Chapter 10, Problem 24E

(a)

To determine

The complete nuclear reaction equation,

$\text{O}+\text{N}\text{e}\to \_\_\_+\text{C}$

Answer to Problem 24E

The complete nuclear reaction equation is $\text{O}+\text{N}\text{e}\to \text{M}\text{g}+\text{C}$.

Explanation of Solution

Total mass number of reactant is $16+20=36$. Mass number of product is shown as $12$. According to conservation of mass number, mass number of reactant is equal to mass number of product. Missing atom must have a mass number of $36-12=24$.

Total atomic number of reactant is $8+10=18$ and shown atomic number of product is $6$. According to conservation of atomic number, the atomic number of reactant and product must be equal. Missing atom must have atomic number of $18-6=12$.

The atom with atomic number $12$ and mass number $24$ is magnesium- $12$ atom.

Conclusion:

Therefore, the complete nuclear reaction equation is $\text{O}+\text{N}\text{e}\to \text{M}\text{g}+\text{C}$.

(b)

To determine

The complete nuclear reaction equation,

$\text{n}+\text{S}\text{i}\to \_\_\_+\text{H}$

Answer to Problem 24E

The complete nuclear reaction equation is $\text{n}+\text{S}\text{i}\to \text{A}\text{l}+\text{H}$.

Explanation of Solution

Total mass number of reactant is $1+28=29$. Mass number of product is shown as $1$. According to conservation of mass number, mass number of reactant is equal to mass number of product. Missing atom must have a mass number of $29-1=28$.

Total atomic number of reactant is $0+14=14$ and shown atomic number of product is $1$. According to conservation of atomic number, the atomic number of reactant and product must be equal. Missing atom must have atomic number of $14-1=13$.

The atom with atomic number $13$ and mass number $28$ is isotope of aluminium- $13$ atom.

Conclusion:

Therefore, the complete nuclear reaction equation is $\text{n}+\text{S}\text{i}\to \text{A}\text{l}+\text{H}$.

(c)

To determine

The complete nuclear reaction equation,

$\_\_\_+\text{T}\text{h}\to \text{F}\text{r}+2\text{H}\text{e}$

Answer to Problem 24E

The complete nuclear reaction equation is $\text{H}+\text{T}\text{h}\to \text{F}\text{r}+2\text{H}\text{e}$.

Explanation of Solution

Total mass number of reactant is shown as $230$. Total mass number of product is $223+2\left(4\right)=231$. According to conservation of mass number, mass number of reactant is equal to mass number of product. Missing atom must have a mass number of $231-230=1$.

Total atomic number of reactant is shown as $90$ and total atomic number of product is $87+2\left(2\right)=91$. According to conservation of atomic number, the atomic number of reactant and product must be equal. Missing atom must have atomic number of $91-90=1$.

The atom with atomic number $1$ and mass number $1$ is Hydrogen atom.

Conclusion:

Therefore, the complete nuclear reaction equation is $\text{H}+\text{T}\text{h}\to \text{F}\text{r}+2\text{H}\text{e}$.

(d)

To determine

The complete nuclear reaction equation,

$\text{C}\text{m}+\text{C}\to \_\_\_+4\text{n}$

Answer to Problem 24E

The complete nuclear reaction equation is $\text{C}\text{m}+\text{C}\to \text{N}\text{o}+4\text{n}$.

Explanation of Solution

Total mass number of reactant is $246+12=258$. Mass number of product is shown as $4\left(1\right)=4$. According to conservation of mass number, mass number of reactant is equal to mass number of product. Missing atom must have a mass number of $258-4=254$.

Total atomic number of reactant is $96+6=102$ and shown atomic number of product is $0$. According to conservation of atomic number, the atomic number of reactant and product must be equal. Missing atom must have atomic number of $102-0=102$.

The atom with atomic number $102$ and mass number $254$ is isotope of nobelium- $102$ atom.

Conclusion:

Therefore, the complete nuclear reaction equation is $\text{C}\text{m}+\text{C}\to \text{N}\text{o}+4\text{n}$.