Interpretation Introduction To determine: The inner diameter of the tube ( in cm ) . Explanation Given Mass of the ethanol = 45 .23 g Length of the cylindrical glass tube, l = 25 .0 cm Density of the ethanol = 0 .789 g / mL Formula Volume is calculated using the formula, Volume = Mass Density Substitute the values of mass and density of the ethanol in above equation. Volume = 45 .23 g 0 .789 g / mL = 57 .32 mL The conversion of milliliter ( mL ) into cubic centimeter ( cm 3 ) is done as, 1 mL = 1 cm 3 Hence, The conversion of 57 .32 mL to cubic centimeter is, 57 .32 mL = ( 57 .32 × 1 ) cm 3 = 57 .32 cm 3 Therefore, the volume of the ethanol is 57

Chemistry: The Central Science Plus Mastering Chemistry with Pearson eText -- Access Card Package (14th Edition)

14th Edition

ISBN: 9780134292816

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Matthew E. Stoltzfus

Publisher: PEARSON

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Chapter 1, Problem 89AE

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To determine: The inner diameter of the tube (in cm) .

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Chapter 1, Problem 88AE

Chapter 1, Problem 90AE

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Chemistry: The Central Science Plus Mastering Chemistry with Pearson eText -- Access Card Package (14th Edition)

Ch. 1.2 - Practice Exercise 1 Which of the following is the...Ch. 1.2 - Aspirin is composed of 60.0% carbon, 4.5%...Ch. 1.5 - Practice Exercise 1 Which of the following weights...Ch. 1.5 - Practice Exercise 2 How many picometers are there...Ch. 1.5 - Practice Exercise 1 Using Wolfram Alpha...Ch. 1.5 - Practice Exercise 2 Ethylene glycol, the major...Ch. 1.5 - Practice Exercise 1 Platinum, Pt. is one of the...Ch. 1.5 - Practice Exercise 2 Calculate the density of a...Ch. 1.5 - Which of the following objects has the greatest...Ch. 1.5 - Prob. 1.5.2PE

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