Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
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Chapter 10, Problem 13PE

(a)

Interpretation Introduction

Interpretation:

The orbital diagram (a) is correct or incorrect have to be identified

Concept Introduction:

Aufbau’s principle:

Aufbau’s principle states that electrons are filled into atomic orbitals in the increasing order of orbital energy level.  According to the Aufbau principle the available atomic orbitals with the lowest energy levels are occupied before those with higher energy levels.

Foundations of College Chemistry, Binder Ready Version, Chapter 10, Problem 13PE

Figure 1

Hund’s Rule:

According to Hund’s rule every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied and all electrons in singly occupied orbitals have the same spin.

(b)

Interpretation Introduction

Interpretation:

The orbital diagram (b) is correct or incorrect have to be identified.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The orbital diagram (c) is correct or incorrect have to be identified.

Concept Introduction:

Refer to part (a).

(d)

Interpretation Introduction

Interpretation:

The orbital diagram (d) is correct or incorrect have to be identified.

Concept Introduction:

Refer to part (a).

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Heparin is used as an anti-coagulant. A risk of heparin use is thrombocytopenia, or low platelet count. This risk is minimized with the use of low molecular weight heparins (LMWH), therefore it is desirable to separate LMWH from higher molecular weight heparins. The method of choice to do this is molecular exclusion chromatography. Below is a chromatogram from a molecular exclusion chromatographic run. Peaks ranging from A to J are clearly distinguishable. The heparin mixture that was analyzed had anywhere from 6 to 30 repeat units of monomer (where the heparin with 30 repeat units would be roughly five times the size of the heparin with six repeat units). a. Which letter most likely represents the peak with 6 repeat units given these heparin polymers were separated with molecular exclusion chromatography? b. Explain your reasoning describing the mechanism of retention in molecular exclusion chromatography. 100 80 60 60 Relative Abundance 40 40 E GH 20 20 B A 36 38 40 42 44 46 48 50 50…
HELP NOW PLEASE ! URGENT!

Chapter 10 Solutions

Foundations of College Chemistry, Binder Ready Version

Ch. 10 - Prob. 4RQCh. 10 - Prob. 5RQCh. 10 - Prob. 6RQCh. 10 - Prob. 7RQCh. 10 - Prob. 8RQCh. 10 - Prob. 9RQCh. 10 - Prob. 10RQCh. 10 - Prob. 11RQCh. 10 - Prob. 12RQCh. 10 - Prob. 13RQCh. 10 - Prob. 14RQCh. 10 - Prob. 15RQCh. 10 - Prob. 16RQCh. 10 - Prob. 17RQCh. 10 - Prob. 18RQCh. 10 - Prob. 19RQCh. 10 - Prob. 20RQCh. 10 - Prob. 21RQCh. 10 - Prob. 22RQCh. 10 - Prob. 23RQCh. 10 - Prob. 24RQCh. 10 - Prob. 25RQCh. 10 - Prob. 1PECh. 10 - Prob. 2PECh. 10 - Prob. 3PECh. 10 - Prob. 4PECh. 10 - Prob. 5PECh. 10 - Prob. 6PECh. 10 - Prob. 7PECh. 10 - Prob. 8PECh. 10 - Prob. 9PECh. 10 - Prob. 10PECh. 10 - Prob. 11PECh. 10 - Prob. 12PECh. 10 - Prob. 13PECh. 10 - Prob. 14PECh. 10 - Prob. 15PECh. 10 - Prob. 16PECh. 10 - Prob. 17PECh. 10 - Prob. 18PECh. 10 - Prob. 19PECh. 10 - Prob. 20PECh. 10 - Prob. 21PECh. 10 - Prob. 22PECh. 10 - Prob. 23PECh. 10 - Prob. 24PECh. 10 - Prob. 25PECh. 10 - Prob. 26PECh. 10 - Prob. 27PECh. 10 - Prob. 28PECh. 10 - Prob. 29PECh. 10 - Prob. 30PECh. 10 - Prob. 31PECh. 10 - Prob. 32PECh. 10 - Prob. 33PECh. 10 - Prob. 34PECh. 10 - Prob. 35PECh. 10 - Prob. 36PECh. 10 - Prob. 37PECh. 10 - Prob. 38PECh. 10 - Prob. 39PECh. 10 - Prob. 40PECh. 10 - Prob. 41PECh. 10 - Prob. 42PECh. 10 - Prob. 43PECh. 10 - Prob. 44PECh. 10 - Prob. 45PECh. 10 - Prob. 46PECh. 10 - Prob. 47PECh. 10 - Prob. 48PECh. 10 - Prob. 49PECh. 10 - Prob. 50PECh. 10 - Prob. 51AECh. 10 - Prob. 52AECh. 10 - Prob. 53AECh. 10 - Prob. 54AECh. 10 - Prob. 57AECh. 10 - Prob. 58AECh. 10 - Prob. 59AECh. 10 - Prob. 60AECh. 10 - Prob. 61AECh. 10 - Prob. 62AECh. 10 - Prob. 63AECh. 10 - Prob. 64AECh. 10 - Prob. 65AECh. 10 - Prob. 66AECh. 10 - Prob. 67AECh. 10 - Prob. 68AECh. 10 - Prob. 69AECh. 10 - Prob. 70AECh. 10 - Prob. 71AECh. 10 - Prob. 72AECh. 10 - Prob. 73AECh. 10 - Prob. 74AECh. 10 - Prob. 75AECh. 10 - Prob. 76AECh. 10 - Prob. 77AECh. 10 - Prob. 78CECh. 10 - Prob. 79CECh. 10 - Prob. 80CECh. 10 - Prob. 81CECh. 10 - Prob. 82CE
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY