Chemistry
7th Edition
ISBN: 9780321940872
Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson
Publisher: PEARSON
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Chapter 10, Problem 10.100SP
Interpretation Introduction
Interpretation:
Determine the molecular weight of a substance that diffuses through a porous membrane 2.92 times slower than H2 using Graham’s law.
Concept introduction:
- Diffusion is the process of gas particles spreading throughout another gas by molecular motion.
- Not all gases will diffuse at the same rate. The rate of diffusion of a substance is inversely proportional to the molar mass of the substance. Therefore, substances of lighter masses will diffuse at much faster rates than heavy gases.
- The relationship of rate to molar mass is referred to as Graham’s law.
To classify:
The molecular weight of the gas which diffuses 2.92 slower than H2.
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Chapter 10 Solutions
Chemistry
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