(a)
Interpretation:
The method for separating a mixture of the volatile gases butane, propane, and isopropane into its components should be determined.
Concept introduction:
A laboratory technique used to separate components of the mixture is known as chromatography. In this method, mixture is dissolved in a fluid known as mobile phase. Different components travel at different speed in the mixture. This results in the separation of the components.
(b)
Interpretation:
The method for separating a solution of rubbing alcohol made up of isopropyl alcohol and water into its components should be determined.
Concept introduction:
Distillation process is used to separate the components of the mixture in liquid state using boiling and condensation methods.
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Chapter 1 Solutions
Student Solutions Manual For Masterton/hurley's Chemistry: Principles And Reactions, 8th
- Density of an aqueous solution of nitric acid is 1.43 g/mL. If this solutioin contained 36.0% nitric acid by mass, what volume of solution would be needed to supply 1.50 mmol of nitric acid?arrow_forward51. A concentrated perchloric acid solution is 65.8% HClO4 by mass and its density is 1.68 g mL−1. What volume (in litres) of the concentrated perchloric acid solution is needed to make 1.81 L of 2.62 mol L−1 HClO4(aq)?arrow_forwardWhat is the molarity of C₁2H22O11 in an aqueous solution that is prepared by dissolving a 29.87 g sample of impure C12H22011 in water to make 725.0 mL of solution. Assume that the sample is 83.0% C12H22011 by mass. Enter your answer in mol L-1, accurate to three significant figures. Do not include units as part of your answer. Use the following molar masses, in g mol-¹, for your calculations. H, 1.008 Number C, 12.01 0, 16.00arrow_forward
- 62. When corn is allowed to ferment, the fructose in the corn is converted to ethyl alcohol according to the following reaction C,H12O6(aq) →2C,H;OH(1) + 2CO2(g) (a) What volume of ethyl alcohol (d = 0.789 g/mL) is produced from one pound of fructose? (b) Gasohol can be a mixture of 10 mL ethyl alcohol and 90 mL of gasoline. How many grams of fructose are required to produce the ethyl alcohol in one gallon of gasohol? 7arrow_forwardIn the laboratory you dessolve 22.3g of iron (III) fluoride in a volumetric flask and add water to a total volume of 250mL. What is the molarity of the solution?arrow_forward(a) The sodium ion did not take part in this chemical reaction(Diluted H2SO4(aq) versus NaOH(aq)). What do we call such an ion?(b) Draw a simple diagram which shows how the sodium ion mixes with water in solution.What do we call this physical process?arrow_forward
- Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) If the calculated molarity is 0.51M, you are to prepare 250 mL of the said molar concentration. If you have an available 2M stock solution of Palmitic acid, How many mL of the 2M palmitic acid stock solution will you need? and; How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution in order to prepare 250 mL total volume of your desired solution?arrow_forwardConsider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the %m/m of the solution? Final answer must be rounded off to 1 decimal place, and shall NOT have any unit.arrow_forwardConsider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) 1.) Based from the Molarity of the palmitic acid solution that you were able to solve earlier, how will you prepare 250 mL of the said molar concentration, if you have an available 2M stock solution of Palmitic acid? How many mL of the 2M palmitic acid stock solution will you need? 2.) How many mL of solvent do you need to add to the amount gotten from the 2M Palmitic acid stock solution in order to prepare 250 mL total volume of your desired solution?arrow_forward
- Consider Palmitic acid C16H32O2, a common fatty acid used in the manufacture of soap. A solution of palmitic acid is prepared by mixing 112 g palmitic acid with 725 mL of benzene C6H6. The density of the resulting solution is 0.902 g/mL. Palmitic acid (molar mass = 256 g/mol and density = 0.852 g/mL); Benzene (molar mass = 78 g/mol and density = 0.879 g/mL) What is the mole fraction of the solvent?arrow_forward(3) HBrarrow_forward(b) The combustion of octane is represented by the following balanced equation: 2 C3H28(1) + 25 Ozlg) → 16 CO2 (g) + 18 H20 (g) In a brief chemistry or scientific language, describe this reaction:arrow_forward
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