Concept explainers
(a)
Interpretation: In the pair of
Concept Introduction:
Ionization energy is the energy required to remove an electron from an isolated gaseous atom or ion.
The first or initial ionization energy is the energy required to remove one mole of electron from the one of an isolated gaseous atom or ion.
Trends of ionization energy:
It is well known that bonding molecular orbitals have lower energy than the atomic orbitals whereas anti-bonding molecular orbitals have higher energy than the atomic orbitals. So the electrons in the bonding molecular orbitals will be more stabilized than that in the anti-bonding molecular orbitals. Thus the first ionization energy will be higher for removing one mole of electron from the bonding molecular orbital and it will be lower for removing one mole of electron from the anti-bonding molecular orbital.
(b)
Interpretation: In the pair of
Concept Introduction:
Ionization energy is the energy required to remove an electron from an isolated gaseous atom or ion.
The first or initial ionization energy is the energy required to remove one mole of electron from the one of an isolated gaseous atom or ion.
Trends of ionization energy:
It is well known that bonding molecular orbitals have lower energy than the atomic orbitals whereas anti-bonding molecular orbitals have higher energy than the atomic orbitals. So the electrons in the bonding molecular orbitals will be more stabilized than that in the anti-bonding molecular orbitals. Thus the first ionization energy will be higher for removing one mole of electron from the bonding molecular orbital and it will be lower for removing one mole of electron from the anti-bonding molecular orbital.
(c)
Interpretation: In the pair of
Concept Introduction:
Ionization energy is the energy required to remove an electron from an isolated gaseous atom or ion.
The first or initial ionization energy is the energy required to remove one mole of electron from the one of an isolated gaseous atom or ion.
Trends of ionization energy:
It is well known that bonding molecular orbitals have lower energy than the atomic orbitals whereas anti-bonding molecular orbitals have higher energy than the atomic orbitals. So the electrons in the bonding molecular orbitals will be more stabilized than that in the anti-bonding molecular orbitals. Thus the first ionization energy will be higher for removing one mole of electron from the bonding molecular orbital and it will be lower for removing one mole of electron from the anti-bonding molecular orbital.
(d)
Interpretation: In the pair of
Concept Introduction:
Ionization energy is the energy required to remove an electron from an isolated gaseous atom or ion.
The first or initial ionization energy is the energy required to remove one mole of electron from the one of an isolated gaseous atom or ion.
Trends of ionization energy:
It is well known that bonding molecular orbitals have lower energy than the atomic orbitals whereas anti-bonding molecular orbitals have higher energy than the atomic orbitals. So the electrons in the bonding molecular orbitals will be more stabilized than that in the anti-bonding molecular orbitals. Thus the first ionization energy will be higher for removing one mole of electron from the bonding molecular orbital and it will be lower for removing one mole of electron from the anti-bonding molecular orbital.

Want to see the full answer?
Check out a sample textbook solution
Chapter 10 Solutions
CHEMISTRY-ALEKS 360 ACCESS
- Hi, I need your help with the drawing, please. I have attached the question along with my lab instructions. Please use the reaction from the lab only, as we are not allowed to use outside sources. Thank you!arrow_forwardHi, I need your help i dont know which one to draw please. I’ve attached the question along with my lab instructions. Please use the reaction from the lab only, as we are not allowed to use outside sources. Thank you!arrow_forward5. Write the formation reaction of the following complex compounds from the following reactants: 6. AgNO₃ + K₂CrO₂ + NH₄OH → 7. HgNO₃ + excess KI → 8. Al(NO₃)₃ + excess NaOH →arrow_forward
- Indicate whether the product formed in the reaction exhibits tautomerism. If so, draw the structure of the tautomers. CO₂C2H5 + CH3-NH-NH,arrow_forwardDraw the major product of this reaction N-(cyclohex-1-en-1-yl)-1-(pyrrolidino) reacts with CH2=CHCHO, heat, H3O+arrow_forwardDraw the starting material that would be needed to make this product through an intramolecular Dieckmann reactionarrow_forward
- Draw the major product of this reaction. Nitropropane reacts + pent-3-en-2-one reacts with NaOCH2CH3, CH3CHOHarrow_forwardIndicate whether the product formed in the reaction exhibits tautomerism. If so, draw the structure of the tautomers. OC2H5 + CoHs-NH-NH,arrow_forwardExplain how substitutions at the 5-position of barbituric acid increase the compound's lipophilicity.arrow_forward
- Explain how substitutions at the 5-position of phenobarbital increase the compound's lipophilicity.arrow_forwardName an interesting derivative of barbituric acid, describing its structure.arrow_forwardBriefly describe the synthesis mechanism of barbituric acid from the condensation of urea with a β-diketone.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





