CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
9th Edition
ISBN: 9781264094202
Author: SILBERBERG
Publisher: MCG
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Chapter 10, Problem 10.62P

(a)

Interpretation Introduction

Interpretation:

Lewis structure of PF5 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(b)

Interpretation Introduction

Interpretation:

Lewis structure of CCl4 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(c)

Interpretation Introduction

Interpretation:

Lewis structure of H3O+ is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(d)

Interpretation Introduction

Interpretation:

Lewis structure of ICl3 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(e)

Interpretation Introduction

Interpretation:

Lewis structure of BeH2 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(f)

Interpretation Introduction

Interpretation:

Lewis structure of PH2 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(g)

Interpretation Introduction

Interpretation:

Lewis structure of GeBr4 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(h)

Interpretation Introduction

Interpretation:

Lewis structure of CH3 is to be determined.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(i)

Interpretation Introduction

Interpretation:

Lewis structure of BCl3 is to be determined.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(j)

Interpretation Introduction

Interpretation:

Lewis structure of BrF4+ is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(k)

Interpretation Introduction

Interpretation:

Lewis structure of XeO3 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

(l)

Interpretation Introduction

Interpretation:

Lewis structure of TeF4 is to be drawn.

Concept introduction:

The steps to draw the Lewis structure of the given molecule are as follows:

Step 1: Choose the least electronegative central metal atom and place the atoms relative to each other.

Step 2: Determine the total number of valence electron.

Step 3: Place a single electron pair between each atom and subtract 2 electrons corresponding to each of these bonds from the total number of valence electrons.

Step 4: Distribute the remaining electrons in pairs around each atom as non bonding electrons such that each atom gets a complete share of eight electrons.

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Chapter 10 Solutions

CHEMISTRY:MOLECULAR...(LL)-W/CONNECT

Ch. 10.2 - Prob. 10.6AFPCh. 10.2 - Prob. 10.6BFPCh. 10.2 - Prob. 10.7AFPCh. 10.2 - Prob. 10.7BFPCh. 10.2 - Prob. 10.8AFPCh. 10.2 - Prob. 10.8BFPCh. 10.3 - Prob. 10.9AFPCh. 10.3 - Prob. 10.9BFPCh. 10 - Prob. 10.1PCh. 10 - When is a resonance hybrid needed to adequately...Ch. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Draw a Lewis structure for (a) SiF4; (b) SeCl2;...Ch. 10 - Draw a Lewis structure for (a) ; (b) C2F4; (c)...Ch. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - Prob. 10.9PCh. 10 - Draw Lewis structures of all the important...Ch. 10 - Prob. 10.11PCh. 10 - Draw Lewis structures of all the important...Ch. 10 - Prob. 10.13PCh. 10 - Prob. 10.14PCh. 10 - Draw the Lewis structure with lowest formal...Ch. 10 - Draw the Lewis structure with lowest formal...Ch. 10 - Prob. 10.17PCh. 10 - Prob. 10.18PCh. 10 - Prob. 10.19PCh. 10 - Prob. 10.20PCh. 10 - These species do not obey the octet rule. Draw a...Ch. 10 - These species do not obey the octet rule. Draw a...Ch. 10 - Molten beryllium chloride reacts with chloride ion...Ch. 10 - Prob. 10.24PCh. 10 - Prob. 10.25PCh. 10 - Phosgene is a colorless, highly toxic gas that was...Ch. 10 - If you know the formula of a molecule or ion, what...Ch. 10 - In what situation is the name of the molecular...Ch. 10 - Prob. 10.29PCh. 10 - Prob. 10.30PCh. 10 - Consider the following molecular shapes. (a) Which...Ch. 10 - Use wedge-bond perspective drawings (if necessary)...Ch. 10 - Prob. 10.33PCh. 10 - Determine the electron-group arrangement,...Ch. 10 - Determine the electron-group arrangement,...Ch. 10 - Prob. 10.36PCh. 10 - Prob. 10.37PCh. 10 - Prob. 10.38PCh. 10 - Prob. 10.39PCh. 10 - Determine the shape, ideal bond angle(s), and the...Ch. 10 - Prob. 10.41PCh. 10 - Determine the shape around each central atom in...Ch. 10 - Prob. 10.43PCh. 10 - Prob. 10.44PCh. 10 - Prob. 10.45PCh. 10 - Prob. 10.46PCh. 10 - Arrange the following ACln species in order of...Ch. 10 - State an ideal value for each of the bond angles...Ch. 10 - Prob. 10.49PCh. 10 - Prob. 10.50PCh. 10 - Prob. 10.51PCh. 10 - Prob. 10.52PCh. 10 - How can a molecule with polar covalent bonds not...Ch. 10 - Prob. 10.54PCh. 10 - Consider the molecules SCl2, F2, CS2, CF4, and...Ch. 10 - Consider the molecules BF3, PF3, BrF3, SF4, and...Ch. 10 - Prob. 10.57PCh. 10 - Prob. 10.58PCh. 10 - Prob. 10.59PCh. 10 - Prob. 10.60PCh. 10 - Prob. 10.61PCh. 10 - Prob. 10.62PCh. 10 - Prob. 10.63PCh. 10 - Prob. 10.64PCh. 10 - Prob. 10.65PCh. 10 - Prob. 10.66PCh. 10 - When SO3 gains two electrons, forms. (a) Which...Ch. 10 - The actual bond angle in NO2 is 134.3°, and in it...Ch. 10 - Prob. 10.69PCh. 10 - Propylene oxide is used to make many products,...Ch. 10 - Prob. 10.71PCh. 10 - Prob. 10.72PCh. 10 - Prob. 10.73PCh. 10 - Prob. 10.74PCh. 10 - Prob. 10.75PCh. 10 - Prob. 10.76PCh. 10 - Prob. 10.77PCh. 10 - A gaseous compound has a composition by mass of...Ch. 10 - Prob. 10.79PCh. 10 - Prob. 10.80PCh. 10 - Prob. 10.81PCh. 10 - Prob. 10.82PCh. 10 - Pure HN3 (atom sequence HNNN) is explosive. In...Ch. 10 - Prob. 10.84PCh. 10 - Prob. 10.85PCh. 10 - Oxalic acid (H2C2O4) is found in toxic...Ch. 10 - Prob. 10.87PCh. 10 - Hydrazine (N2H4) is used as a rocket fuel because...Ch. 10 - Prob. 10.89PCh. 10 - Prob. 10.90PCh. 10 - Prob. 10.91PCh. 10 - Consider the following molecular shapes: Match...Ch. 10 - Prob. 10.93PCh. 10 - Prob. 10.94PCh. 10 - Prob. 10.95PCh. 10 - Phosphorus pentachloride, a key industrial...
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