Concept explainers
Interpretation:
The maximum
Concept Introduction:
Bond Enthalpy:
The measure of stability of molecule is bond enthalpy. The change in enthalpy is related in breaking a specific bond of 1 mole of gaseous molecule. In solids and liquids bond enthalpies are affected by neighboring molecules. There is possibility to predict the enthalpy of reaction using the average bond enthalpies. Energy is always needed for the breaking of
The enthalpy of reaction in gas phase is given by,
Where,
BE= Bond enthalpy and
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CHEMISTRY:ATOMS FIRST-2 YEAR CONNECT
- Bond Enthalpy When atoms of the hypothetical element X are placed together, they rapidly undergo reaction to form the X2 molecule: X(g)+X(g)X2(g) a Would you predict that this reaction is exothermic or endothermic? Explain. b Is the bond enthalpy of X2 a positive or a negative quantity? Why? c Suppose H for the reaction is 500 kJ/mol. Estimate the bond enthalpy of the X2 molecule. d Another hypothetical molecular compound, Y2(g), has a bond enthalpy of 750 kJ/mol, and the molecular compound XY(g) has a bond enthalpy of 1500 kJ/mol. Using bond enthalpy information, calculate H for the following reaction. X2(g)+Y2(g)2XY(g) e Given the following information, as well as the information previously presented, predict whether or not the hypothetical ionic compound AX is likely to form. In this compound, A forms the A+ cation, and X forms the X anion. Be sure to justify your answer. Reaction: A(g)+12X2(g)AX(s)The first ionization energy of A(g) is 400 kJ/mol. The electron affinity of X(g) is 525 kJ/mol. The lattice energy of AX(s) is 100 kJ/mol. f If you predicted that no ionic compound would form from the reaction in Part e, what minimum amount of AX(s) lattice energy might lead to compound formation?arrow_forwardUsing the bond energies provided, calculate the enthalpy of the reaction (∆Hrxn, in kJ) for the combustion of methanol shown below. CH3OH(l) +3/2 O2 (g) → CO2 (g) + 2 H2O(g)arrow_forwardWith reference to the “Chemistry Put to Work” box on explosives, (a) use bond enthalpies to estimate the enthalpy change for the explosion of 1.00 g of nitroglycerin. (b) Write a balanced equation for the decomposition of TNT. Assume that, upon explosion, TNT decomposes into N2(g), CO2(g), H2O(g), and C(s).arrow_forward
- (a) Compare the bond enthalpies (Table 8.3) of the carbon–carbon single, double, and triple bonds to deduce an averageπ -bond contribution to the enthalpy. What fraction ofa single bond does this quantity represent? (b) Make a similarcomparison of nitrogen–nitrogen bonds. What do youobserve? (c) Write Lewis structures of N2H4, N2H2, and N2,and determine the hybridization around nitrogen in eachcase. (d) Propose a reason for the large difference in yourobservations of parts (a) and (b).arrow_forwardHydrazine, N2H4, burns in oxygen as follows: N2H4 + O2 → N2 + 2H2O [The bond energies in kJ/mol are: N-H = 388; N-N 163; N≡N 944; O-H 463; O=O 496] Draw the chemical structures of the reactants and products and give the formula to calculate enthalpy change in a reaction, ΔH.arrow_forwardThe two compounds nitrogen dioxide and dinitrogen tetraoxide are introduced in Section 3.13. (a) NO2 is an odd-electron compound. Draw the best Lewis diagrams possible for it, recognizing that one atom cannot achieve an octet configuration. Use formal charges to decide whether that should be the (central) nitrogen atom or one of the oxygen atoms. (b) Draw resonance forms for N2O4 that obey the octet rule. The two N atoms are bonded in this molecule.arrow_forward
- 5. Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g)N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and bond enthalpies to estimate the enthalpy of the nitrogen-nitrogen bond in N2H4N2H4. (Hint: In an N2H4N2H4 molecule, each NN atom has single bonds to the adjacent NN atom and two HH atoms. In an NH3NH3 molecule, the central NN atom has single bonds to three HH atoms.)arrow_forwardCalculate the enthalpy change from bond energies for each of these reactions: 1. Н-(g) + F:(g) — 2 HF(g) AH= 2. CH(g) + 20-(g) — СО2(g) + 2H-0 (g) AH= 3. CO(g) + 2H2(g) → CH;OH(I) AH= 4. 2H2(g) + Oz(g) – 2H;O(g) AH= 5. 2H2O(g) → 2H2(g) + O2(g) AH= 6. H2CCH2(g) + Cl2(g) → CIH2CCH2CI(g) AH=arrow_forwardUse the molar bond enthalpy data in the table to estimate the value of AHin for the equation CC14(g) + 2 F₂ (g) → CF₁ (g) + 2 Cl₂ (g) 2 The bonding in the molecules is shown. ΔΗ +=++· rxn = -CI F-F F-F -C-F CI-CI CI-CI Average molar bond enthalpies (Hbond) Bond Bond O-H C=N 0-0 N-H C-O N-N 0=0 N=N C=O N=N C-C F-F C=C Cl-Cl C=C Br-Br C-H H-H C-F H-F C-Cl H-Cl C-Br H-Br C-N H-S C=N S-S kJ.mol-¹ 464 142 351 502 730 347 615 811 414 439 331 276 293 615 kJ.mol-1 890 390 159 418 945 155 243 192 435 565 431 368 364 225 kJ.mol-¹arrow_forward
- Calculate the enthalpy change for the following reactions using the bond enthalpy given below. (Bond enthalpy/kJ : H−H = 436, C−H = 413, C=O = 799, O=O = 495, O−H = 463) (a) H2(g) + 1⁄2O2(g) → H2O(g) (b) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)arrow_forwardUsing average bond enthalpies (linked above), estimate the enthalpy change for the following reaction: CH4(g) + Cl₂(g)→→→→CH3CI(g) + HCI(g) kJarrow_forwardFructose, C6H1206(S), consists of 5 C-C single bonds, 7 C-O bonds, 7 C-H bonds, and 5 O-H bonds with average bond energies of 348 kJ/mol, 360 kJ/mol, 412 kJ/mol, and 463 kJ/mol respectively. The bond energy for C=O is 799 kJ/mol and O=O is 498 kJ/mol. The molar mass of fructose is 180.12 g/mol. Estimate the change in enthalpy if 2.56 g of fructose undergoes complete combustion at standard temperature and pressure.arrow_forward
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