EBK ELECTRIC CIRCUITS
10th Edition
ISBN: 8220100801792
Author: Riedel
Publisher: YUZU
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Chapter 1, Problem 5P
To determine
Find the thickness of the layer before it dries.
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PSD
A certain signal f(t) has the following PSD (assume 12 load):
| Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)]
(a) What is the mean power in the bandwidth w≤ 1 rad/sec?
(b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec?
(c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec?
(d) What is the total mean power in (t)?
Pav=
+
2T
SfLw) dw
- SALW)
An AM modulation waveform signal:-
p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt
(a) Sketch the amplitude spectrum of p(t).
(b) Find total power, sideband power and power efficiency.
(c) Find the average power containing of each sideband.
Can you rewrite the solution because it is
unclear?
AM
(+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks)
=
cos 10000 πt.
8 cos wat + 4 cos wit + 4 cos Wat coswet.
-Jet
jooort
J11000 t
= 4 e
jqooort jgoort
+4e
+ e
+e
j 12000rt.
12000 kt
+
e
+e
jooxt
igoo t
te
(w) = 8ES(W- 100007) + 8IS (W-10000)
USB
Chapter 1 Solutions
EBK ELECTRIC CIRCUITS
Ch. 1.2 - Assume a telephone signal travels through a cable...Ch. 1.2 - How many dollars per millisecond would the federal...Ch. 1.5 - The current at the terminals of the element in...Ch. 1.5 - The expression for the charge entering the upper...Ch. 1.6 - Assume that a 20 V voltage drop occurs across an...Ch. 1.6 - Prob. 6APCh. 1.6 - A high-voltage direct-current (dc) transmission...Ch. 1 - There are approximately 260 million passenger...Ch. 1 - A hand-held video player displays 480 × 320...Ch. 1 - The 16 gigabyte (GB = 230 bytes) flash memory chip...
Ch. 1 - The line described in Assessment Problem 1.7 is...Ch. 1 - One liter (L) of paint covers approximately of...Ch. 1 - Some species of bamboo can grow (250 mm/day)....Ch. 1 - There is no charge at the upper terminal of the...Ch. 1 - The current entering the upper terminal of Fig....Ch. 1 - Prob. 9PCh. 1 - In electronic circuits it is not unusual to...Ch. 1 - How much energy is imparted to an electron as it...Ch. 1 - The references for the voltage and current at the...Ch. 1 - Repeat Problem 1.12 with a voltage of −60 V.
1.12...Ch. 1 - Prob. 14PCh. 1 - When a car has a dead battery, it can often be...Ch. 1 - Prob. 16PCh. 1 - One 12 V battery supplies 100 mA to a boom box....Ch. 1 - Prob. 18PCh. 1 - The voltage and current at the terminals of the...Ch. 1 - Prob. 20PCh. 1 - The voltage and current at the terminals of the...Ch. 1 - The voltage and current at the terminals of the...Ch. 1 - The voltage and current at the terminals of the...Ch. 1 - The voltage and current at the terminals of the...Ch. 1 - The voltage and current at the terminals of the...Ch. 1 - The voltage and current at the terminals of an...Ch. 1 - The voltage and current at the terminals of the...Ch. 1 - An industrial battery is charged over a period of...Ch. 1 - The numerical values for the currents and voltages...Ch. 1 - The numerical values of the voltages and currents...Ch. 1 - Assume you are an engineer in charge of a project...Ch. 1 - The voltage and power values for each of the...Ch. 1 - The current and power for each of the...Ch. 1 - Show that the power balances for the circuit shown...Ch. 1 - Suppose there is no power lost in the wires used...
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- Can you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forward
- Find Io using Mesh analysisarrow_forwardFM station of 100 MHz carrier frequency modulated by a 20 kHz sinusoid with an amplitude of 10 volt, so that the peak frequency deviation is 25 kHz determine: 1) The BW of the FM signal. 2) The approximated BW if the modulating signal amplitude is increased to 50 volt. 3) The approximated BW if the modulating signal frequency is increased by 70%. 4) The amplitude of the modulating signal if the BW is 65 kHz.arrow_forwardAn FDM is used to multiplex two groups of signals using AM-SSB, the first group contains 25 speech signals, each has maximum frequency of 4 kHz, the second group contains 15 music signals, each has maximum frequency of 10 kHz. A guard bandwidth of 500 Hz is used bety each two signals and before the first one. 1. Find the BWmultiplexing 2. Find the BWtransmission if the multiplexing signal is modulated using AM-DSB-LC.arrow_forward
- An FM signal with 75 kHz deviation, has an input signal-to-noise ratio of 18 dB, with a modulating frequency of 15 kHz. 1) Find SNRO at demodulator o/p. 2) Find SNRO at demodulator o/p if AM is used with m=0.3. 3) Compare the performance in case 1) and 2).. Hint: for single tone AM-DSB-LC, SNR₁ = (2m²) (4)arrow_forwardFind Va and Vb using Nodal analysisarrow_forwardCalculate the nodal voltage in the circuitarrow_forward
- Calculate the mesh currents, find Ia, Ib, Ic. Apply mesh analysisarrow_forwardFind Va and Vb using Nodal analysisarrow_forward4. A battery operated sensor transmits to a receiver that is plugged in to a power outlet. The device is continuously operated. The battery is a 3.6 V coin-cell battery with a 245mAHr capacity. The application requires a bit rate of 36 Mbps and an error rate of less than 10^-3. The channel has a center frequency of 2.4 GHz, a bandwidth of 10 MHz and a noise power spectral density of 10^-14 W/Hz. The maximum distance is 36 meters and the losses in the channel attenuates the signal by 0.25 dB/meter. Your company has two families of chips that you can use. An M-ary ASK and an M-ary QAM chip. The have very different power requirements as shown in the table below. The total current for the system is the current required to achieve the desired Eb/No PLUS the current identified below: Hokies PSK Chip Set Operating Current NOT Including the required Eb/No for the application Hokies QAM Chip Set Operating Current NOT Including the required Eb/No for the application Chip ID M-ary Voltage (volts)…arrow_forward
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