EBK APPLIED FLUID MECHANICS
7th Edition
ISBN: 8220100668340
Author: UNTENER
Publisher: PEARSON
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Chapter 10, Problem 10.29PP
Determine the energy loss that will occur if water flows from a reservoir into a pipe with a velocity of
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An AISI 1018 steel ball with 1.100-in diameter is used as a roller between a flat plate
made from 2024 T3 aluminum and a flat table surface made from ASTM No. 30 gray
cast iron. Determine the maximum amount of weight that can be stacked on the
aluminum plate without exceeding a maximum shear stress of 19.00 kpsi in any of the
three pieces. Assume the figure given below, which is based on a typical Poisson's
ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress
occurs for these materials.
1.0
0.8
Ratio of stress to Pmax
0.4
90
0.6
στ
Tmax
0.2
0.5a
a
1.5a
2a
2.5a
За
Distance from contact surface
The maximum amount of weight that can be stacked on the aluminum plate is
lbf.
A carbon steel ball with 27.00-mm diameter is pressed together with an aluminum ball
with a 36.00-mm diameter by a force of 11.00 N. Determine the maximum shear
stress and the depth at which it will occur for the aluminum ball. Assume the figure
given below, which is based on a typical Poisson's ratio of 0.3, is applicable to estimate
the depth at which the maximum shear stress occurs for these materials.
1.0
0.8
Ratio of stress to Pma
9 0.6
στ
24
0.4
Tmax
0.2
0
0.5a
a
1.5a
Z
2a
2.5a
За
Distance from contact surface
The maximum shear stress is determined to be
MPa.
The depth in the aluminum ball at which the maximum shear stress will occur is
determined to be [
mm.
Show all work please
Chapter 10 Solutions
EBK APPLIED FLUID MECHANICS
Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the energy loss due to a sudden...Ch. 10 - Determine the pressure difference between two...Ch. 10 - Determine the pressure difference for the...Ch. 10 - Determine the energy loss due to a gradual...Ch. 10 - Determine the energy loss for the conditions in...Ch. 10 - Compute the energy loss for gradual enlargements...Ch. 10 - Plot a graph of energy loss versus cone angle for...Ch. 10 - For the data in Problem 10.8, compute the length...
Ch. 10 - Add the energy loss due to friction from Problem...Ch. 10 - Another term for an enlargement is a diffuser. A...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Compute the resulting pressure after a "real"...Ch. 10 - Determine the energy loss when 0.04m3/s of water...Ch. 10 - Determine the energy loss when 1.50ft3/s of water...Ch. 10 - Determine the energy loss when oil with a specific...Ch. 10 - For the conditions in Problem 10.17, if the...Ch. 10 - True or false: For a sudden contraction with a...Ch. 10 - Determine the energy loss for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - Determine the energy lass for a sudden contraction...Ch. 10 - Determine the energy loss for a gradual...Ch. 10 - For the data in Problem 10.22, compute the energy...Ch. 10 - For each contraction described in Problems 10.22...Ch. 10 - Note in Figs. 10.10 and 10.11 that the minimum...Ch. 10 - If the contraction from a 6-in to a 3-in ductile...Ch. 10 - Compute the energy loss that would occur as 50...Ch. 10 - Determine the energy loss that will occur if water...Ch. 10 - Determine the equivalent length in meters of pipe...Ch. 10 - Repeat Problem 10.30 for a fully open gate valve.Ch. 10 - Calculate the resistance coefficient K for a...Ch. 10 - Calculate the pressure difference across a fully...Ch. 10 - Determine the pressure drop across a 90 C standard...Ch. 10 - Prob. 10.35PPCh. 10 - Repeat Problem 10.34 for a long radius elbow....Ch. 10 - A simple heat exchanger is made by installing a...Ch. 10 - A proposed alternate form for the heat exchanger...Ch. 10 - A piping system for a pump contains a tee, as...Ch. 10 - A piping system for supplying heavy fuel oil at 25...Ch. 10 - A 25 mm ODx2.0 mm wall copper tube supplies hot...Ch. 10 - Specify the radius in mm to the centerline of a 90...Ch. 10 - The inlet and the outlet shown in Fig. 10.36 are...Ch. 10 - Compare the energy losses for the two proposals...Ch. 10 - Determine the energy loss that occurs as 40 L/min...Ch. 10 - Figure 10.38 shows a test setup for determining...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - Compute the energy loss in a 90 bend in a steel...Ch. 10 - For the data in Problem 10.47, compute the...Ch. 10 - For the data in Problem 10.48, compute the...Ch. 10 - A tube similar to that in Problem 10.47 is being...Ch. 10 - Prob. 10.52PPCh. 10 - Prob. 10.53PPCh. 10 - Prob. 10.54PPCh. 10 - Prob. 10.55PPCh. 10 - Repeat Problem 10.55 for flow rates of 7.5 gal/min...Ch. 10 - Prob. 10.57PPCh. 10 - Prob. 10.58PPCh. 10 - Prob. 10.59PPCh. 10 - Prob. 10.60PPCh. 10 - A 34 plastic ball valve carries 15 gal/min of...Ch. 10 - A 114 plastic butterfly valve carries 60 gal/min...Ch. 10 - A 3 -in plastic butterfly valve carries 300...Ch. 10 - A 10-in plastic butterfly valve carries 5000...Ch. 10 - A 1 12 plastic diaphragm valve carries 60 gal/min...Ch. 10 - Prob. 10.66PPCh. 10 - Prob. 10.67PPCh. 10 - Prob. 10.68PPCh. 10 - Prob. 10.69PPCh. 10 - An 8 -in plastic swing check valve carries 3500...Ch. 10 - Use PIPE-FLO software to determine the pressure...Ch. 10 - Use PIPE-FLO to calculate the head loss and...
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- Draw top, side, front view With pen(cil) and paper Multi view drawing and handwriting all of itarrow_forwardA wheel of diameter 150.0 mm and width 37.00 mm carrying a load 2.200 kN rolls on a flat rail. Take the wheel material as steel and the rail material as cast iron. Assume the figure given, which is based on a Poisson's ratio of 0.3, is applicable to estimate the depth at which the maximum shear stress occurs for these materials. At this critical depth, calculate the Hertzian stresses σr, σy, σz, and Tmax for the wheel. 1.0 0.8 0, т Ratio of stress to Pmax 0.4 0.6 90 69 0.2 0.5b b 1.5b Tmax 2b Distance from contact surface The Hertizian stresses are as follows: 02 = or = -23.8 psi for the wheel =| necessary.) σy for the wheel =| MPa σz for the wheel = MPa V4 for the wheel = | MPa 2.5b ཡི 3b MPa (Include a minus sign ifarrow_forwardOnly question 3arrow_forward
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