the means and standard deviations for API and growth scores

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Answer 1

Question

Chapter 10, Problem 1CS

To determine

To find: the means and standard deviations for API and growth scores

Expert Solution & Answer

Answer to Problem 1CS

In Alvord district:

Statistic	Mean	Standard deviation
API	756.42	40.08
Growth	271	17.95

In Riverside unified district:

Statistic	Mean	Standard deviation
API	806.85	43.12
Growth	14.78	12.67

Explanation of Solution

Given:

API and the growth scores for each of the two districts

Calculation:

Let’s find out means and standard deviations for API and growth scores for each of the two districts

API (1= Alvord schools and 2= riverside unified schools)

The mean is the sum of all values divided by the number of values:

x1¯=786+760+768+745+731+815+6907=756.4286x2¯= 891+778+827+789+805+762+798+ 796+731+818+769+815+841+87614=806.8571

The sample standard deviation is the square root of the population sample

s1= ( 786−756.4 ) 2 + ( 760−756.4 ) 2 + ( 768−756.4 ) 2 + ( 745−756.4 ) 2 + ( 731−756.4 ) 2 + ( 815−756.4 ) 2 + ( 690−756.4 ) 2 7−1=40.08

s2= ( 891−806.85 ) 2 + ( 778−806.85 ) 2 + ( 827−806.85 ) 2 + ( 789−806.85 ) 2 + ( 805−806.85 ) 2 + ( 762−806.85 ) 2 + ( 798−806.85 ) 2 + ( 796−806.85 ) 2 + ( 731−806.85 ) 2 + ( 818−806.85 ) 2 + ( 769−806.85 ) 2 + ( 815−806.85 ) 2 + ( 841−806.85 ) 2 + ( 876−806.85 ) 2 14−1=43.12

Growth (1= Alvord schools and 2 = riverside unified schools)

x1¯=−5−2+8+40−6+0−157=2.7143x2¯= 18+8+10+23+28+6+35+ 34−4+28+3+7+8+314=14.7857

The sample standard deviation is the square root of the population sample

s1= ( −5−2.71 ) 2 + ( −2−2.71 ) 2 + ( 8−2.71 ) 2 + ( 40−2.71 ) 2 + ( −6−2.71 ) 2 + ( 0−2.71 ) 2 + ( −16−2.71 ) 2 7−1=17.9510s2= ( 18−14.78 ) 2 + ( 8−14.78 ) 2 + ( 10−14.78 ) 2 + ( 23−14.78 ) 2 + ( 28−14.78 ) 2 + ( 6−14.78 ) 2 + ( 35−14.78 ) 2 + ( 34−14.78 ) 2 + ( −4−14.78 ) 2 + ( 28−14.78 ) 2 + ( 3−14.78 ) 2 + ( 7−14.78 ) 2 + ( 8−14.78 ) 2 + ( 3−14.78 ) 2 14−1=12.6745

In Alvord district:

Statistic	Mean	Standard deviation
API	756.42	40.08
Growth	271	17.95

In Riverside unified district:

Statistic	Mean	Standard deviation
API	806.85	43.12
Growth	14.78	12.67

Conclusion:

Therefore, means and standard deviations for API and growth scoresare done

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Answer 2

Question

Chapter 10, Problem 1CS

To determine

To find: the means and standard deviations for API and growth scores

Expert Solution & Answer

Answer to Problem 1CS

In Alvord district:

Statistic	Mean	Standard deviation
API	756.42	40.08
Growth	271	17.95

In Riverside unified district:

Statistic	Mean	Standard deviation
API	806.85	43.12
Growth	14.78	12.67