Limestone is predominantly CaCO 3 , which can undergo the reaction CaCO 3 ( s ) → CaO ( s ) + C O 2 ( g ) . We know from experience that this reaction is not spontaneous, yet Δ S for the reaction is positive. How can the second law of thermodynamics explain that this reaction is not spontaneous?
Limestone is predominantly CaCO 3 , which can undergo the reaction CaCO 3 ( s ) → CaO ( s ) + C O 2 ( g ) . We know from experience that this reaction is not spontaneous, yet Δ S for the reaction is positive. How can the second law of thermodynamics explain that this reaction is not spontaneous?
Solution Summary: The author explains that the second law of thermodynamics is not violated despite a positive entropy change.
Limestone is predominantly CaCO3, which can undergo the reaction
CaCO
3
(
s
)
→
CaO
(
s
)
+
C
O
2
(
g
)
. We know from experience that this reaction is not spontaneous, yet
Δ
S
for the reaction is positive. How can the second law of thermodynamics explain that this reaction is not spontaneous?
Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.
Will NBS (and heat or light) work for this reaction, or do we have to use Br2?
HAND DRAW
Predict the major products of the following organic reaction:
Some important notes:
Δ
CN
?
• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
ONO reaction.
Click and drag to start drawing a structure.
Chapter 10 Solutions
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