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Concept explainers
(a)
Interpretation:
Concept Introduction:
The atomic number of an atom is equal to the number of protons in it. The atomic number is represented by Z.
![Check Mark](/static/check-mark.png)
Answer to Problem 20P
The atomic number for isotope of nitrogen A and B is 7.
Explanation of Solution
In the molecular model of fluorine, blue balls represent protons, whereas orange balls represent neutrons. Since the number of protons from given molecular model A and B is 7, the atomic number becomes 7 for A and B in both cases, as the atomic number is equal to the number of protons in that atom.
(b)
Interpretation:
The mass number for each isotope of nitrogen A and B given below should be predicted.
Concept Introduction:
The mass number is equal to the number of protons and neutrons in an atom.
![Check Mark](/static/check-mark.png)
Answer to Problem 20P
The mass number for isotope of nitrogen A and B is 14 and 13 respectively.
Explanation of Solution
From the molecular model of an isotope of nitrogen, the number of neutrons can be counted. Thus, the number of neutrons in A and B is 7 and 6 respectively.
As
For A and B, the mass number will be calculated as follows:
(c)
Interpretation:
The number of protons for each isotope of nitrogen A and B given below should be predicted.
Concept Introduction:
The number of protons is equal to the atomic number of that atom.
![Check Mark](/static/check-mark.png)
Answer to Problem 20P
The number of protons in isotope of nitrogen A and B is 7.
Explanation of Solution
As the number of protons is equal to the atomic number in an atom. The atomic number of an isotope of nitrogen of A and B is 7. Thus, the number of protons in A and B will be 7.
(d)
Interpretation:
The number of neutrons for each isotope of nitrogen A and B given below should be predicted.
Concept Introduction:
The mass number is the sum of all the protons and neutrons present in an atom. Thus, the number of neutrons can be calculated simply by subtracting the number of protons from the mass number of that atom.
![Check Mark](/static/check-mark.png)
Answer to Problem 20P
The number of neutrons in A and B is 7 and 6 respectively.
Explanation of Solution
For A the mass number and number of protons are 14 and 7 respectively. Thus, the number of neutrons in A will be calculated as follows:
For B the mass number and number of protons are 13 and 7 respectively. Thus, the number of neutrons in B will be calculated as follows:
(e)
Interpretation:
The isotope symbol for each isotope of nitrogen A and B given below should be predicted.
Concept Introduction:
Isotopes are the compounds having the same atomic number but different
To write an isotope symbol atomic number (Z) is written on the lower left side and atomic mass(A) is written on the upper left side of an element.
![Check Mark](/static/check-mark.png)
Answer to Problem 20P
The isotope symbol for A and B is
Explanation of Solution
For A, the mass number and atomic number are 14 and 7 respectively. Thus, the isotope symbol for A will be represented as follows:
For B, the mass number and atomic number are 13 and 7 respectively. Thus, the isotope symbol for B will be represented as follows:
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Chapter 10 Solutions
General, Organic, and Biological Chemistry - 4th edition
- X Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forward
- Nonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forward
- Predict and draw the product of the following organic reaction:arrow_forwardNonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forward
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