EBK APPLIED FLUID MECHANICS
7th Edition
ISBN: 8220100668340
Author: UNTENER
Publisher: PEARSON
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Textbook Question
Chapter 10, Problem 10.9PP
Plot a graph of energy loss versus cone angle for the results of Problem 10.8.
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Qu 3 Nickel (Ni) single crystal turbine blades burn less fuel at higher temperatures because blades are grown on [110] closed packed direction. Nickel (Ni) at 20°C is FCC, and has an atomic radius, R, of 0.125 nm. Draw a reduced-sphere unit cell for this crystal and draw and label the vector [I 10], starting from the origin (0, 0, 0).
a) Calculate the length of the vector [| 10] in nanometers. Express your answer in nanometers to one significant figure.
b) Calculate the linear density of Nickel in the [| 1 0] direction in [atom/nm]. Express your answer in atoms/nm to one significant figure.
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Chapter 10 Solutions
EBK APPLIED FLUID MECHANICS
Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the pressure difference between two...Ch. 10 - Determine the pressure difference for the...Ch. 10 - Determine the energy loss due to a gradual...Ch. 10 - Determine the energy loss for the conditions in...Ch. 10 - Compute the energy loss for gradual enlargements...Ch. 10 - Plot a graph of energy loss versus cone angle for...Ch. 10 - For the data in Problem 10.8, compute the length...
Ch. 10 - Add the energy loss due to friction from Problem...Ch. 10 - Another term for an enlargement is a diffuser. A...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Determine the energy loss when 0.04m3/s of water...Ch. 10 - Determine the energy loss when 1.50ft3/s of water...Ch. 10 - Determine the energy loss when oil with a specific...Ch. 10 - For the conditions in Problem 10.17, if the...Ch. 10 - True or false: For a sudden contraction with a...Ch. 10 - Determine the energy loss for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - Determine the energy lass for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - For the data in Problem 10.22, compute the energy...Ch. 10 - For each contraction described in Problems 10.22...Ch. 10 - Note in Figs. 10.10 and 10.11 that the minimum...Ch. 10 - If the contraction from a 6-in to a 3-in ductile...Ch. 10 - Compute the energy loss that would occur as 50...Ch. 10 - Determine the energy loss that will occur if water...Ch. 10 - Determine the equivalent length in meters of pipe...Ch. 10 - Repeat Problem 10.30 for a fully open gate valve.Ch. 10 - Calculate the resistance coefficient K for a...Ch. 10 - Calculate the pressure difference across a fully...Ch. 10 - Determine the pressure drop across a 90 C standard...Ch. 10 - Prob. 10.35PPCh. 10 - Repeat Problem 10.34 for a long radius elbow....Ch. 10 - A simple heat exchanger is made by installing a...Ch. 10 - A proposed alternate form for the heat exchanger...Ch. 10 - A piping system for a pump contains a tee, as...Ch. 10 - A piping system for supplying heavy fuel oil at 25...Ch. 10 - A 25 mm ODx2.0 mm wall copper tube supplies hot...Ch. 10 - Specify the radius in mm to the centerline of a 90...Ch. 10 - The inlet and the outlet shown in Fig. 10.36 are...Ch. 10 - Compare the energy losses for the two proposals...Ch. 10 - Determine the energy loss that occurs as 40 L/min...Ch. 10 - Figure 10.38 shows a test setup for determining...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - For the data in Problem 10.47, compute the...Ch. 10 - For the data in Problem 10.48, compute the...Ch. 10 - A tube similar to that in Problem 10.47 is being...Ch. 10 - Prob. 10.52PPCh. 10 - Prob. 10.53PPCh. 10 - Prob. 10.54PPCh. 10 - Prob. 10.55PPCh. 10 - Repeat Problem 10.55 for flow rates of 7.5 gal/min...Ch. 10 - Prob. 10.57PPCh. 10 - Prob. 10.58PPCh. 10 - Prob. 10.59PPCh. 10 - Prob. 10.60PPCh. 10 - A 34 plastic ball valve carries 15 gal/min of...Ch. 10 - A 114 plastic butterfly valve carries 60 gal/min...Ch. 10 - A 3 -in plastic butterfly valve carries 300...Ch. 10 - A 10-in plastic butterfly valve carries 5000...Ch. 10 - A 1 12 plastic diaphragm valve carries 60 gal/min...Ch. 10 - Prob. 10.66PPCh. 10 - Prob. 10.67PPCh. 10 - Prob. 10.68PPCh. 10 - Prob. 10.69PPCh. 10 - An 8 -in plastic swing check valve carries 3500...Ch. 10 - Use PIPE-FLO software to determine the pressure...Ch. 10 - Use PIPE-FLO to calculate the head loss and...
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- Problem 6 (Optional, extra 6 points) 150 mm 150 mm 120 mm 80 mm 60 mm PROBLEM 18.103 A 2.5 kg homogeneous disk of radius 80 mm rotates with an angular velocity ₁ with respect to arm ABC, which is welded to a shaft DCE rotating as shown at the constant rate w212 rad/s. Friction in the bearing at A causes ₁ to decrease at the rate of 15 rad/s². Determine the dynamic reactions at D and E at a time when ₁ has decreased to 50 rad/s. Answer: 5=-22.01 +26.8} N E=-21.2-5.20Ĵ Narrow_forwardProblem 1. Two uniform rods AB and CE, each of weight 3 lb and length 2 ft, are welded to each other at their midpoints. Knowing that this assembly has an angular velocity of constant magnitude c = 12 rad/s, determine: (1). the magnitude and direction of the angular momentum HD of the assembly about D. (2). the dynamic reactions (ignore mg) at the bearings at A and B. 9 in. 3 in. 03 9 in. 3 in. Answers: HD = 0.162 i +0.184 j slug-ft²/s HG = 2.21 k Ay =-1.1 lb; Az = 0; By = 1.1 lb; B₂ = 0.arrow_forwardProblem 5 (Optional, extra 6 points) A 6-lb homogeneous disk of radius 3 in. spins as shown at the constant rate w₁ = 60 rad/s. The disk is supported by the fork-ended rod AB, which is welded to the vertical shaft CBD. The system is at rest when a couple Mo= (0.25ft-lb)j is applied to the shaft for 2 s and then removed. Determine the dynamic reactions at C and D before and after the couple has been removed at 2 s. 4 in. C B Mo 5 in 4 in. Note: 2 rotating around CD induced by Mo is NOT constant before Mo is removed. and ₂ (two unknowns) are related by the equation: ₂ =0+ w₂t 3 in. Partial Answer (after Mo has been removed): C-7.81+7.43k lb D -7.81 7.43 lbarrow_forward
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