EBK UNDERSTANDING OUR UNIVERSE (THIRD E
3rd Edition
ISBN: 9780393631760
Author: Blumenthal
Publisher: VST
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Chapter 1, Problem 40QAP
To determine
The travel time of light in standard notation and scientific notation.
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question 1: parts A, B, and C please
The moon is 1.3 light-seconds away. Imagine you are standing at the Canadian Space Agency headquarters in St. Hubert, Quebec and you bounce a 755 MHz radio signal off the moon (the moon acts like a mirror, reflecting the signal, such that it comes back to you). How long will it take for that radio signal to get back to you on earth? Answer in seconds with one decimal place.
Using a single dimensional equation, estimate the number of steps it would take a person with a step length of 2.65 ft to walk from the Earth to Alpha Centauri a distance of 4.37 light-years. The speed of light is 1.86282 x 105 miles/s. Number of Steps = Enter your answer in accordance to the question statement x 1017
Chapter 1 Solutions
EBK UNDERSTANDING OUR UNIVERSE (THIRD E
Ch. 1.1 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1 - Prob. 1QAPCh. 1 - Prob. 2QAPCh. 1 - Prob. 3QAPCh. 1 - Prob. 4QAPCh. 1 - Prob. 5QAPCh. 1 - Prob. 6QAPCh. 1 - Prob. 7QAP
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- A light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 x 10^8m/s) 5 light-minutes 6 light-days 6 light-days, but this time answer in miles (enter just the number with no units)arrow_forwardA light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 × 108 m/s). 1. 4 light-seconds 2. 3 light-minutes 3. 2 light-days 4. 2 light-days, but this time answer in miles (enter just the number with no units)arrow_forwardUsing the data in the table below and the appropriate conversion factors, find the mean distance to the moon, in feet. Approximate Values of Some Measured Lengths Length (m) Distance from Earth to most remote known quasar 1 ✕ 1026 Distance from Earth to most remote known galaxies 4 ✕ 1025 Distance from Earth to nearest large galaxy (M31 in Andromeda) 2 ✕ 1022 Distance from Earth to nearest star (Proxima Centauri) 4 ✕ 1016 One lightyear 9 ✕ 1015 Mean orbit radius of the Earth about the Sun 2 ✕ 1011 Mean distance from the Earth to the Moon 4 ✕ 108 Mean radius of the Earth 6 ✕ 106 Typical altitude of a satellite orbiting Earth 2 ✕ 105 Length of a football field 9 ✕ 101 Length of a housefly 5 ✕ 10-3 Size of the smallest dust particles 1 ✕ 10-4 Size of the cells of most living organisms 1 ✕ 10-5 Diameter of a hydrogen atom 1 ✕ 10-10 Diameter of an atomic nucleus 1 ✕ 10-14 Diameter of a proton 1 ✕ 10-15arrow_forward
- (the complete question is in the picture) If the Newtonian constant has units G = [N · m2/kg2], the speed of light has units c = [m/s], the mass has units M = [kg] and the SI unit newtons is equivalentto N = [kg · m/s2], what are the units of the relation GM/c3?A. [kg · s]B. [kg · m2/s]C. [m2/s]D. [s]arrow_forwardPlease solve this questionarrow_forwardOn a 1-to-10^19 scale our Milky Way galaxy would just about fit on a soccer field. On this scale, how far is the distance from the sun to alpha centauri (one of the closest stars to the sun, at a distance of 4.4 light years).arrow_forward
- It is important to have an idea about the distances between and relative sizes of celestial objects in the solar system. In Part 1 we will pretend to shrink the solar system until its center piece, the Sun, is 67.3 cm in diameter. This will represent the Sun which is 1,390,000 km in diameter. The scale of our model is thus: 67.3 cm = 4.84 x 10-5 cm km Scale 1, 390, 000 km To find the size or distance between objects in centimeters for the model, simply multiply the actual size or distance in kilometers by the scale factor above. 1. Fill in following table: Quantity Actual Distance (km) Model Distance (cm) Diameter of Sun 1,390,000 Diameter of Earth 12,760 Diameter of Moon 3,480 Distance Between Earth and Sun 1.5 x 108 Distance Between Earth and Moon 384,000 Distance to Proxima Centauri 3.97 x 1013arrow_forwardThe distance from the Sun to the nearest star is about 4 1016 m. The Milky Way galaxy (Fig. P1.31) is roughly a disk of diameter 1021 in and thickness 1019 m. Find the order of magnitude of the number of stars in the Milky Way. Assume the distance between the Sun and our nearest neighbor is typical. Figure P1.31 The Milky Way galaxy.arrow_forwardTry Now ... .... Listed below are some distances from Earth to other objects in the Milky Way galaxy. Convert each distance to light-years. (Each of these distances is less than one light-year. For an added challenge, convert each distance to light minutes or light seconds.) 1. The distance from Earth to the Moon is about 384,400 km. How many light-years is this? 2. The distance from Earth to Mars is about 784,000,000 km. How many light-years is this? 3. The distance from Earth to Pluto is about 5,750,000,000 km. How many light-years is this?arrow_forward
- The Sun and the planets of the solar system are located in a spiral galaxy , called the Milky Way . Which numbered area on the model best represents the location of the Sun in this galaxy ?arrow_forwardRewrite the following expression in proper scientific notation as in the example at page 1. Note that here you also have to take care of the number of significant digits. (1.4088x102) (1.8775x101) (6.0110x104) (7.76)/ (2.4x10-4) (4.01x1010) (8.80x101) 3) Solve the above expression using your calculator. Round your answer to the appropriate number of significant digits. (need this)arrow_forwardWhat is the number of miles in a light-year, using (see picture) mi/s as the speed of light? I know the number of seconds in a year and 365 days will help but confused on how to put it in the equation.arrow_forward
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