Chapter 10, Problem 10.36P

Interpretation Introduction

(a)

Interpretation:

Derive an expression of a and b.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure

Interpretation Introduction

(b)

Interpretation:

Calculate the mole fraction of pentane in the vapor phase for the given case and estimate a and b.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure

Interpretation Introduction

(c)

Interpretation:

Prove the given equation is valid using the materials balances.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure

Interpretation Introduction

(d)

Interpretation:

Derive the given expression.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure

Interpretation Introduction

(e)

Interpretation:

Calculate x, y, NL and nv. On a single graph plot x and y versus t for calculated Q values.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure

Interpretation Introduction

(f)

Interpretation:

Explain about the composition of the vapor and residual liquid, how the heating rate affects the system behavior.

Concept introduction:

Raoult’s law equation is given as,

$yP=x{P}^{*}$

Where, P = the pressure of the system, y = mole fraction in vapor, x = mole fraction in liquid and $P^{*}$ = vapor pressure