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Concept explainers
(a)
Interpretation:
Each of the Nitrogen compounds has to be matched with their bond length along with the geometry of the one of Nitrogen atoms in each compound and the hybrid orbital that is needed to describe in
Concept Introduction
Valence bond theory: VSEPR theory tells about the shapes of molecules and ions by taking the consideration that the outermost electron pairs are arranged about each atom so that the pairs of electrons are kept at a distance from one molecule to other, thereby minimizing the repulsion of electron-pair.
Hybrid orbitals:
Hybrid orbitals are formed from the combination of atomic orbitals of the isolated atom. Hybrid orbitals are used to describe the formation of bonds in the directions predicted by VSEPR model.
To give the bond length, geometry and hybrid orbital of
(b)
Interpretation:
Each of the Nitrogen compounds has to be matched with their bond length along with the geometry of the one of Nitrogen atoms in each compound and the hybrid orbital that is needed to describe in valence bond theory has to be explained.
Concept Introduction
Valence bond theory: VSEPR theory tells about the shapes of molecules and ions by taking the consideration that the outermost electron pairs are arranged about each atom so that the pairs of electrons are kept at a distance from one molecule to other, thereby minimizing the repulsion of electron-pair.
Hybrid orbitals:
Hybrid orbitals are formed from the combination of atomic orbitals of the isolated atom. Hybrid orbitals are used to describe the formation of bonds in the directions predicted by VSEPR model.
To give the bond length, geometry and hybrid orbital of
(c)
Interpretation:
Each of the Nitrogen compounds has to be matched with their bond length along with the geometry of the one of Nitrogen atoms in each compound and the hybrid orbital that is needed to describe in valence bond theory has to be explained.
Concept Introduction
Valence bond theory: VSEPR theory tells about the shapes of molecules and ions by taking the consideration that the outermost electron pairs are arranged about each atom so that the pairs of electrons are kept at a distance from one molecule to other, thereby minimizing the repulsion of electron-pair.
Hybrid orbitals:
Hybrid orbitals are formed from the combination of atomic orbitals of the isolated atom. Hybrid orbitals are used to describe the formation of bonds in the directions predicted by VSEPR model.
To give the bond length, geometry and hybrid orbital of
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Chapter 10 Solutions
Bundle: General Chemistry, Loose-leaf Version, 11th + OWLv2, 4 terms (24 months) Printed Access Card
- The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;arrow_forwardThe highest boiling compound from among the following isA. 2-methylheptane; B. 3-methylheptane; C. 2,2-dimethylhexane;D. octane; E. 2,2,3-trimethylpentanearrow_forwardWhich of the following features are found in the most stable structure ofCH5NO that does not have a CO bond?w. a π bond, x. two NH bonds, y. one OH bond, z. 3 lone pairsA. w, x; B. x, y; C. y, z; D. x, y, z; E. all of them.arrow_forward
- Which one of the following functional groups is not present in thecompound shownA. amine; B. aldehyde, C. ether; D. amide. E. ketonearrow_forwardWhich of the following formulas correspond to at least one compound inwhich resonance is important?w. C2H5N x. C3H5Br; y. C3H4; z. C4H6.A. w, x, y; B. x, y, z; C. w, x, z; D. w, y, z; E. all of themarrow_forwardPredict the product(s) that are formed after each step for reactions 1-4. In each case, consider formation of any chiral center(s) and draw all expected stereoisomers. 1) OH 1) HBr (SN2) 2) NaOH, heat 3) BH3, THF 4) H2O2, NaOH 2) OH 1) SOCI 2, py 2) NaOEt 3) Br2, H₂O 3) OH 1) H2SO4 conc. 2) HBr, ROOR 3) KOtBu 4) OH 1) TsCl, py 2) NaOEt 3) 03 4) DMSarrow_forward
- Which of the following rings has the least strain in its most stableconformation?A. Cyclobutane; B. Cyclopentane; C. Cyclohexane; D. Cycloheptane;E. Cyclooctanearrow_forwardThe number of different carbon skeletons that have a main chain of 9carbons and an ethyl branch isA 3; B. 4; C. 5; D. 6; E. 7arrow_forwardQ5: Classify the following pair of molecules as constitutional isomers, enantiomers, diastereomers, the same molecule, or completely different molecules. Br O CI Br OH OH 111 Br .!!!/Br F OH and ...m Br Br OH CI Br OH ་་་་་" ། ་arrow_forward
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