
When one object is a specialized version of another object, there is an_________ between them.
- a. “is a” relationship
- b. innate association
- c. inherent union
- d. unbreakable union

In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects.
Hence, the correct answer is option “A”.
Explanation of Solution
“is a” relationship:
In C#, if one object is a specialized type of another object, then there should be an “is a” relationship between those objects. This is used to create the “is a” relationship among several classes.
For example:
- • A truck is a vehicle.
- • A circle is a shape.
Form the above example,
- • The first statement implies that the vehicle is a “base class” and truck is the “derived class”.
- ○ The “vehicle” is the parent of the “truck” in inheritance tree.
- • Similarly, second statement implies that the shape is a “base class” and “circle” is the “derived class”.
- ○ The “shape” is the parent of the “circle” in inheritance tree.
Explanation for incorrect options:
Innate association:
The innate association is not a “is a” relationship among those objects.
Hence, the option “B” is wrong.
Inherent union:
The inherent union is not a “is a” relationship among those objects.
Hence, the option “C” is wrong.
Unbreakable union:
The unbreakable union is not a “is a” relationship among those objects.
Hence, the option “D” is wrong.
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