Concept explainers
(a)
Interpretation:
The nuclear binding energy of nickel-62 nucleus has to be given.
Concept Introduction:
Nuclear binding energy and the mass defect:
Nuclear binding energy is the minimum energy that would be required to disassemble the nucleus of an atom into its component parts. These component parts are neutrons and protons which are collectively called nucleons. The mass of an atomic nucleus is less than the sum of the individual masses of the free constituent protons and neutrons according to Einstein’s equation
(a)

Answer to Problem 10C.3E
The binding energy of the carbon nucleus is
Explanation of Solution
Given:
The mass of nickel-62 is
The mass of neutron is
The mass of proton is
The mass of an electron is
The mass defect can be calculated as,
The binding energy of the carbon nucleus is,
The binding energy of the Nickel-62 nucleus is
(b)
Interpretation:
The binding energy of Plutonium-239 has to be given.
Concept Introduction:
Refer to part (a).
(b)

Answer to Problem 10C.3E
The binding energy of the plutonium-239 nucleus is
Explanation of Solution
Given:
The mass of plutonium is
The mass of neutron is
The mass of proton is
The mass of an electron is
The mass defect can be calculated as,
The binding energy of the carbon nucleus is,
The binding energy of the plutonium-239 nucleus is
(c)
Interpretation:
The binding energy of Deuterium has to be given.
Concept Introduction:
Refer to part (a).
(c)

Answer to Problem 10C.3E
The binding energy of the Deuterium nucleus is
Explanation of Solution
Given:
The mass of Deuterium is
The mass of neutron is
The mass of proton is
The mass of an electron is
The mass defect can be calculated as,
The binding energy of the carbon nucleus is,
The binding energy of the Deuterium nucleus is
(d)
Interpretation:
The binding energy of tritium-3 has to be given.
Concept Introduction:
Refer to part (a).
(d)

Answer to Problem 10C.3E
The binding energy of the tritium nucleus is
Explanation of Solution
Given:
The mass of Tritium is
The mass of neutron is
The mass of proton is
The mass of an electron is
The mass defect can be calculated as,
The binding energy of the carbon nucleus is,
The binding energy of the Deuterium nucleus is
(e)
Interpretation:
The most stable nuclide has to be given.
Concept Introduction:
The binding energy is directly proportional to the stability of the nuclide. Thus, greater the binding energy greater will be the stability of the nucleus.
(e)

Answer to Problem 10C.3E
Nickel -62 is the most stable nucleus.
Explanation of Solution
Since, the binding energy of the nickel-62 is greater it is the most stable nucleus.
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Chapter 10 Solutions
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