Engineering Fundamentals: An Introduction to Engineering
Engineering Fundamentals: An Introduction to Engineering
6th Edition
ISBN: 9780357391273
Author: Saeed Moaveni
Publisher: Cengage Learning US
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Chapter 10, Problem 21P
To determine

Convert the systolic/diastolic of 115/85 mm of Hg into Pa, psi and inH2O.

Expert Solution & Answer
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Answer to Problem 21P

The systolic pressure from 115 mmHg to Pa is 15,322 kPa, to psi is 2.2 psi, and to inH2O is 61.42 inH2O.

The diastolic pressure from 85 mmHg to Pa is 11.322 kPa, to psi is 1.64 psi, and to inH2O is 45.27 inH2O.

Explanation of Solution

Given data:

A systolic pressure is 115 mmHg.

A diastolic pressure is 85mmHg.

Formula used:

Formula to determine the gauge pressure is,

P=ρgh (1)

Here,

ρ is the density.

g is the gravitational constant.

h is the height of the fluid column.

Calculation:

Case 1:

Conversion for 115 mm Hg to Pa:

P=115×133.322Pa                                 [1mmHg = 133.322Pa]=15,332Pa=15.322×103Pa=15.322kPa

Conversion for 115 mm Hg to psi:

1 mm of Hg is equal to 0.0193368 psi. Therefore,

P=(115)(0.0193368 psi)=2.22psi

Conversion for 115 mm Hg to inch of water:

Substitute 1000kgm3 for ρ, 15.332 kPa for P, and 9.81ms2 for g in equation (1) to find the height of the fluid column h.

15.322kPa=(1000kgm3)(9.81ms2)(h)h=(15.322kPa)(9810kgm3×ms2)                                    =(15.322kPa)(98101m3×kgms2)                         [1N=1kgms2]               =(15.322kPa)(98101m3×N)

Reduce the equation as follows,

h=(15.322kPa)(98101m×Nm2)                                      [1Pa=1Nm2]=(15.322kPa)(98101m×Pa)=1.56m

Converting the height of fluid column (h=1.56m) of systolic pressure to inch of water as,

P=1.56×39.37in                                        [1m=39.37in]=61.42in.ofH2O

Case 2:

Conversion for 85 mm Hg to Pa:

P=85×133.322Pa                            [1mmHg = 133.322Pa]=11332Pa=11.332×103Pa=11.332kPa

Conversion for 85 mm Hg to psi:

1 mm of Hg is equal to 0.0193368 psi. Therefore,

P=(85)(0.0193368 psi)=1.64psi

Conversion for 85 mm Hg to inch of water:

Substitute 1000kgm3 for ρ, 11.332 kPa for P, and 9.81ms2 for g in equation (1) to find the height of the fluid column h.

11.332kPa=(1000kgm3)(9.81ms2)(h)h=(11,322kPa)(9810kgm3×ms2)                                    =(11,322kPa)(98101m3×kgms2)                        [1N=1kgms2]               =(11.322kPa)(98101m3×N)

Reduce the equation as follows,

h=(11.322kPa)(98101m×Nm2)                              [1Pa=1Nm2]=(11.322kPa)(98101m×Pa)=1.15m

Converting the height of fluid column (h=1.15m) of diastolic pressure to inch of water as,

P=1.15×39.37in                                   [1m=39.37in]=45.27in.ofH2O

Conclusion:

Hence, the conversion for systolic/diastolic of 115/85 mm Hg is explained.

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Chapter 10 Solutions

Engineering Fundamentals: An Introduction to Engineering

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