Elements of Physical Chemistry
Elements of Physical Chemistry
7th Edition
ISBN: 9780192522764
Author: Peter Atkins; Julio de Paula
Publisher: Oxford University Press Academic UK
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Chapter 10, Problem 10A.5E

(a)

Interpretation Introduction

Interpretation:

The units of polarizability, α has to be given.

Concept introduction:

Polar covalent bond involves an unequal sharing of electrons between two bonded atoms; it creates a partial separation of charge and a dipole moment.

Covalent bonds are polar, if there is a difference in electronegativity between the bonded atoms.

Direction of dipole moment in a molecule is can be represented as follows,

  Positive  Negative

(b)

Interpretation Introduction

Interpretation:

The units of polarizability volume can be expressed in m3 has to be proven.

Concept introduction:

Polar covalent bond involves an unequal sharing of electrons between two bonded atoms; it creates a partial separation of charge and a dipole moment.

Covalent bonds are polar, if there is a difference in electronegativity between the bonded atoms.

Direction of dipole moment in a molecule is can be represented as follows,

  Positive  Negative

Calculation of the polarizability volume:

  α'=α4πε0α'-Polarizabilityvolumeα-Polarizabilityε0-8.854×10-12J-1C2m-1

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Potential Energy (kJ) 1. Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. AH = -950 kJ AH = 575 kJ (i) Cl₂ (g) + Pt (s) 2C1 (g) + Pt (s) Ea = 1550 kJ (ii) Cl (g)+ CO (g) + Pt (s) → CICO (g) + Pt (s) (iii) Cl (g) + CICO (g) → Cl₂CO (g) Ea = 2240 kJ Ea = 2350 kJ AH = -825 kJ 2600 2400 2200 2000 1800 1600 1400 1200 1000 a. Draw the potential energy diagram for the reaction. Label the data points for clarity. The potential energy of the reactants is 600 kJ 800 600 400 200 0 -200- -400 -600- -800- Reaction Progress
Can u help me figure out the reaction mechanisms for these, idk where to even start
Hi, I need your help with the drawing, please. I have attached the question along with my lab instructions. Please use the reaction from the lab only, as we are not allowed to use outside sources. Thank you!
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