EBK UNDERSTANDING OUR UNIVERSE (THIRD E
3rd Edition
ISBN: 9780393631760
Author: Blumenthal
Publisher: VST
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Chapter 1, Problem 6QAP
To determine
The correct order of occurrence of astronomical events.
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Big Bang produced mainly hydrogen and helium and only extremely trace amount of heavier elements. Yet there is abundant amount of carbon on Earth. The carbon atoms in your body were produced by
A. Fusion in other stars that have already died
B. Radiative decays inside the Earth
C. Chemical reactions inside the Earth
D. Fusion in the Sun
The first stars to form in our galaxy
a.
had circular orbits.
b.
had highly elliptical orbits.
c.
were population I stars.
d.
all had orbits in the same plane.
e.
formed the galactic clusters we see today.
Read this main idea: The sun is the center of our solar system. Choose three details that go with the main idea.
The sun's gravity holds the planets in place. It provides them with heat and light.
The largest stars, called supergiants, are 1,500 times bigger than our sun.
It takes Earth 365 days to orbit the sun. Jupiter takes 12 years!
Our sun is not the largest or hottest star. It is a medium sized yellow star.
Radio telescopes use radio waves to show stars in great detail.
Astronomers long ago and today use star charts to map star locations.
All of the planets in our solar system revolve around one star-our sun.
Stars can be blue, white, yellow, or red. Blue stars are the hottest.
A reflector telescope bounces star light through mirrors.
Chapter 1 Solutions
EBK UNDERSTANDING OUR UNIVERSE (THIRD E
Ch. 1.1 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1 - Prob. 1QAPCh. 1 - Prob. 2QAPCh. 1 - Prob. 3QAPCh. 1 - Prob. 4QAPCh. 1 - Prob. 5QAPCh. 1 - Prob. 6QAPCh. 1 - Prob. 7QAP
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- 1. Consider our Sun - it is in orbit around the center of our Milky Way Galaxy. The velocity of the Sun in its orbit is about 250 km/s. The distance to the center of the galaxy is about 9.1 kpc (kiloparsecs). We can use Kepler's third law to calculate the mass of the galaxy interior to the Sun's orbit. We assume that the orbit is circular so that the semimajor axis is just the radius of the circular orbit = 9.1 kpc. First we need to calculate the number of AU's in 9.1 kpc. (Note that 1 Крс - 1000 рс - 3260 1t yrs and 1 pc - 206,265 AU.) %3D a =r =9.1kpc = (9.1kpc) 1000 pc 206,265AU] 1kpc AU Sun 1pcarrow_forwardWhy are we unlikely to find Earth-like planets around halo stars in the Galaxy? A. Halo stars formed in a different way from disk stars. B. Planets around stars are known to be extremely rare. C. Halo stars formed in an environment where there were few heavy elements to create rocky planets. D. Halo stars do not have enough mass to hold onto planets. Is the answer C? Since halo stars are formed early when the galaxy consisted of mainly hydrogen and helium, there are no heavier elements available to create Earth-like planets so just halo stars are formed? Thanks!arrow_forwardAStrology: What are the three most common celestial objects a star can become after it can't do nuclear fusion?arrow_forward
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