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Chapter 10, Problem 10.14E
Interpretation Introduction

Interpretation:

The description of half-life in terms of something familiar, such as cake or cookies or checking account is to be stated.

Concept introduction:

The process by which an unstable nucleus radiates energy along with the emission of an alpha or beta particle is known as radioactive decay. A substance is said to be radioactive if it possesses an unstable nucleus.

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AG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, N
4. For the following complexes, draw the structures and give a d-electron count of the metal: a) Tris(acetylacetonato)iron(III) b) Hexabromoplatinate(2-) c) Potassium diamminetetrabromocobaltate(III) (6 points)
2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation constant for [Fe(CN)6] 4 is ~1032, and that: Fe3+ (aq) + e = Fe²+ (aq) E° = +0.77 V [Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V (4 points)

Chapter 10 Solutions

Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card

Ch. 10 - Prob. 10.11ECh. 10 - Prob. 10.12ECh. 10 - Prob. 10.13ECh. 10 - Prob. 10.14ECh. 10 - Prob. 10.15ECh. 10 - Prob. 10.16ECh. 10 - Prob. 10.17ECh. 10 - Prob. 10.18ECh. 10 - Prob. 10.19ECh. 10 - Prob. 10.20ECh. 10 - Prob. 10.21ECh. 10 - Prob. 10.22ECh. 10 - Prob. 10.23ECh. 10 - Prob. 10.24ECh. 10 - Prob. 10.25ECh. 10 - Prob. 10.26ECh. 10 - Prob. 10.27ECh. 10 - Prob. 10.28ECh. 10 - Prob. 10.29ECh. 10 - Prob. 10.30ECh. 10 - Prob. 10.31ECh. 10 - Prob. 10.32ECh. 10 - Prob. 10.33ECh. 10 - Prob. 10.34ECh. 10 - Prob. 10.35ECh. 10 - Prob. 10.36ECh. 10 - Prob. 10.37ECh. 10 - Prob. 10.38ECh. 10 - Prob. 10.39ECh. 10 - Prob. 10.40ECh. 10 - Prob. 10.41ECh. 10 - Prob. 10.42ECh. 10 - Prob. 10.43ECh. 10 - Prob. 10.44ECh. 10 - Prob. 10.45ECh. 10 - Prob. 10.46ECh. 10 - Prob. 10.47ECh. 10 - Prob. 10.48ECh. 10 - Prob. 10.49ECh. 10 - Prob. 10.50ECh. 10 - Prob. 10.51ECh. 10 - Prob. 10.52ECh. 10 - Prob. 10.53ECh. 10 - Prob. 10.54ECh. 10 - Prob. 10.55ECh. 10 - Prob. 10.56ECh. 10 - Prob. 10.57ECh. 10 - Prob. 10.58ECh. 10 - Prob. 10.59ECh. 10 - Prob. 10.60ECh. 10 - Prob. 10.61ECh. 10 - Prob. 10.62ECh. 10 - Prob. 10.63ECh. 10 - Prob. 10.64ECh. 10 - Prob. 10.65ECh. 10 - Prob. 10.66ECh. 10 - Prob. 10.67ECh. 10 - Prob. 10.68ECh. 10 - Prob. 10.69ECh. 10 - Prob. 10.70ECh. 10 - Prob. 10.71ECh. 10 - Prob. 10.72ECh. 10 - Prob. 10.73ECh. 10 - Prob. 10.74ECh. 10 - Prob. 10.75ECh. 10 - Prob. 10.76ECh. 10 - Prob. 10.77ECh. 10 - Prob. 10.78ECh. 10 - Prob. 10.79ECh. 10 - Prob. 10.80ECh. 10 - Prob. 10.81ECh. 10 - Prob. 10.82ECh. 10 - Prob. 10.83ECh. 10 - Prob. 10.84ECh. 10 - Prob. 10.85ECh. 10 - Prob. 10.86E
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