Physical Universe
15th Edition
ISBN: 9780077510534
Author: KRAUSKOPF
Publisher: Mcgraw-hill Higher Education (us)
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 10, Problem 1MC
To determine
The correct option from given set of options.
Expert Solution & Answer
Answer to Problem 1MC
The correct option is “a. an element”
Explanation of Solution
All matter in the universe is made up of atoms. Compounds can be broken down into simpler substance known as elements. While, elements cannot be further broken down or decomposed further by chemical or physical means. Elements comprises of atoms of same type.
Conclusion:
Therefore from the above explanation, we can find that option a will be the best choice among the given options.
A compound can be broken down into elements by
A solid can be or cannot be a pure substance. If the solid is made up of two or more elements then it can be decomposed further by chemical means and hence option c is an incorrect one.
A solution is made up of solvent and solute. Therefore, it can also be decomposed further by chemical means and hence option d is an incorrect one.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
If a 1/2 inch diameter drill bit spins at 3000 rotations per minute, how fast is the outer edge moving as it contacts a piece of metal while drilling a machine part?
Need help with the third question (C)A gymnast weighing 68 kg attempts a handstand using only one arm. He plants his hand at an angl reesulting in the reaction force shown.
Q: What is the direction of the force on the current carrying conductor in the
magnetic field in each of the cases 1 to 8 shown below?
(1)
B
B
B into page
X X X
x
X X X X
(2)
B
11 -10°
B
x I
B
I out of page
(3)
I into page
(4)
B out of page
out of page
I
N
N
S
x X X X
I
X
X X X
I
(5)
(6)
(7)
(8)
S
Chapter 10 Solutions
Physical Universe
Ch. 10 - Prob. 1MCCh. 10 - Prob. 2MCCh. 10 - Prob. 3MCCh. 10 - Prob. 4MCCh. 10 - Prob. 5MCCh. 10 - Prob. 6MCCh. 10 - Prob. 7MCCh. 10 - Prob. 8MCCh. 10 - Prob. 9MCCh. 10 - Prob. 10MC
Ch. 10 - Prob. 11MCCh. 10 - Prob. 12MCCh. 10 - Prob. 13MCCh. 10 - Prob. 14MCCh. 10 - Prob. 15MCCh. 10 - Prob. 16MCCh. 10 - Prob. 17MCCh. 10 - Prob. 18MCCh. 10 - Prob. 19MCCh. 10 - Prob. 20MCCh. 10 - Prob. 21MCCh. 10 - Prob. 22MCCh. 10 - Prob. 23MCCh. 10 - Prob. 24MCCh. 10 - Prob. 25MCCh. 10 - Prob. 26MCCh. 10 - Prob. 27MCCh. 10 - Prob. 28MCCh. 10 - Prob. 29MCCh. 10 - Prob. 30MCCh. 10 - Prob. 31MCCh. 10 - Prob. 32MCCh. 10 - Prob. 33MCCh. 10 - Prob. 34MCCh. 10 - Prob. 35MCCh. 10 - Prob. 36MCCh. 10 - Prob. 37MCCh. 10 - Prob. 38MCCh. 10 - Prob. 39MCCh. 10 - Prob. 40MCCh. 10 - Prob. 1ECh. 10 - Prob. 2ECh. 10 - Prob. 3ECh. 10 - Prob. 4ECh. 10 - Prob. 5ECh. 10 - Prob. 6ECh. 10 - Prob. 7ECh. 10 - Prob. 8ECh. 10 - Prob. 9ECh. 10 - Prob. 10ECh. 10 - Prob. 11ECh. 10 - The Bronze Age got its name from the ability of...Ch. 10 - Prob. 13ECh. 10 - What energy change would you expect when a...Ch. 10 - Prob. 15ECh. 10 - Prob. 16ECh. 10 - Prob. 17ECh. 10 - Prob. 18ECh. 10 - Prob. 19ECh. 10 - Prob. 20ECh. 10 - Prob. 21ECh. 10 - Prob. 22ECh. 10 - Prob. 23ECh. 10 - Prob. 24ECh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - Prob. 33ECh. 10 - Prob. 34ECh. 10 - Prob. 35ECh. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - How many atoms of which elements are present in a...Ch. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - Prob. 54ECh. 10 - Prob. 55ECh. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Q: What is the direction of the magnetic field at point A, due to the current I in a wire, in each of the cases 1 to 6 shown below? Note: point A is in the plane of the page. ▪A I I ▪A (1) (2) ▪A • I (out of page) (3) ▪A I x I (into page) ▪A ▪A I (4) (5) (6)arrow_forwardA tennis ball is thrown into the air with initial speed vo=46 m/s and angle (theta) 38 degrees from the ground. Find the distance it travels (x) when it hits the ground.arrow_forwardProblem 04.08 (17 points). Answer the following questions related to the figure below. ථි R₁ www R₂ E R₁ www ли R₁ A Use Kirchhoff's laws to calculate the currents through each battery and resistor in terms of R1, R2, E1, & E2. B Given that all the resistances and EMFs have positive values, if E₁ > E2 and R₁ > R2, which direction is the current flowing through E₁? Through R₂? C If E1 E2 and R₁ > R2, which direction is the current flowing through E₁? Through R2?arrow_forward
- A 105- and a 45.0-Q resistor are connected in parallel. When this combination is connected across a battery, the current delivered by the battery is 0.268 A. When the 45.0-resistor is disconnected, the current from the battery drops to 0.0840 A. Determine (a) the emf and (b) the internal resistance of the battery. 10 R2 R₁ ww R₁ Emf 14 Emf Final circuit Initial circuitarrow_forwardA ball is shot at an angle of 60° with the ground. What should be the initial velocity of the ball so that it will go inside the ring 8 meters away and 3 meters high. Suppose that you want the ball to be scored exactly at the buzzer, determine the required time to throw and shoot the ball. Full solution and figure if there is.arrow_forwardCorrect answer please. I will upvote.arrow_forward
- Define operational amplifierarrow_forwardA bungee jumper plans to bungee jump from a bridge 64.0 m above the ground. He plans to use a uniform elastic cord, tied to a harness around his body, to stop his fall at a point 6.00 m above the water. Model his body as a particle and the cord as having negligible mass and obeying Hooke's law. In a preliminary test he finds that when hanging at rest from a 5.00 m length of the cord, his body weight stretches it by 1.55 m. He will drop from rest at the point where the top end of a longer section of the cord is attached to the bridge. (a) What length of cord should he use? Use subscripts 1 and 2 respectively to represent the 5.00 m test length and the actual jump length. Use Hooke's law F = KAL and the fact that the change in length AL for a given force is proportional the length L (AL = CL), to determine the force constant for the test case and for the jump case. Use conservation of mechanical energy to determine the length of the rope. m (b) What maximum acceleration will he…arrow_forward9 V 300 Ω www 100 Ω 200 Ω www 400 Ω 500 Ω www 600 Ω ww 700 Ω Figure 1: Circuit symbols for a variety of useful circuit elements Problem 04.07 (17 points). Answer the following questions related to the figure below. A What is the equivalent resistance of the network of resistors in the circuit below? B If the battery has an EMF of 9V and is considered as an ideal batter (internal resistance is zero), how much current flows through it in this circuit? C If the 9V EMF battery has an internal resistance of 2 2, would this current be larger or smaller? By how much? D In the ideal battery case, calculate the current through and the voltage across each resistor in the circuit.arrow_forward
- helparrow_forwardIf the block does reach point B, how far up the curved portion of the track does it reach, and if it does not, how far short of point B does the block come to a stop? (Enter your answer in m.)arrow_forwardTruck suspensions often have "helper springs" that engage at high loads. One such arrangement is a leaf spring with a helper coil spring mounted on the axle, as shown in the figure below. When the main leaf spring is compressed by distance yo, the helper spring engages and then helps to support any additional load. Suppose the leaf spring constant is 5.05 × 105 N/m, the helper spring constant is 3.50 × 105 N/m, and y = 0.500 m. Truck body yo Main leaf spring -"Helper" spring Axle (a) What is the compression of the leaf spring for a load of 6.00 × 105 N? Your response differs from the correct answer by more than 10%. Double check your calculations. m (b) How much work is done in compressing the springs? ☑ Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. Jarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning