the class “BullsEyeComponent”.
- Define the method “paintComponent”.
- Draw the required number of circles and fill the color with black and white alternatively.
- Define the method “paintComponent”.
- Define the main method.
- Instantiate “BullsEyeViewer”.
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 10 Solutions
Big Java Late Objects
Ch. 10.1 - Prob. 1SCCh. 10.1 - Prob. 2SCCh. 10.1 - Prob. 3SCCh. 10.1 - Prob. 4SCCh. 10.1 - Prob. 5SCCh. 10.1 - Prob. 6SCCh. 10.2 - Prob. 7SCCh. 10.2 - Prob. 8SCCh. 10.2 - Prob. 9SCCh. 10.2 - Prob. 10SC
Ch. 10.2 - Prob. 11SCCh. 10.3 - Prob. 12SCCh. 10.3 - Prob. 13SCCh. 10.3 - Prob. 14SCCh. 10.3 - Prob. 15SCCh. 10.3 - Prob. 16SCCh. 10.4 - Prob. 17SCCh. 10.4 - Prob. 18SCCh. 10.4 - Prob. 19SCCh. 10.4 - Prob. 20SCCh. 10.4 - Prob. 21SCCh. 10.4 - Prob. 22SCCh. 10.4 - Prob. 23SCCh. 10.4 - Prob. 24SCCh. 10.4 - Prob. 25SCCh. 10.4 - Prob. 26SCCh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 1PECh. 10 - Prob. 2PECh. 10 - Prob. 3PECh. 10 - Prob. 4PECh. 10 - Prob. 5PECh. 10 - Prob. 6PECh. 10 - Prob. 9PECh. 10 - Prob. 10PECh. 10 - Prob. 11PECh. 10 - Prob. 12PECh. 10 - Prob. 13PECh. 10 - Prob. 14PECh. 10 - Prob. 15PECh. 10 - Prob. 16PECh. 10 - Prob. 17PECh. 10 - Prob. 18PECh. 10 - Prob. 19PECh. 10 - Prob. 1PPCh. 10 - Prob. 2PPCh. 10 - Prob. 3PPCh. 10 - Prob. 4PPCh. 10 - Prob. 5PPCh. 10 - Prob. 7PPCh. 10 - Prob. 8PPCh. 10 - Prob. 9PPCh. 10 - Prob. 10PPCh. 10 - Prob. 14PPCh. 10 - Prob. 16PP
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