When one object is a specialized version of another object, there is an_________ between them. a. “is a” relationship b. innate association c. inherent union d. unbreakable union

Question

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Answer 1

Textbook Question

Chapter 10, Problem 1MC

When one object is a specialized version of another object, there is an_________ between them.

a. “is a” relationship
b. innate association
c. inherent union
d. unbreakable union

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

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Answer 2

Textbook Question

Chapter 10, Problem 1MC

When one object is a specialized version of another object, there is an_________ between them.

a. “is a” relationship
b. innate association
c. inherent union
d. unbreakable union

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 10, Problem 1MC

When one object is a specialized version of another object, there is an_________ between them.

a. “is a” relationship
b. innate association
c. inherent union
d. unbreakable union

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

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Answer 4

Textbook Question

Chapter 10, Problem 1MC

When one object is a specialized version of another object, there is an_________ between them.

a. “is a” relationship
b. innate association
c. inherent union
d. unbreakable union

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

Answer 8

Expert Solution & Answer

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Program Description Answer

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.

Hence, the correct answer is option “A”.

Answer 12

Explanation of Solution

“is a” relationship:

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.

For example:

• A truck is a vehicle.
• A circle is a shape.

Form the above example,

• The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
• Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.

Explanation for incorrect options:

Innate association:

The innate association is not a “is a” relationship among those objects.

Hence, the option “B” is wrong.

Inherent union:

The inherent union is not a “is a” relationship among those objects.

Hence, the option “C” is wrong.

Unbreakable union:

The unbreakable union is not a “is a” relationship among those objects.

Hence, the option “D” is wrong.